《c语言题库答案》word版.docx

第三章1：判断是否为闰年#include stdio.hvoid main()int year;printf(请输入一个年份：);scanf_s(%d, &year);if (year % 4 = 0) & (year % 100 != 0) | (year % 400 = 0)printf(%d是闰年！n, year);elseprintf(%d不是闰年！n, year);2:输入a，b，c三个数，再按照由小到大的顺序输出/打擂#include stdio.hvoid main()int a, b, c, temp;printf(请任意输入三个整数：);scanf_s(%d%d%d,&a,&b,&c);/注意if并列出现if (a b)temp = a;a = b;b = temp;if (a c)temp = a;a = c;c = temp;if (b c)temp = b;b = c;c = temp;printf(a、b、c三个数按照由小到大的顺序排列之为%d、%d、%dn,a,b,c);3：输出100-999之间的水仙花数。#include stdio.hvoid main()int num, a, b, c;for (num = 100; num = 999; num+)/下面为数字各位数字的提取a = num / 100;b = num / 10 % 10;c = num % 10;if (a*a*a + b*b*b + c*c*c = num)/判断条件printf(%-5d, num);printf(n);4输出101-1000之间的质数。#include stdio.hvoid main()int num, n, i = 0;printf(101到1000以内的质数有：n);for (num = 101; num = 1000; num+)/双重循环，外层为被除数，内层为除数n = 2;while (num%n != 0)n+;if (n = num)/内层if嵌套是为了达到题目要求的每行8个数printf(%-5d, num);i+;if (i % 8 = 0)printf(n);printf(n共有%d个！, i);?5：运输公司运费问题。#include stdio.hvoid main()int s;float d,p,w,f;printf(请输入每吨货物的基本运费p，货物重w和距离s：);scanf_s(%f%f%d,&p,&w,&s);switch (int)(s/250)/强制转化类型，也可以不用，因为/本来就是取整case 0:d = 0;break;case 1:d = 0.02;break;case 2:case 3:case 4:case 5:case 6:case 7:d = 0.08;break;case 8:case 9:case 10:case 11:d=0.1;break;default:d=0.15;break;f=p*w*s*(1-d);printf(总运费为:%5.2f,f);6：分段函数#include stdio.hvoid main()float x, f;printf(请输入x:);scanf_s(%f,&x);if (x = 5)f = 10 * x - 10;else/(x = -5 & x 5)f = 5*x*x+5;printf(f=%fn,f);7：100-1000中17的倍数#include stdio.hvoid main()int num, i = 0;for (num = 100; num = 1000; num+)if (num % 17 = 0)printf(%5d, num);i+;if (i % 5 = 0)/每行5个printf(n);printf(n);8：2/1+3/2+5/3+前20项的和。 #include stdio.hvoid main()int i;double sum=0.0,m=1.0,n=2.0,temp;for (i = 0; i = a&words = A&words =0&words =9)nums+;elseothers+;printf(您输入的字符串中有%d个字母，有%d个数字，其他字符有%d个！n,letters,nums,others);10：2到20之间偶数的阶乘的和。#include stdio.hvoid main()int i, j,sum=0,num;for (i = 2; i = 1; j-)/此处还可以将其写成逆序形式for(j=1;j=i;j+)num*=j;sum += num;printf(2!+4!+6!+8!+10!+12!+14!+16!+18!+20!=%dn,sum);第四章1：10个整数冒泡法排序。#include#define n 10void main()int i,j,c,numn;printf(输入%d个整数n,n);for(i=0;in;i+)scanf(%d,&numi);for(i=0;in;i+)for(j=0;jnumj+1)c=numj+1;numj+1=numj;numj=c;for(i=0;in;i+)printf(%d ,numi);printf(n);?2：数组的倒置。注意此题未达到题目要求正确的请看考试题4.2（VS2012）#include stdio.hvoid main()int num34, i, j;printf(请依次输入这个三行四列的数组中的数：);for (i = 0; i 3; i+)for (j = 0; j 4; j+)scanf_s(%d, &numij);printf(a=n);for (i = 0; i 3; i+)for (j = 0; j 4; j+)printf(%dt, numij);printf(n);printf(nb=n);for (j = 0; j 4; j+)for (i = 0; i 3; i+)printf(%dt, numij);printf(n);printf(n);3：找出输入的10个串中最大的串#include stdio.h#include string.h#define N 10#define SIZE 20void main()char cNSIZE, maxSIZE;int i;printf(请任意输入%d个字符串：n, N);for (i = 0; i N; i+)gets(ci);strcpy(max, c0);for (i = 0; i N; i+)if (strcmp(max, ci) 0)/strcmp（1，2）函数有返回值，12返回1；1=2返回0；12返回-1strcpy(max, ci);printf(最大的字符串为%sn:, max);4：判断字符串是否为回文串#include stdio.h#define N 20void main() char cN; int i, j,n,temp=1; printf(请输入一个字符串：); scanf(%s,&c); for (i = 0; i N; i+) if (ci = 0) n = i; /strlen函数可实现 for (i = 0,j = n - 1; i n,ij;j-, i+) if (ci != cj) temp = 0; break; if (temp = 0) printf(%s没有构成回文串！n,c); else printf(%s构成了回文串！n,c); 5：三维数组#includestdio.hvoid main()int a223 = 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12 , i, j, t;for (t = 0; t2; t+)/控制面for (i = 0; i2; i+)/控制行for (j = 0; j3; j+)/控制列printf(a%d%d%d=%dt, t, i, j, atij);printf(n);#6：将十个数排序（插入排序）#includevoid main() inta10,i,j,t; printf(Pleaseinput10numbers:);for(i=0;i10;i+)scanf(%d,&ai);for(i=1;i=0&taj;j-)/*在有序序列（下标0i-1）中寻找插入位置*/aj+1=aj;/*若未找到插入位置，则当前元素后移一个位置*/aj+1=t;/*插入位置，完成插入*/printf(Thesortednumbers:);for(i=0;i10;i+)printf(%d,ai);printf(n);#7:折半查找某个数#include#define N 10void main()int aN, m, i, j, index, midindex = -1;int low, high, mid, temp;printf(请输入10个数:);for (i = 0; i = N - 1; i+)scanf(%d, &ai);printf(n请输入要查找的数:);scanf(%d, &m);for (i = 0; i N - 1; i+)index = i;for (j = i; j = N - 1; j+)if (aj aindex)index = j;temp = ai;ai = aindex;aindex = temp;/此处在将输入的数排序low = 0;high = N - 1;while (low amid)low = mid + 1;else if (m amid)high = mid - 1;elsemidindex = mid;break;if (midindex != -1)printf(nfound!);elseprintf(nnot found!);?8:依次提取字符串中的数字#includeint degital(char *a, int b);void main()char a51;int b100, i, j;printf(输入字符串n);gets(a);i = degital(a, b);printf(提取的数字有：n);for (j = 0; j= 0&*a = 9)bi+ = *a - 0;return i;9：系统登录界面#include#includevoid main()char mima13;int time;printf(请输入登录密码(密码不超过12位字符串)：n);for (time = 3; time0; time-)gets(mima);if (strcmp(mima, admin) = 0)printf(登录成功！n);break;elseif (time1)printf(密码错误！n);printf(请输入登录密码(密码不超过12位字符串)：n);if (time1)printf(n sorry!n);10：输出名字最长的#include#includeint main()/可以用无返回值的（void main）最后就不用return了char name100 = 0 , temp100 = 0 ;int i;printf(请输入10个人的姓名：n);for (i = 0; i10; i+)gets(temp);if (strlen(name) strlen(temp)strcpy(name, temp);printf(%s最长n, name);return 0;第五章#1：最小公倍数#includeint main()int a, b, c;printf(请输入两个数:n);scanf(%d%d, &a, &b);c = a*b;while (a)if (ab)int t = a; a = b; b = t;a %= b;printf(最小公倍数：%dn, c / b);return 0;2：用函数将数组转置#include#define N 4void revert(int aN)/传入了一个二维数组int i, j, t;for (i = 0; iN; i+)for (j = i; j N;j+)t = aij; aij = aji; aji = t;void main()int i, j, aNN;printf(n input 16 integer:);for (i = 0; iN; i+)for (j = 0; jN; j+)scanf(%d, &aij);printf(init data:n);for (i = 0; iN; i+)for (j = 0; jN; j+)printf(%3d, aij);putchar(n);revert(a);printf(revert data:n);for (i = 0; iN; i+)for (j = 0; jN; j+)printf(%3d, aij);putchar(n);3：输出大于平均值的数#include#define N 100int fun(int a, int b, int n)int i, c = 0;float aver1, sum = 0;for (i = 0; in; i+)sum += ai;aver1 = sum / n;for (i = 0; iaver1)bc+ = ai;return c;void main()int xN, yN, num, count;int j, n;printf(Please input the N:);scanf(%d, &num);printf(Input %d integers:n, num);for (j = 0; jnum; j+)scanf(%d, &xj);count = fun(x, y, num);printf(result is:);for (j = 0; jcount; j+)printf(%5d, yj);if (j + 1) % 5 = 0)printf(n);4：计数（有多少个三位数的各位和为5）#includeint fun(int x)/以一个整数来接收si这个整数int t = 0;int x1, x2, x3;x3 = x/100;x2 = x / 10 % 10;x1 = x % 10;if (x1 + x2 + x3 = 5)t = 1;return t;void main()int s10, i,c = 0;printf(nplease input 10 integers:);for (i = 0; i 10; i+)scanf(%d, &si);for (i = 0; i 10; i+)if (fun(si)/fun(si)已经是一个返回值，if(0)不满足条件，不执行if条件一下的语句if(非0)满足条件c+;printf(total number is:%d, c);#5：递归法求阶乘#includeint f(int i);void main()int n;printf(请输入n的值：);scanf_s(%d, &n);printf(n!的值为：%dn, f(n);int f(int i)if (i = 0 | i = 1)return 1;elsereturn i*f(i - 1);?6：将字符串的所有数字变成一个整数#includeint str2int(char *str)int i = 0, rs = 0;char c = 0;while (c = *(str + i) != 0)if (c = 0 & c = 9)rs = rs * 10 + c - 0;i+;return rs;void main()char a10;int i;printf(请输入整型数字字符串：n);gets(a);i = str2int(a);printf(转换后为:%dn, i);7：string copy 函数#includevoid strcpy(char *target, char *src)int i = 0;char c = 0;while (c = *(src + i) != 0)*(target + i) = c;i+;*(target + i) = 0;void main()char a257, b257;printf(请输入源字符串：);gets(a);strcpy(b, a);printf(源字符串：%sn, a);printf(复制后的字符串：%sn, b);8：输出文件扩展名#includeint strlen(char *filename)int i = 0;char c = 0;while (c = *(filename + i) != 0)i+;return i;/可调用strlen函数char *getFileExtName(char *filename)int len = strlen(filename);int i = len - 1, size = 0, j = 0;char *p = NULL;while (i = 0)if (*(filename + i) = .)break;i-;if (i 0)return NULL;size = len - i;p = (char *)malloc(size*sizeof(char);for (j = 0; j size; j+)*(p + j) = filenamei + j + 1;*(p + j) = 0;return p;void main()char s100, *a;printf(输入文件名n);gets(s);a = getFileExtName(s);printf(文件扩展名为：%sn, a);?9：strcmp函数#include#define N 1000int strcmp(char *str1, char *str2)int rs = 0, i = 0;while (*(str1 + i) = *(str2 + i) & *(str1 + i) != 0 & *(str2 + i) != 0)i+;if (*(str1 + i) *(str2 + i)rs = 1;else if (*(str1 + i) *(str2 + i)rs = -1;return rs;void main()int i;char aN, bN;printf(请输入第一个字符串：);gets(a);printf(请输入第二个字符串：);gets(b);i = strcmp(a, b);printf(%dn, i);#10：函数打金字塔#includevoid drawPyramid(int level)int i = 0, j = 0;for (i = 0; i level; i+)for (j = 0; j level - i - 1; j+)printf( );for (j = 0; j 2 * i + 1; j+)printf(*);printf(n);void main()int i;printf(请输入高度：);scanf(%d, &i);printf(结果为：n);drawPyramid(i);第七章1：交换两个数（指针）不能用数组#includestdio.hvoidswap(int*a,int*b)intt; t=*a; *a=*b; *b=t; voidmain()intx,y,*p1,*p2; x=10;y=20; p1=&x;p2=&y; printf(ninitdatex=%d,y=%d,x,y); x=10,y=20; swap(&x,&y); printf(nswapx=%d,y=%d,x,y);?3：每列中最小值的和#include #define N 4#define M 4int SumColumMin(int aNM, int *min)int i, j, t, k, s = 0;for (i = 0; i M; i+)k = 0;for (j = 1; j aji)k = j;printf(%dt, aki);s += aki;*min = s;return s;void main()int aNM;int i, j,sum;printf(请输入16个数字：);for (i = 0; i N;i+)for (j = 0; j M; j+)scanf(%d, &aij);SumColumMin(a, &sum);printf(%d, sum);4：统计字符串中的数字的个数#include void fun(char *a, int *t)int i = 0;doif (*a = 0)i+;a+; while (*a != 0);*t = i;void main()char str80;int c;printf(Please enter the string:);gets(str);fun(str, &c);printf(there are %d numbern, c);5:指定字符出现的次数#include int findchar(char *src, char ch)int i=0;doif (*src = ch)i+;src+; while (*src != 0);return i;void main()char len500;char ch;int i;printf(Please enter the string:);gets(len);printf(Please enter the word you want to find:);scanf(%c, &ch);i=findchar(len, ch);printf(%s of char %c %d times, len,ch,i);?6：反序#include #include #define N 10int invert(int *p)int i,j;for (i = 0; i N / 2; i+) j= pi;/从两端到中间开始倒序pi = pN-i-1;pN-i-1 = j;return 0;void main()int i, j;int aN;printf(Please enter %d integers:,N);for (i = 0; i N; i+)scanf(%d, &ai);invert(a);for (i = 0; i N; i+)printf(%d, ai);?7：反序并计数数字的个数#include #include int func(char *p1)char *p2,ch;p2 = p1;int i,j=0,h=0;doif (*p2 = 0&*p2 = 9)h+;p2+;j+;/用于字符串长度计算可用strlen代替 while (*p2 != 0);for (i = 0; i j / 2;i+)ch = p1i;p1i = p1j - 1 - i;p1j-1-i = ch; return h;void main()char a200;int i,num,j;printf(Please enter the string：);gets(a); num=func(a);j = strlen(a);for (i = 0; i j; i+)printf(%c, ai);printf(nc=%d, num);#8：字符串的插入#include #include void insert(char *s1, char *s2)int len1, len2, f = 0;char *p1, *p2;len1 = strlen(s1);len2 = strlen(s2);p1 = s1;p2 = s1 + len1 - 1;while (*p1 != 0&*p1 != *s2)p1+;if (*p1 != 0)for (; p2 p1; p2-)*(p2 + len2 - 1) = *p2;f = 1;while (*s2)*p1+ = *s2+;if (f)*(s1 + len1 + len2 - 1) = 0;else*(s1 + len1 + len2) = 0;void main()char str1100, str2100;printf(请输入一个字符串：);gets(str1);printf(请输入插入的字符串：);gets(str2);insert(str1, str2);printf(%s, str1);9：提取字符串的数字#include void main()char *p;char a256;int i;printf( Please enter the string:);gets(a);p = a;doif (0 = *p&*p 9 | *(p + 1) 0)printf(n);p+; while (*p != 0);10：strcmp函数（返回两个字符串的ASCLL码差值）#include int mystrcpy(char *p1, char *p2)int s;doif (*p1 != *p2) | (*p1 = 0&*p2 != 0) | (*p2 = 0&*p1 != 0)s = *p1 - *p2;return s;p1+;p2+; while (*p1 != 0 | *p2 != 0);return 0;void main()char len150, len250;printf(Please enter the stringa:);gets(len1);printf(Please enter the stringb:);gets(len2);mystrcpy(len1, len2);printf(The Comparing Result is:%d, mystrcpy(len1, len2);7.11将一个数列的指定段落倒序#includevoid fun(int *a,int m,int n);#define s 10void main()int a10,i,m,n;printf(输入%d个数n,s);for(i=0;is;i+)scanf(%d,&ai);printf(输入需要倒序的端点位置n);scanf(%d%d,&m,&n);fun(a,m,n);for(i=0;is;i+)printf(%d ,ai);printf(n);void fun(int *a,int m,int n)int t,i,j;i=m-1;j=n-1;/j=m-1+n-1while(ij)t=*(a+i);*(a+i)=*(a+j);*(a+j)=t;i+;j-;7.12用指针实现字符串的3个基本函数的功能#includevoid strcpy(char *target,char *src)do*target=*src;src+;target+;if(*src=0)*target=0;break;while(1);int strcmp(char *str1,char *str2)int c;doif(*str1*str2)|(*str1!=0)&(*str2=0)c=1;break;else if(*str1 %sn,a,b);elseprintf(%s %sn,a,b);第八章8.1手机通讯录100人#include#define n 100struct ppiin