大学计算机VB程序设计考试题目

1、实验三第1题 四则运算题设计如下窗体，为五个命令按钮编写5段代码完成四则运算及退出程序，其中在计算除法时，如果第二个数是零，在消息框中显示信息“除数为零”。public class form1 private sub button1_click(byval sender as system.object, byval e as system.eventargs) handles button1.click dim a, b as single a = textbox1.text b = textbox2.text textbox3.text = a + b end sub private su

2、b button2_click(byval sender as system.object, byval e as system.eventargs) handles button2.click dim a, b as single a = textbox1.text b = textbox2.text textbox3.text = a - b end sub private sub button3_click(byval sender as system.object, byval e as system.eventargs) handles button3.click dim a, b

3、as single a = textbox1.text b = textbox2.text textbox3.text = a * b end sub private sub button4_click(byval sender as system.object, byval e as system.eventargs) handles button4.click dim a, b as single a = textbox1.text b = textbox2.text if b = 0 then messagebox.show(除数为零) else textbox3.text = a /

4、b end if end sub private sub button5_click(byval sender as system.object, byval e as system.eventargs) handles button5.click end end subend class第2题 一元二次方程求解输入系数后，单击“求解”按钮后，根据判别式的3种不同情况，分别显示如下的不同结果。 public class form1 private sub button1_click(byval sender as system.object, byval e as system.eventar

5、gs) handles button1.click dim a, b, c, delta as double a = textbox1.text b = textbox2.text c = textbox3.text delta = b * b - 4 * a * c if delta 0 then label5.visible = true label6.visible = true label4.text = 方程有两个不相等实根 label5.text = x1= & (-b + math.sqrt(delta) / 2 / a) label6.text = x2= & (-b - ma

6、th.sqrt(delta) / 2 / a) elseif delta = 0 then label4.text = 方程有两个相等实根 label5.visible = true label5.text = x1=x2= & (-b / 2 / a) label6.visible = false else label4.text = 方程没有实根 label5.visible = false label6.visible = false end if end sub private sub button2_click(byval sender as system.object, byval

7、 e as system.eventargs) handles button2.click end end subend class第3题 文本框中前景色和背景色的不同组合目的：单选按钮的使用（1）设计窗体如下所示窗体中包含两组单选按钮、两个框架和一个命令按钮。（2）程序功能：分别单击不同的前景色和背景色按钮，在文本框中显示颜色的改变。（3）设置控件的主要属性1）窗体的文本属性为“不同前景色背景色的组合”2）初始前景色为红色、背景色为黄色3）其它属性根据图中显示来设置（4）事件代码public class form1 private sub radiobutton1_checkedchange

8、d(byval sender as system.object, byval e as system.eventargs) handles radiobutton1.checkedchanged textbox1.forecolor = color.red end sub private sub radiobutton2_checkedchanged(byval sender as system.object, byval e as system.eventargs) handles radiobutton2.checkedchanged textbox1.forecolor = color.

9、green end sub private sub radiobutton3_checkedchanged(byval sender as system.object, byval e as system.eventargs) handles radiobutton3.checkedchanged textbox1.forecolor = color.black end sub private sub radiobutton4_checkedchanged(byval sender as system.object, byval e as system.eventargs) handles r

10、adiobutton4.checkedchanged textbox1.backcolor = color.white end sub private sub radiobutton5_checkedchanged(byval sender as system.object, byval e as system.eventargs) handles radiobutton5.checkedchanged textbox1.backcolor = color.yellow end sub private sub form1_load(byval sender as system.object,

11、byval e as system.eventargs) handles mybase.load end subend class第4题 三位整数的反序显示在窗体中添加二个文本框、二个标签和一个命令按钮，在一个文本框中输入一个三位的整数，单击命令按钮后，在另一个框中按相反顺序显示该数，例如，输入123，则在另一个文本框中显示321。 提示：本题先将每位上的数字分解出来，这要用到整除和计算余数的运算符，例如123整除100后的结果1就是百位，而123除以10的余数就是个位，至于十位，大家可以自己确定。分解后的三位数再倒序组合成新的三位整数。public class form1 private s

12、ub button1_click(byval sender as system.object, byval e as system.eventargs) handles button1.click dim a, b, c, d, y as single a = textbox1.text b = a 100 c = (a - 100 * b) 10 d = a - 100 * b - 10 * c textbox2.text = d & c & b end subend class试验五第1题 累加编写程序，计算1100之间的所有偶数之和，程序窗口界面及控件自行设计。public class

13、form1 private sub button1_click(byval sender as system.object, byval e as system.eventargs) handles button1.click dim i, sum as long for i = 2 to 100 step 2 sum += i next textbox1.text = sum end subend class第2题 使用循环求解水仙花数的问题要求：（1）参考教材上例4-3关于水仙花数的定义。（2）程序窗口界面及控件与例4-3的结果即图4-3一样。 （3）单击“开始”按钮后，在文本框中显示求出

14、的结果。public class form1 private sub button1_click(byval sender as system.object, byval e as system.eventargs) handles button1.click dim m, k1, k2, k3 as integer textbox1.clear() for m = 100 to 999 k1 = m 100 k2 = (m 10) mod 10 k3 = m mod 10 if m = k1 3 + k2 3 + k3 3 then textbox1.text += m.tostring()

15、 + = + k1.tostring() + 3+ + k2.tostring() + 3+ + k3.tostring() + 3 + vbcrlf end if next end subend class第3题 统计整数的因子编写程序，向一个文本框输入一个整数，单击“开始”按钮后，找出该数的所有因子，并统计因子的个数和总和，结果在另一个文本框中显示，共有三行，其中第一行该数的所有因子，第二行显示该数的因子个数，最后一行显示该数所有因子之和，窗体界面如下：public class form1 private sub button1_click(byval sender as system.o

16、bject, byval e as system.eventargs) handles button1.click dim a, b, c, d as long c = 0 a = textbox1.text b = 1 while b = a if a mod b = 0 then c += 1 d += b textbox2.text = 该整数的因子是： & +=cstr(b) + , + vbcrlf + 因子个数为： + c.tostring() + vbcrlf + 因子之和为： + d.tostring() end if b = b + 1 end while end suben

17、d class第4题 判断素数编写程序，判断某个整数是否是素数，在一个文本框中输入一个整数，单击命令按钮后，在另一个文本框中显示该数是否是素数，程序代码可以参考例4-10的代码，在此基础上改写。以下是输入不同整数后的两种不同的结果，窗体结构也参照下图。 public class form1 private sub button1_click(byval sender as system.object, byval e as system.eventargs) handles button1.click dim i, j as integer dim flag as boolean = true

18、 i = textbox1.text j = 2 while j 5 then k = a(i) a(i) = a(11 - i) a(11 - i) = k textbox1.text += a(11 - i).tostring + else k = a(11 - i) a(11 - i) = a(i) a(i) = k textbox1.text += a(i).tostring + end if next完整程序; public class form1 private sub button1_click(byval sender as system.object, byval e as

19、system.eventargs) handles button1.click dim a(10), k as integer for i = 1 to 10 a(i) = inputbox(请输入整数) textbox1.text += a(i).tostring + next k = 0 textbox1.text += vbcrlf + 交换后： for i = 1 to 10 if i 5 then k = a(i) a(i) = a(11 - i) a(11 - i) = k textbox1.text += a(11 - i).tostring + else k = a(11 -

20、i) a(11 - i) = a(i) a(i) = k textbox1.text += a(i).tostring + end if next textbox1.text = 交换前： + textbox1.text end sub private sub form1_load(byval sender as system.object, byval e as system.eventargs) handles mybase.load end subend class第2题 元素平均编写程序，通过使用inputbox将10个整数放入一个一维数组中，然后计算这10个整数的平均值，在文本框中显

21、示平均值和这10个数中低于平均值的数public class form1 private sub button1_click(byval sender as system.object, byval e as system.eventargs) handles button1.click dim a(10), sum, i as integer dim av as single for i = 1 to 10 a(i) = inputbox(请输入整数) sum += a(i) next av = sum / 10 for i = 1 to 10 if a(i) av then textbox

22、1.text += a(i).tostring + end if next textbox1.text = 该组数的平均值为： + av.tostring + vbcrlf + 小于平均值的数有： + textbox1.text end subend class第3题 矩阵转置编写程序，实现矩阵转置，即矩阵的行、列互换，将一个3行4列的矩阵转换为4行3列，要示在文本框中分别显示转换前后的两个矩阵。提示: str = 交换前： + vbcrlf for i = 0 to 3 for j = 0 to 2 str += a(i, j).tostring() + b(j, i) = a(i, j)

23、next str += vbcrlf next str += 交换后: + vbcrlf for i = 0 to 2 for j = 0 to 3 str += b(i, j).tostring + next str += vbcrlf next完整程序:public class form1 private sub button1_click(byval sender as system.object, byval e as system.eventargs) handles button1.click dim a(,) as integer = 1, 2, 3, 4, 4, 5, 6, 7

24、, 6, 7, 8, 9 dim i, j, b(3, 2) as integer, str as string str = 交换前： + vbcrlf for i = 0 to 2 for j = 0 to 3 str += a(i, j).tostring() + b(j, i) = a(i, j) next str += vbcrlf next str += 交换后： + vbcrlf for i = 0 to 3 for j = 0 to 2 str += b(i, j).tostring() + next str += vbcrlf next textbox1.text = str

25、end subend class试验七:第1题 完全数编写程序，找出22000之间的所有完全数。完全数是指某个整数的每个因子之和正好等于该数本身，例如： 因为6=1+2+3，28=1+2+4+7+14，所以这两个数都是完全数。要求：（1）程序窗口界面及控件自行设计。 （2）单击“开始”按钮后，在文本框中显示求出的结果。（3） 请用进度条提示.public class form1 private sub button1_click(byval sender as system.object, byval e as system.eventargs) handles button1.click d

26、im a, b, c, d, i as integer for a = 2 to 2000 c = 0 for b = 1 to a - 1 d = a mod b if d = 0 then c += b end if next if a = c then textbox1.text += a.tostring + end if progressbar1.value = a next end subend class第2题 杨辉三角形打印以下的杨辉三角形（打印10行）。11 11 2 11 3 3 11 4 6 4 11 5 10 10 5 1提示：（1）使用一个二维数组a保存这些数据（2）

27、第0列、主对角线上元素都为1（3）其它元素为其上一行元素与上一行左侧元素之和,即: a(i,j)=a(i-1,j)+a(i-1,j-1)public class form1 private sub button1_click(byval sender as system.object, byval e as system.eventargs) handles button1.click dim a(10, 10) as integer dim i, j as integer a(1, 1) = 1 for i = 2 to 10 a(i, 1) = 1 for j = 2 to i a(i,

28、j) = a(i - 1, j - 1) + a(i - 1, j) next next for i = 1 to 10 for j = 1 to i textbox1.text += a(i, j).tostring + next textbox1.text += vbcrlf next end subend class第3题 求最小值建立一个4行3列的二维数组，找出其中最小的元素所在的行和列，并在文本框中输出该值及其行、列位置。public class form1 private sub button1_click(byval sender as system.object, byval

29、e as system.eventargs) handles button1.click dim a(,) as integer = 45, 21, 13, 42, 15, 16, 37, 18, 29, 39, 51, 62 dim i, j, m, b as integer dim min as integer = 100 for i = 0 to 3 for j = 0 to 2 if a(i, j) min then min = a(i, j) m = i + 1 : b = j + 1 end if next next textbox1.text += min.tostring +

30、+ m.tostring + 行 + b.tostring + 列 end subend class试验八:第1题 计算阶乘设计如下的窗体，向第一个文本框中输入一个整数，单击“计算”按钮，在另外一个文本框中显示该整数的阶乘，要求，阶乘的计算在按钮的单击事件中完成。public class form1 private sub button1_click(byval sender as system.object, byval e as system.eventargs) handles button1.click dim a, b, c as integer a = textbox1.text

31、b = 1 for c = 1 to a step 1 b = b * c next textbox2.text = b end subend class第2题 计算阶乘设计窗体与第1题相同，向第一个文本框中输入一个整数，单击“计算”按钮，在另外一个文本框中显示该整数的阶乘，要求采用sub子过程计算阶乘，整数通过参数传递，阶乘在子过程中显示。public class form1 private sub button1_click(byval sender as system.object, byval e as system.eventargs) handles button1.click d

32、im a as integer a = textbox1.text jch(a) end sub sub jch(byval n as integer) dim i, s as integer s = 1 for i = 1 to n s = s * i next textbox2.text = s end subend class第3题 计算阶乘设计窗体与第1题相同，向第一个文本框中输入一个整数，单击“计算”按钮，在另外一个文本框中显示该整数的阶乘，要求采用fuction 函数过程，整数通过参数传递，阶乘由该过程返回。public class form1 private sub button

33、1_click(byval sender as system.object, byval e as system.eventargs) handles button1.click dim a as integer a = textbox1.text textbox2.text = jch(a) end sub function jch(byval n as integer) dim i, s as integer s = 1 for i = 1 to n s = s * i next return s end functionend class第4题 找出一维数组元素中的最大值和最小值设计窗体

34、如下图，单击“开始”按钮后，从键盘输入10个整数，输入到一维数组中，输入时采用inputbox函数，见图（2），然后找出这10个数中的最大值和最小值，并在文本框中输出，见图， public class form1 private sub button1_click(byval sender as system.object, byval e as system.eventargs) handles button1.click dim a(9), b, c, i as integer a(0) = inputbox(输入第一个数) a(1) = inputbox(输入第二个数) a(2) = i

35、nputbox(输入第三个数) a(3) = inputbox(输入第四个数) a(4) = inputbox(输入第五个数) a(5) = inputbox(输入第六个数) a(6) = inputbox(输入第七个数) a(7) = inputbox(输入第八个数) a(8) = inputbox(输入第九个数) a(9) = inputbox(输入第十个数) b = a(0) : c = a(0) for i = 0 to 9 if a(i) c then c = a(i) end if textbox1.text += a(i).tostring + next textbox1.tex

36、t = textbox1.text + vbcrlf + 最大数为： + c.tostring + vbcrlf + 最小数为： + b.tostring end sub private sub button2_click(byval sender as system.object, byval e as system.eventargs) handles button2.click end end subend class试验九:第1题 计算数列之和求a+aa+aaa+aaaa+. .+aa.a（n个），其中a为19之间的整数。 例如：当a = 1, n = 3时，求1+11+111之和；当

37、a = 5, n = 7时，求5555555555555555555555之和。public class form1 private sub button1_click(byval sender as system.object, byval e as system.eventargs) handles button1.click dim a, n, s, i, m, b as integer a = textbox1.text n = textbox2.text b = n for i = 1 to n m = a * (10 (i - 1) * b b = b - 1 s = s + m

38、next textbox3.text = s end subend class第2题 计算长方形的面积和周长设计如下的窗体，向前两个文本框中分别输入长和宽，单击“计算”，在另外一个文本框中显示长方形的面积，要求采用function 函数过程计算面积，长和宽通过参数传递。function area(byref a as integer, byref b as integer) as long dim m as long m = a * b return m end function function ccc(byref a as integer, byref b as integer) as i

39、nteger dim n as integer n = 2 * (a + b) return n end function private sub button1_click(byval sender as system.object, byval e as system.eventargs) handles button1.click dim a, b, c as integer dim s as long a = textbox1.text b = textbox2.text s = area(a, b) c = ccc(a, b) textbox3.text = s textbox4.t

40、ext = c end subend class第3题 综合题，统计各个分数段的人数设计窗体如下：编程要求：（1）单击“开始”按钮后，显示如下的消息框，向框中输入总的人数：如果输入的人数小于1，则显示下列的消息框，然后重新输入人数（2）输入人数后，接下来分别输入这些学生的分数，如果输入的分数不在0100之间，则显示下面的消息框，然后重新输入（3）输入分数时同时统计每个分数段的人数，每个分数段按下列的规定：90100：优8089：良7079：中6069：及格60分以下：不及格（4）最后按下图显示统计后的结果：（图中是输入10个分数后的结果）public class form1 private s

41、ub button1_click(byval sender as system.object, byval e as system.eventargs) handles button1.click dim str as string dim a as integer str = 请输入学生人数 a = inputbox(str) if a 1 then messagebox.show(请重新输入) end if dim s(a), i as integer for i = 1 to a str = 请输入分数 s(i) = inputbox(str) if s(i) 100 then mess

42、agebox.show(分数不对，请重新输入) end if next dim you, liang, zhong, ji, bu as integer for i = 1 to a if s(i) = 90 then you += 1 elseif s(i) = 80 then liang += 1 elseif s(i) = 70 then zhong += 1 elseif s(i) = 60 then ji += 1 else : bu += 1 end if next str = for i = 1 to a str += s(i).tostring + next textbox1.text = 分数： + vbcrlf + str + vbcrlf + 总人数 + = + a.tostring + vbcrlf + 各等级分数的人数： + vbcrlf + 优秀 + = + you.