c语言-简单小程序-简单算法

1、 以下小程序都在TC2.0中运行通过，程序没来得及加注释。程序比较简单，都是一些初学c语言时写的程序，请通过运行看效果。5个字符串排序.c#include stdio.h#include stdilb.hvoid paixu(char *p5) int i,j; char *q; for(i=0;i4;i+) for(j=0;j0) q=pj; pj=pj+1; pj+1=q; main() char *p5; int i; for(i=0;i5;i+) pi=(char *)malloc(10); scanf(%s,pi); paixu(p); for(i=0;i1|take4|take-G

2、ame Begin-n);stick(21);printf(-Game Over!-n);&/猜数字游戏#include stdio.h#include stdlib.hint yuan4,shu4;yuan_fen(int num)yuan0=num/1000;yuan1=num/100%10;yuan2=num/10%10;yuan3=num%10;shu_fen(int num)shu0=num/1000;shu1=num/100%10;shu2=num/10%10;shu3=num%10;int shudui_panduan()int shu14,shudui=0,i,j,t=0,q,

3、biao=0;for(i=0;i4;i+) shu1i=-1;for(i=0;i4;i+)for(j=0;j4;j+)if(shui=yuanj)biao=0;for(q=0;qt;q+)if(shui=shu1q) biao=1;break;if(biao=0)shu1t=shui;t+;shudui+;return shudui;int weidui_panduan()int weidui=0,i;for(i=0;i9999|manin1000) goto g1;shu_fen(manin);gotoxy(23,6+dui);printf(%d,shudui_panduan();gotox

4、y(40,6+dui);printf(%d,weidui_panduan();if(weidui_panduan()!=4) dui+;goto g1;else break;gotoxy(10,7+dui);printf(yi gong cai le %d ci!,dui+1);gotoxy(10,8+dui);printf(ni xuan ze ji xu?(y/n);flushall();if(getchar()=y) goto g2;&/九宫格.c main() int a,b, c, d,i,j; int s3030 ;/* 定义一个足够大的数组*/ printf(shu ru yi

5、ge ji shu:); scanf(%d,&b); if(b%2!=0)/*输入一个数，不是偶数才执行下面的代码*/ for ( i = 0; i b; i+)/*将数组里赋初值0，以便后面的比较*/for ( j = 0; j b; j+)sij = 0;d = (b - 1) / 2;c = 0; /*下面是向数组里填数，填成魔方*/s0d = 1;for (a = 2; a = 0)if (d + 1 b - 1)c = c - 1;d = 0;elseif (sc - 1 d + 1 != 0)c = c + 1;elsec = c - 1;d = d + 1;elseif (d +

6、 1 b - 1)c = c + 1;elsec = b - 1;d = d + 1;sc d = a;/*下面输出数组*/for (i = 0; i b; i+) for (j = 0; j b; j+)printf(%dt,sij);/*这里用了t所以不要输入的数太大，不然输出对不齐*/printf(n);&/输出菱形 数组.c#include #include main() int i,j,n; char s20=; printf(nn); n=19; for(i=-n/2; i=n/2; i+) for(j=0;j=abs(i); j+)printf(%c, ); for(j=0;j=

7、n/2-abs(i);j+)printf(%c,sj); for(j=19-(n/2-abs(i); j2|inmanthisman) gotoxy(15,20);printf(Input error!Press any key to restart.);flushall();getchar();gotoxy(15,20);printf( );goto l1;this_inrets() l2:gotoxy(20,17);printf( ); gotoxy(20,17);printf(Input the number of retainer to that bank:);flushall();i

8、f(scanf(%d,&inret)!=1)goto l2;gotoxy(15,20);printf( );if(inret2|inretthisret) gotoxy(15,20);printf(Input error!Press any key to restart.);flushall();getchar();gotoxy(15,20);printf( );goto l2;that_inmans() l3:gotoxy(20,17);printf( );gotoxy(20,17);printf(Input the number of men to this bank:);flushall

9、();if(scanf(%d,&inman)!=1)goto l3;gotoxy(15,20);printf( );if(inman2|inmanthatman)gotoxy(15,20);printf(Input error!Press any key to restart.);flushall();getchar();gotoxy(15,20);printf( );goto l3;that_inrets() l4:gotoxy(20,17);printf( );gotoxy(20,17);printf(Input the number of retainer to this bank:);

10、flushall();if(scanf(%d,&inret)!=1)goto l4;gotoxy(15,20);printf( );if(inret2|inretthatret)gotoxy(15,20);printf(Input error!Press any key to restart.);flushall();getchar();gotoxy(15,20);printf( );goto l4;int this_panduan()int thisman1,thisret1,thatman1,thatret1;thisman1=thisman;thisret1=thisret;thatma

11、n1=thatman;thatret1=thatret;thisman=thisman-inman;thisret=thisret-inret;thatman=thatman+inman;thatret=thatret+inret;if(thisman!=0&thismanthisret) thisman=thisman1; thisret=thisret1; thatman=thatman1; thatret=thatret1;return 0;elseif(thatman!=0&thatmanthatret)thisman=thisman1;thisret=thisret1;thatman

12、=thatman1;thatret=thatret1;return 0;else return 1;int that_panduan()int thisman1,thisret1,thatman1,thatret1;thisman1=thisman;thisret1=thisret;thatman1=thatman;thatret1=thatret;thisman=thisman+inman;thisret=thisret+inret;thatman=thatman-inman;thatret=thatret-inret;if(thisman!=0&thismanthisret) thisma

13、n=thisman1; thisret=thisret1; thatman=thatman1; thatret=thatret1;return 0;elseif(thatman!=0&thatmanthatret)thisman=thisman1;thisret=thisret1;thatman=thatman1;thatret=thatret1;return 0;else return 1;t_printf()int i;gotoxy(12,15);printf( );gotoxy(12,15); for(i=0;ithisman;i+) printf(Man );gotoxy(12,16)

14、;printf( );gotoxy(12,16); for(i=0;ithisret;i+) printf(Retainer );gotoxy(42,15);printf( );gotoxy(42,15); for(i=0;ithatman;i+) printf(Man );gotoxy(42,16);printf( );gotoxy(42,16); for(i=0;i);if(thisman!=0) this_inmans();else inman=0;if(thisret!=0&inman!=2) this_inrets();else inret=0;if(inret+inman2)got

15、oxy(15,20);printf(Input error!Press any key to restart.);flushall();getchar();gotoxy(15,20);printf( );goto t1;if(this_panduan()!=1) gotoxy(15,20);printf( );gotoxy(15,20);printf(The man were killed.Press any key to restart.);flushall();getchar();gotoxy(15,20);printf( );j=1;break;t_printf();t2:if(this

16、man=0&thisret=0) break; gotoxy(27,14);printf(2)gotoxy(15,20);printf( );gotoxy(15,20);printf(Input error!Press any key to restart.);goto t2;if(that_panduan()!=1) gotoxy(15,20);printf( );gotoxy(15,20);printf(The man were killed.Press any key to restart.);flushall();getchar();gotoxy(15,20);printf( );j=

17、1;break;t_printf();if(j=1) goto w1;elsegotoxy(15,20);printf( );gotoxy(15,20);printf(Congratulations! Mission Completed!Any key to quit.);flushall();getchar();return 0;&字符倒置 删除.C#include char *fan(char *p)char *a,*d,b;a=p;d=p;while(*p!=0)p+;p-;for(;adataq-data) if(p-lchild=NULL) p-lchild=q;elseadd(p-

18、lchild,q);else if(p-rchild=NULL)p-rchild=q;elseadd(p-rchild,q);bianli( struct ercha *p)if(p!=NULL)bianli(p-lchild);printf(t%d,p-data);bianli(p-rchild);main()int pr_num,i=0;struct ercha *p;while(1)g1:flushall();p=(struct ercha *)malloc(LEN);if(scanf(%d,&pr_num)!=1) goto g1;if(pr_num=-1111) break;p-da

19、ta=pr_num;p-lchild=NULL;p-rchild=NULL;if(i=0) head=p;i+;continue;add(head,p);bianli(head);$二叉树.c#include stdio.h#include conio.h#include malloc.h#define LEN sizeof(struct ercha)#define NULL 0struct ercha *head;struct ercha char data; struct ercha * rch; struct ercha * lch;qianbianli(struct ercha *p)

20、 if(p!=NULL) printf(%c ,p-data); qianbianli(p-lch); qianbianli(p-rch); zhongbianli(struct ercha *p) if(p!=NULL) zhongbianli(p-lch); printf(%c ,p-data); zhongbianli(p-rch); houbianli(struct ercha *p) if(p!=NULL) houbianli(p-lch); houbianli(p-rch); printf(%c ,p-data); charu() char c,b; struct ercha *p

21、,*q;while(1) p=(struct ercha *)malloc(LEN); printf(shu ru shu ju:n); flushall(); scanf(%c,&c); p-data=c; p-rch=NULL; p-lch=NULL; if(c=0) break; if(head=NULL) head=p; else q=head; do printf(xuan ze cha ru wei zhi:n); flushall(); scanf(%c,&b); switch(b) case r: if(q-rch!=NULL) q=q-rch;printf(yi you shu ju,qing zai ci ); else q-rch=p