Java上机习题解答

1、任务4：编写程序，模拟银行账户功能。要求如下：属性：账号、储户姓名、地址、存款余额、最小余额方法：存款、取款、查询根据用户操作显示储户相关信息。如存款操作后，显示储户原有余额、今日存款数额及最终存款余额；取款时，若最后余额小于最小余额，拒绝取款，并显示“至少保留余额：XXX”。import java.util.Scanner;class Bank1private String account,name,address;private double over,minover;Bank1(String account,String name,String address,double over,d

2、ouble minover)this.account=account;=name;this.address=address;this.over=over;this.minover=minover;public void deposit(double de)System.out.println(原有余额为+over+元);System.out.println(今日存款为+de+元);System.out.println(现有余额为+(over+de)+元);this.over = over+de;public void withdrawals(double wi)if(over

3、-wi) 0.0 & this.length 0.0 & this.width b & a c) return a; else if (b a & b c) return b; else return c; public int min(int a, int b, int c) if (a b & a c) return a; else if (b a & b c) return b; else return c; public int sum(int a, int b, int c) return a + b + c; public double average(int a, int b,

4、int c) return (a + b + c) / 3; public static void main(String args) Scanner in = new Scanner(System.in); main m = new main(); System.out.println(a b c); int a,b,c; a=in.nextInt(); b=in.nextInt(); c=in.nextInt(); System.out.println(max:+m.max(a,b,c); System.out.println(min:+m.min(a,b,c); System.out.p

5、rintln(sum:+m.sum(a,b,c); System.out.println(average:+m.average(a,b,c); in.close();任务1： 请求1到n的数的阶乘之和。基本流程如下面三个图所示。 package duihuakuang;import javax.swing.JFrame;import javax.swing.JOptionPane;public class test1 public static void main(String args) while (true) JFrame f = new JFrame(); / 创建一个应用程序框架窗口

6、String ip = JOptionPane.showInputDialog(f, 请输入一个数); try int a = Integer.parseInt(ip);/if(ip.equals(null)|ip.equals()break;【1】if (a 0)continue;long sum = 0;long jie = 1;for (int i = 1; i Long.MAX_VALUE | sum 0) JOptionPane.showMessageDialog(f, 这数字太大了, 消息, JOptionPane.WARNING_MESSAGE);/【2】 elseJOption

7、Pane.showMessageDialog(f, 1到 + a + 的阶乘之和是 + sum, 消息, JOptionPane.INFORMATION_MESSAGE);int haha = JOptionPane.showConfirmDialog(f, 是否还要求另一个数的阶乘？, 选择一个选项,JOptionPane.YES_NO_CANCEL_OPTION);/ showConfirmDialog方法根据用户的不同选择，返回不同的整型常量值，具体情况如下：/ YES_OPTION：选择YES 时从类方法返回的值(0)；/ NO_OPTION：选择NO时的返回值(1)；/ CANCEL_OPTION：选择CANCEL时的返回值(2)；/ CLOSED_OPTION：用户没有做出任何选择而关闭了窗口时方法的返回值(-1)。if (haha = JOptionPane.NO_OPTION | haha = JOptionPane.CANCEL_OPTION| haha = JOptionPane.CLOSED_OPTION) / 当选择否和取消就跳出循环break; catch (NumberFormatException e) break