扑克牌3张两人比大小,C语言代码.doc

扑克牌3张两人比大小，C语言代码背景：两个人每人发3张牌（各从一副牌中），每张牌包括花色（红桃(Heart)黑桃(Spade)方块(Diamond)梅花(Club）和大小（从小到大依次是：2-10、J、Q、K、A），谁手上有最大的一张或多张（如果有相同的牌）牌谁获胜。输入：A的3张牌（未排序）和B的3张牌（未排序）。（参见用例）输出：A的3张牌的排序后的输出和B的3张牌的排序后的输出，以及A和B谁获胜。（参见用例）1.DA H2 C32.H4 H3 DJ View plain1.Winner is B!2.A: H2 DA C33.B: H4 H3 DJ Unlimited 256M 0 Test Case 3 View plain1.HA CA CB2.HQ CJ CQ View plain1.Input Error! Unlimited 256M 0 Test Case 4 View plain1.HA CA CJ2.DA DK DK View plain1.Input Error! Unlimited 256M 0 Test Case 5 View plain1.SA SJ SK2.SA SJ SK View plain1.Winner is X!2.A: SA SK SJ3.B: SA SK SJ Unlimited代码#includeint asc(char p3);intisError(char p13);void compare(char p33,char p43);int main()char a33,b33,c;int i,j,resulta,resultb,result,flag=0;printf(请输入A的扑克牌，扑克牌之间以空格隔开，然后按下回车：n);for(i=0;i3;i+)for(j=0;j=1&c=9)if(c=J)c=59;if(c=Q)c=60;if(c=K)c=61;if(c=A)c=62;if(c=1)flag=1;elseprintf(Input Error!n);return 0;if(j=2)if(c!=0)printf(Input Error!n);return 0;elseflag=0;c=58;ai1=c;break;aij=c;elseif(flag=1)printf(Input Error!n);return 0;if(j=2)break;j-;printf(请输入B的扑克牌，扑克牌之间以空格隔开，然后按下回车：n);for(i=0;i3;i+)for(j=0;j=1&c=9)if(c=J)c=59;if(c=Q)c=60;if(c=K)c=61;if(c=A)c=62;if(c=1)flag=1;elseprintf(Input Error!n);return 0;if(j=2)if(c!=0)printf(Input Error!n);return 0;elseflag=0;c=58;bi1=c;break;bij=c;elseif(flag=1)printf(Input Error!n);return 0;if(j=2)break;j-;resulta=asc(a);if(resulta=0)return 0;resultb=asc(b);if(resultb=0)return 0;result=isError(a);if(result=0)return 0;result=isError(b);if(result=0)return 0;compare(a,b);for(i=0;i3;i+)ai2=0;bi2=0;printf(A: );for(i=0;i=2&ai1=2&ai1=9)printf(H);printf(%c ,ai1);elseif(ai1=58)printf(%c,ai0);printf(10 );if(ai1=59)printf(%c,ai0);printf(J );if(ai1=60)printf(%c,ai0);printf(Q );if(ai1=61)printf(%c,ai0);printf(K );if(ai1=62)printf(%c,ai0);printf(A );for(i=2;i=2&ai1=2&ai1=9)printf(H);printf(%c,ai1);elseif(ai1=58)printf(%c,ai0);printf(10);if(ai1=59)printf(%c,ai0);printf(J);if(ai1=60)printf(%c,ai0);printf(Q);if(ai1=61)printf(%c,ai0);printf(K);if(ai1=62)printf(%c,ai0);printf(A);printf(nB: );for(i=0;i=2&bi1=2&bi1=9)printf(H);printf(%c ,bi1);elseif(bi1=58)printf(%c,bi0);printf(10 );if(bi1=59)printf(%c,bi0);printf(J );if(bi1=60)printf(%c,bi0);printf(Q );if(bi1=61)printf(%c,bi0);printf(K );if(bi1=62)printf(%c,bi0);printf(A );for(i=2;i=2&bi1=2&bi1=9)printf(H);printf(%c,bi1);elseif(bi1=58)printf(%c,bi0);printf(10);if(bi1=59)printf(%c,bi0);printf(J);if(bi1=60)printf(%c,bi0);printf(Q);if(bi1=61)printf(%c,bi0);printf(K);if(bi1=62)printf(%c,bi0);printf(A);printf(n);return 0;int asc(char p3)int m,temp2;if(p01=p11)if(p00=p10)printf(Input Error!n);return 0;if(p11=p21)if(p10=p20)printf(Input Error!n);return 0;if(p01=p21)if(p00=p20)printf(Input Error!n);return 0;m=0;if(pm0pm+10)temp0=pm0;temp1=pm1;pm0=pm+10;pm1=pm+11;pm+10=temp0;pm+11=temp1;if(pm0pm+20)temp0=pm0;temp1=pm1;pm0=pm+20;pm1=pm+21;pm+20=temp0;pm+21=temp1;m=1;if(pm0pm+10)temp0=pm0;temp1=pm1;pm0=pm+10;pm1=pm+11;pm+10=temp0;pm+11=temp1;if(p00=p10)if(p01p11)temp0=p00;temp1=p01;p00=p10;p01=p11;p10=temp0;p11=temp1;if(p00=p20)if(p01p21)temp0=p00;temp1=p01;p00=p20;p01=p21;p20=temp0;p21=temp1;if(p10=p20)if(p11p21)temp0=p10;temp1=p11;p10=p20;p11=p21;p20=temp0;p21=temp1;return 1;intisError(char p13)if(p100=p110)if(p101=p111)printf(Input Error!n);return 0;if(p110=p120)if(p111=p121)printf(Input Error!n);return 0;return 1;void compa