新高考数学一轮复习 讲与练第2练 不等式（原卷版）

第2讲不等式的性质及其解法学校____________姓名____________班级____________一、单选题1．已知集合SKIPIF1<0，则SKIPIF1<0=（

）A．[-1，4) B．[-1，2) C．(-2，-1) D．∅2．已知二次函数SKIPIF1<0（SKIPIF1<0）的值域为SKIPIF1<0，则SKIPIF1<0的最小值为（

）A．SKIPIF1<0 B．4 C．8 D．SKIPIF1<03．若实数a，b满足SKIPIF1<0，则ab的最大值为（

）A．2 B．1 C．SKIPIF1<0 D．SKIPIF1<04．已知集合SKIPIF1<0，SKIPIF1<0，则SKIPIF1<0（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<05．已知函数SKIPIF1<0为偶函数，则不等式SKIPIF1<0的解集为（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<06．对于任意实数SKIPIF1<0，不等式SKIPIF1<0恒成立，则实数SKIPIF1<0的取值范围是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<07．函数SKIPIF1<0的最小值为（

）A．4 B．SKIPIF1<0 C．3 D．SKIPIF1<08．设SKIPIF1<0，SKIPIF1<0，若SKIPIF1<0，则SKIPIF1<0的最大值为（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<0二、多选题9．已知SKIPIF1<0，则a，b满足（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<010．已知正数a，b满足SKIPIF1<0，则下列说法一定正确的是（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<011．已知SKIPIF1<0，直线SKIPIF1<0与曲线SKIPIF1<0相切，则下列不等式成立的是（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<012．已知正数a，b满足SKIPIF1<0，则（

）A．SKIPIF1<0的最大值是SKIPIF1<0B．SKIPIF1<0的最大值是SKIPIF1<0C．SKIPIF1<0的最小值是SKIPIF1<0D．SKIPIF1<0的最小值为SKIPIF1<0三、填空题13．命题“SKIPIF1<0”为假命题，则实数a的取值范围为___________.14．已知SKIPIF1<0，SKIPIF1<0，SKIPIF1<0，则SKIPIF1<0的最小值为__．15．若SKIPIF1<0，SKIPIF1<0，SKIPIF1<0，SKIPIF1<0，则SKIPIF1<0的最小值为______．16．设SKIPIF1<0，SKIPIF1<0，SKIPIF1<0，则SKIPIF1<0的最小值为______．四、解答题17．已知函数SKIPIF1<0．(1)求函数SKIPIF1<0的值域；(2)已知SKIPIF1<0，SKIPIF1<0，且SKIPIF1<0，不等式SKIPIF1<0恒成立，求实数x的取值范围．18．已知函