2013年计算机等级考试三级PC技术上机20.doc

2013年计算机等级考试三级pc技术上机（20）请编制程序，其功能是：有一抄表系统采集的数据中包括8位的窃水状态字节(一个字节记录4块水表状态)，格式为：d7 d6 d5 d4 d3 d2 d1 d0s4 s3 s2 s1 x4 x3 x2 x1其中si，xi(i=1,2,3,4)分别表示第i块水表短路和断路状态位，1表示有短路或断路情况发生(表示有偷水情况)，现共采集了5个字节的窃水状态，如果有窃水情况，则记录在result中，记录格式为：表号，状态，表号，状态没有短断路，则记录e0h，断路记录e1h，短路记录e2h，如01h,e1h,02h,e0h,03h,e2h,04h,e0h表示第一块表断路，第二块表无窃水状态，第三块表短路，第四块表也无窃水发生。例如：内存中有： 83h结果为： 01h,e1h,02h,e1h,03h,e0h,04h,e2h该内存中从source开始有一字符串，其以00h结束，长度不超过100。试编程对其进行压缩，结果存入result开始的内存单元。部分程序已给出, 其中原始数据由过程load从文件input1.dat中读入source开始的内存单元中。运算结果要求从result开始存放,由过程save保存到文件output1.dat中。填空begin和end之间已给出的一段源程序使其完整(空白已用横线标出,每行空白一般只需一条指令, 但采用功能相当的多条指令亦可),或删除begin和end之间原有的代码并自行编程来完成要求的功能。对程序必须进行汇编,并与io.obj链接产生prog1.exe执行文件,最终运行程序产生结果(无结果或结果不正确者均不得分)。调试中若发现整个程序中存在错误之处, 请加以修改。试题程序：extrn load:far,save:farn equ 5esc_code equ 27stac segment stackdb 128 dup(?)stac endsdata segmentsource db n dup(?)result db n*8 dup(0)name0 db input1.dat,0name1 db output1.dat,0data endscode segmentassume cs:code,ds:data,ss:stacstart proc farpush dsxor ax,axpush axmov ax,datamov ds,axmov es,ax ;置附加段寄存器lea dx,source ;数据区起始地址lea si,name0 ;原始数据文件名mov cx,n ;字节数call load ;从input1.dat中读取数据;*begin*lea si,sourcemov di,offset resultmov dh,nlpm: mov al,simov bl,alinc simov cl,_shr bl,clmov cx,4mov bh,0lp0: shr al,1 ;bh放水表号inc bhmov di,bh_jc lp1shr bl,1jc lp2mov dl,0e0hjmp lpcomlplp: loop _jmp ret1lp1: shr bl,1mov dl,_jmp lpcomlp2: mov dl,0e2hlpcom: mov di,dl_jmp lplpret1: dec dh_ lpm;*end*lea dx,result ;结果数据区首址lea si,name1 ;结果文件名mov cx,n*2 ;字节数call save ;保存结果到文件retstart endpcode 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