计算机科学-浙江大学集成电路原理与设计Exercise19-19本习题答案7

浙江大学电气工程学院模拟与数模混合集成电路吴晓波，赵梦恋

2018-2019学年夏学期2019年6月

Tabic7.1

TypicalParameterValue

Parameter

SymbolParameterDescriptionn-Channelp-ChannelUnits

%Thresholdvoltage=0)0.7±0.15-0.7±0.15V

K'Transconductanceparameter110.0±10%50.0±10%出A/V?

(insaturation)

yBulkthresholdparameter0.40.57

XChannellengthmodulation0.04(L=1gm)0.05(L=1即)v-'

parameter0.01(L=2怯m)0.01(L=2|xm)

2同Surfacepotentialatstrong0.70.8V

inversion

7.1ThecircuitshowninFigure7.1calledafolded-currentmirrordifferentialamplifierandisuseful

forlowvaluesofpowersupply.AssumethatallW/Lvaluesofeachtransistoris100.Usingthe

parametersshownintable7.1,

a)Findthemaximuminputcommonmodevoltage.V(c(max)ardtheminimuminputcommon

modevoltage,Vic(min).Keepalltransistorsinsaturationfor:hisproblem.

b)Whatistheinputcommonmodevoltagerange,ICMR?

c)Findthesmallsignalvoltagegain,ifv//r=v；-也.

Solution:

%Z=%+4V=0.74-+0.7=1.495V

2100.2-50，一

((+07

Vj(min)=0+VDs5sat)+Vcsi50pA)=110100+\IIOIOO-

=0.1348+0953+0.7=0.9302V=vi(min)=0.9302V

b)k=v1(nwx)-vI(min)=1.495-0.9302=0.5648V

c.)A=g〃“x(%//%//%)=116.5V/V

7.2IntheopampofFig7.2,(W/L)I.8=100/0.5,Iss=lmA,andVbi=1.7V.Assumethaty=X=0.

VDD=3V.

(a)Whatis(hemaximumallowableinputCMlevel?

(b)WhatisVx?

(c)WhatisthemaximumallowableoutputswingifthegateofM?isconnectedtotheoutput?(make

sure(hatM2andM4workinsaturationregion)

(d)WhatistheacceptablerangeofVb2?

Fig7.2

解：

(a)

匕.Lmax=%+^77/1=Kl—匕;S3+^7771

=Kl-~匕"3+^7771=%—K>D3

=0.213V

^^=1.7-0.213=1.4877

(b)

解得Vx=l.984V

(c)

M2和M4均工作在饱和区，所以

%〃一小匕，

%”之匕I一%

且有力=匕一%S4

整理得％<%一(%「%)

所以△匕吹=2%，—&4=2卜一%3=14—0913=().487V

(d)

Vz<Vx+G,且％=匕一Ms』，所以

V

匕2v%+THT%s51=1984+0.7-1.016=1.668V

且匕2-=1.984-0.7=1.284V

7.3SupposethecircuitofFig7.3isdesignedwithIssequaltoImA.IIW-IDI:equalto0.5mA,and

(W/L)9.i2=100/0.5.VDD=3V.X=0.

(a)WhatCMlevelisrequiredatXandY?

(b)IfIssrequiresaniininiumvoltageof400mMchoosetheminimumdimensionsofMi-M«to

allowapcak-to-peakswingof200mVatXandalY,assumethatM-Miareofthesamesizeand

Ms-Mgareofthesamesize.

(c)Givetheexpressionoftheoverallvoltagegain.

(b)

Vx摆幅为200mV,所以Vxmax=2.084V,VXmi„=1.884V

匕汹二匕w二匕〃)；鹏=0.458V

"%3="min；V/ss=0742v

w_ss

一=95.35

~L15.7

W

-=16.51

IT,3

(C)

4=Mm(g〃//3&//g，/，5%)g〃,9(%//%J

7.4ConsidertheamplifierofFig7.4,where(W/L)M=50/0.5andIss=Ii=0.5mA.kp=0.2and

Xn=0.1.

(a)EstimatethepolesatnodesXandYbymultiplyingthesmall-signalresistanceandcapacitance

toground.AssumethatCx=Cv=0.5pF.Whatisthephasemarginforunity-gainfeedback?

(b)IfCX=0.5pEwhatisthemaximumtolerablevalueofCYthatyieldsaphasemarginfor600

forunity-gainfeedback?

解:

(a)

1

6

8px---------------7=150xl0raz//

GY(%//%)

W

g”4=、2/K-3.3x10-3

VI£

co=------------r=6.6x109rad/s

pnyvu

g,〃2=)%((?[=2.35x10.3

低频增益为：

gm2(r2//%)=31.33—29.9dB

所以增益交点对应频率为：20log4L=29.9,©=4.69x103ad/

*X