




文档简介
2001) 17:1041132001 Li . N. . to is to is a be a to of a of is a 32-1 of in A by to be to in it is to in . N. . 0332E 18. 8, a of is of on on 911. as 12, 13 to as a to at by of is on it D 14 by a of is it is As a be by be by of 15. a of in is by at 16to to of on 17. et 18an of In a of a Li 9 20 05by at 21 2. a on a on a to to to by A is to a of is as a of on is a 32-1 a in is to to to be or of is in is 1). at be as )j = x,y,z) in of xi,yi,1. A zi,at j = x,y,z) xi,j = x,j,z) of at a is 23. to of a be to of a an 23, p. 93:9(16*)2(2)1 - - s to a i(= 23, p. 217: - )3 - of be a q. (2). *)29(4)E* - )In to 000 N, 2of to . is to of . Li . N. by in in is by as a as to is 17 is to by , g, 2)to be in of 2of as (+ (+ () (6)ii 2of a on to , )C= .C= .nL+i= iaL+i, bL+i, gL+by at g, i = 1,2,. . .,C)to is to be by at at is is of on of to i = 1,. . .,L), X, of in g,2. in be 3). to be )by 2of be 11)to in g, by of 15, 23. to is in by at of is U* - W*) =12i=1(L+(L+(0)= 3. of 07* of W* by Q = z is ( 1, l = zof q. (10) is to is at s (+() #A of be is 19: 1)is by in 0 (12) 0of in is be by i:0(i = 1, . . ., L + C) (13)it is at a of is i# i = 1, . . .,L+C) (14)at f =5)(11)(14)q. (15) by 24. of as a In of is as 2of is as a of a of is As a to a 2of a 2to be or to e, an on To a e,at of it is a “to 2of as of e. q. (15) 16)e, (11)(14)to of an is to By e as 2of is of K, on d is 25:K =7) I in be a to of an to be a a of be A to a m) of m of 1.,At . Li . N. 4. in )(18)g, of , 2, 3 (+(+()on at At by at be in at on to 4 is to (i = 1, . . .,m)(j = x,y,z,r)(19)of k = 1,. . .,C)is at to be of is at a as q. (20):k
温馨提示
- 1. 本站所有资源如无特殊说明,都需要本地电脑安装OFFICE2007和PDF阅读器。图纸软件为CAD,CAXA,PROE,UG,SolidWorks等.压缩文件请下载最新的WinRAR软件解压。
- 2. 本站的文档不包含任何第三方提供的附件图纸等,如果需要附件,请联系上传者。文件的所有权益归上传用户所有。
- 3. 本站RAR压缩包中若带图纸,网页内容里面会有图纸预览,若没有图纸预览就没有图纸。
- 4. 未经权益所有人同意不得将文件中的内容挪作商业或盈利用途。
- 5. 人人文库网仅提供信息存储空间,仅对用户上传内容的表现方式做保护处理,对用户上传分享的文档内容本身不做任何修改或编辑,并不能对任何下载内容负责。
- 6. 下载文件中如有侵权或不适当内容,请与我们联系,我们立即纠正。
- 7. 本站不保证下载资源的准确性、安全性和完整性, 同时也不承担用户因使用这些下载资源对自己和他人造成任何形式的伤害或损失。
最新文档
- 初中数学九年级下册统编教案 8.1中学生的视力情况调查2
- AI大模型智算运营运维服务建设方案
- 哮喘诊断新定义
- 内蒙古自治区锡林郭勒盟三县联考2024-2025学年八年级下学期6月月考道德与法治试卷(含答案)
- 洗胃及胃排空试题及答案
- 河南省青桐鸣2024-2025学年高一下学期5月大联考英语试卷(不含音频) - 原卷
- 2025年甘肃省定西市安定区城区联考三模数学试题(含部分答案)
- 2025短视频平台委托开发合同
- 2025国际石油勘探合同标准格式的争议解决条款研究
- 加强家电公司品牌建设与市场营销
- DB32/T 4622.4-2023采供血过程风险管理第4部分:血液成分制备和供应风险控制规范
- 技术员奖励协议书
- 北京市先农坛体育运动技术学校招聘笔试真题2024
- 2025年供应链管理专业考试试题及答案
- 2025山东能源集团营销贸易限公司招聘机关部分业务人员31人易考易错模拟试题(共500题)试卷后附参考答案
- 2024年漳州市招聘中小学幼儿园教师真题
- 2025年道德与法治课程考试试卷及答案
- 天津2025年中国医学科学院放射医学研究所第一批招聘笔试历年参考题库附带答案详解
- 《小米印度发展路线》课件
- 互联网公司网络安全工程师入职培训
- 2025年中南出版传媒集团湖南教育出版社分公司招聘笔试参考题库含答案解析
评论
0/150
提交评论