C程序设计(第三版)潭浩强著课本例题程序源代码.doc

1.1输出一行信息 #include void main() printf (This is a C program.n); 1.2求两数之和 #include void main ( ) int a,b,sum; a=123; b=456; sum=a+b; printf (sum is %dn, sum); 1.3求2个数中较大者#include void main ( ) int max(int x,int y);int a, b, c; scanf (%d,%d,&a,&b); c=max (a,b); printf (max=%d,c);int max(int x,int y)int z; if (xy) z=x; else z=y; return (z); 3.1符号常量的使用#define PRICE 30#include void main ( ) int num, total; num=10; total=num * PRICE; printf(total=%dn,total); 3.5转义字符的使用#include void main ( ) printf( ab ct derftgn); printf(htibbj kn);显示结果：f_-_-_-_gde h_-_-_-j_k3.7大小写字母的转换#include void main() char c1,c2; c1=a; c2=b;c1=c1-32;c2=c2-32; printf(%c %c,c1,c2); 4.11#include void main() char c1,c2; c1=getchar(); printf(%c,%dn,c1,c1); c2=c1+32; printf(%c,%dn,c2,c2);5.4输入一个字符，判断它是否大写字母，如果是，将它转换成小写字母；如果不是，不转换，然后输出最后得到的字符#include void main ( ) char ch; scanf(%c,& ch); ch=(ch=A& ch=Z)?(ch+32):ch; printf(%cn,ch);3.8强制类型转换#include void main ( ) float x; int i; x=3.6; i=(int)x; printf(x=%f, i=%dn,x,i);运行结果：x=3.600000, i=34.1输出单个字符#include void main ( ) char a,b,c; a=B;b=O;c=Y; putchar(a);putchar(b);putchar(c); putchar (n); 结果：BOY4.3无符号数据的输出#include void main() unsigned int a=65535; int b=-2; printf(a=%d,%o,%x,%un,a,a,a,a); printf(b=%d,%o,%x,%un,b,b,b,b); 结果：a=-1,177777,ffff,65535b=-2,177776,fffe,655344.5字符串的输出#include void main ( ) printf(%3s,%7.2s,%.4s,%-5.3sn,CHINA,CHINA, CHINA, CHINA);输出入下：CHINA,_-_-_CH,CHIN,CHI_-4.6输出实数时的有效位数#include void main() float x,y; x=111111.111;y=222222.222; printf(%f,x+y);结果：333333.3281254.7输出双精度数时的有效位数#include void main() double x,y;x=1111111111111.111111111; y=2222222222222.222222222;printf(%f,x+y);结果：3333333333333.3330004.8输出实数时指定小数位数#include void main ( )float f=123.456;printf(%f %10f %10.2f %.2f %-10.2fn,f,f,f,f,f);结果：123.456001_-123.456001_-_-_-123.46_-123.46_-123.46_-_-5.1由小到大输出输入的两个实数#include void main() float a,b,t; scanf(%f,%f,&a,&b); if(ab) t=a;a=b;b=t; printf(%5.2f,%5.2fn,a,b);5.2输入3 个数，按由小到大输出#include void main ( ) float a,b,c,t; scanf(%f,%f,%f,&a,&b,&c); if(ab) t=a;a=b;b=t; if(ac) t=a;a=c;c=t; t=b;b=c;c=t; printf(%5.2f,%5.2f,%5.2fn,a,b,c); 5.3有一函数 -1 (x0)输入一个x值，输出一个y值#include void main () int x,y; scanf(%d,&x); if(x0)y=-1; else if(x=0) y=0; else y=1; printf(x=%d,y=%dn,x,y); 5.3A#include void main () int x,y; scanf(%d,&x); if (x=0)if (x0) y= 1;else y= 0; else y=-1; printf(x=%d,y=%dn,x,y); 6.1用if和goto语句构成循环，求#include void main( ) int i, sum=0;i=1;loop: if(i=100) sum=sum+i; i+; goto loop; printf(%dn,sum);6.2while语句实现#include void main() int i,sum=0; i=1; while (i=100) sum=sum+i; i+; printf(%dn,sum); 6.3用dowhile语句求。#include void main() int i,sum=0; i=1; do sum=sum+i; i+; while(i=100); printf(%dn,sum); 6.4while和do.while循环的比较 #include void main ( ) int sum=0,i; scanf(%d,&i); while (i=10) sum=sum+i; i+; printf(sum=%dn,sum); 运行情况：1 sum=55 11 sum=0 #include void main( ) int sum=0,i; scanf(%d,&i); do sum=sum+i; i+; while (i=10); printf(sum=%dn,sum);运行情况：1 sum=55 11 sum=11 6.5把100200之间不能被3整除的数输出#include void main() int n; for (n=100;n=200;n+) if (n%3=0)continue; printf(%d ,n); 求100内能被3整除的所有数的和。#include main()int x,sum;sum=0;for(x=1;x=100;x+)if(x%3=0)sum=sum+xprintf(“%dn”,sum); 6.6用 /4=1-1/3+1/5-1/7+公式求的近似值，直到某一项的绝对值小于10 为止#include #includevoid main()int s;float n,t,pi;t=1;pi=0;n=1.0;s=1;while(fabs(t)1e-6)pi=pi+t; n=n+2; s=-s; t=s/n;pi=pi*4;printf(pi=%10.6fn,pi);6.8判断m是否素数#include #include void main() int m,i,k; scanf(%d,&m);k=sqrt(m); for (i=2;ik) printf(%d is a prime numbern,m); else printf(%d is not a prime numbern,m); 6.9求100-200间的全部素数# include # include void main() int m,k,i,n=0; for(m=101;m=200;m=m+2) k=sqrt(m); for (i=2;i=k+1)printf(%d ,m);n=n+1;if(n%10=0) printf(n); printf (n);7.1数组元素的引用使a0-a9的值为0-9，然后按逆序输出#include void main() int i,a10; for (i=0; i=0; i-)printf(%d ,ai); printf(n); 结果：9 8 7 6 5 4 3 2 1 07.3用起泡法对10个数排序（由小到大）#include void main() int a10; int i,j,t; printf(input 10 numbers :n); for (i=0;i10;i+)scanf(%d,&ai); printf(n); for(j=0;j9;j+)for(i=0;iai+1) t=ai;ai=ai+1;ai+1=t; printf(the sorted numbers :n); for(i=0;i10;i+)printf(%d ,ai); printf(n);7.4将一个二维数组行和列的元素互换，存到另一个二维数组中 1 2 3 1 4a= b= 2 5 4 5 6 3 6#include void main() int a23=1,2,3,4,5,6; int b32,i,j; printf(array a:n); for (i=0;i=1;i+) for (j=0;j=2;j+) printf(%5d,aij); bji=aij; printf(n); printf(array b:n); for (i=0;i=2;i+) for(j=0;j=1;j+) printf(%5d,bij); printf(n); 7.5#include void main() int i,j,row=0,colum=0,max; int a34=1,2,3,4,9,8,7,6,-10,10,-5,2; max=a00; for (i=0;i=2;i+) for (j=0;jmax) max=aij; row=i; colum=j; printf(max=%d,row=%d,colum=%dn,max,row,colum); 8.14有一个3*4的矩阵，求所有元素中的最大值#include max_value(int array4)int i,j,max;max=array00;for(i=0;i3;i+) for(j=0;jmax)max=arrayij;return (max);main()int a34=1,3,5,7,2,4,6,8,15,17,34,12;printf(Max value is %dn,max_value(a);7.6 输出一个字符串#include void main() char c10=I, ,a,m, ,a, ,b,o,y; int i; for(i=0;i10;i+)printf(%c,ci); printf(n); 结果：I am a boy7.7输出一个菱形图#include void main() char diamond5= , ,*, ,*, ,*,*, , , ,*, ,*, ,*, , ,*; int i,j; for (i=0;i5;i+) for (j=0;j5;j+) printf(%c,diamondij); printf(n); 7.8输入一行字符，统计其中有多少个单词，单词之间用空格分隔开#include void main() char string81; int i,num=0,word=0; char c; gets(string); for (i=0;(c=stringi)!=0;i+) if(c= ) word=0; else if(word=0)word=1; num+; printf(There are %d words in the line.n,num);7.9有3个字符串，找出其中最大者#include#includevoid main ( )char string20;char str320;int i;for (i=0;i0) strcpy(string,str0);else strcpy(string,str1);if (strcmp(str2,string)0) strcpy(string,str2);printf(nthe largest string is:n%sn,string);运行：CHINA HOLLAND AMERICA结果： HOLLAND8.8用递归方法求n!#include void main() float fac(int n); int n; float y; printf(input an integer number:); scanf(%d,&n); y=fac(n); printf(%d!=%10.0fn,n,y);float fac(int n) float f; if(n0) printf(n0,dataerror!); else if(n=0,n=1) f=1; else f=fac(n-1)*n; return(f); 8.18输出1到5的阶乘值#include void main() int fac(int n);int i; for(i=1;i=5;i+) printf(%d!=%dn,i,fac(i);int fac(int n) static int f=1; f=f*n; return(f); 求7的阶乘值#include .void main() int x,t;t=1;for(x=1;x=7;x+)t=t*x;printf(%dn,t)；8.11 有一个一位数组，内放10个学生成绩，求平均成绩。#include void main()float average(float array10); float score10,aver; int i; printf(input 10 scores:n); for(i=0;i10;i+) scanf(%f,&scorei); printf(n); aver=average(score); printf(average score is %5.2fn,aver); float average(float array10) int i; float aver,sum=array0; for(i=1;i10;i+) sum=sum+arrayi; aver=sum/10; return(aver);8.15有一个一位数组，内放10个学生成绩，写一个函数，求出平均分，最高分和最低分#include float Max=0,Min=0; void main() float average(float array ,int n);float ave,score10; int i; for(i=0;i10;i+) scanf(%f,&scorei); ave=average(score,10); printf(max=%6.2fnmin=%6.2fnaverage=%6.2fn,Max,Min,ave); float average(float ar