类和对象 实验九 刘维富编写的C++程序设计书后习题.doc

实验九1、定义一个学生类CStudent,私有数据成员包括name(姓名)、id(学号)、math(数学成绩)和english(英语成绩)，私有静态数据成员包括count(学生总人数)、mathc(数学总成绩)和engishc(英语总成绩)，公有函数成员包括设置两门课的成绩、求本人总成绩和输出本人数据、输出各门课程的平均分，以及构造函数和析构函数。在主函数中定义一个学生对象数组。输入10名学生的数据，输出各门课程的平均分以及总成绩位于前20%的学生数据。#include stdafx.h#include #include #include #define N 10using namespace std;class CStudent char name10; int id; float math, english; static int count; static float mathc; static float englishc; public :CStudent(char *name=#, int id=0, float math=0, float english=0) strcpy(this-name, name);this-id = id;this-math = math;this-english = english;count +;mathc += math;englishc += english;CStudent() void setScore(float math, float english) this-math = math;this-english = english;float ScoreSum() return math + english;void OutPut() cout姓名：namet学号：idt数学成绩：matht英语成绩：englisht总成绩为：ScoreSum()endl;void AvgScore() cout数学的平均分：mathc/countendl;cout英语的平均分：englishc/countnameidab;mathc += a; englishc += b ;math = a; english = b;static void sortScore(CStudent C, int n); ;void CStudent:sortScore(CStudent C, int n) int i, j;CStudent t;for(i=0; in; i+) for(j=0; jn-i-1; j+) if(Cj.math+Cj.english Cj+1.math+Cj+1.english) t = Cj; Cj = Cj+1; Cj+1 = t; int CStudent:count;float CStudent:mathc;float CStudent:englishc;int main() CStudent CN;cout请输入N个学生的信息(姓名 学号 数学成绩 英语成绩)：n;for(int i=0; iN; i+) Ci.InPut();coutendl;cout两门课的平均分如下：n;C0. AvgScore();coutendl;CStudent:sortScore(C, N);cout按两门成绩总分降序排序后，学生排名如下：n;for(i=0; iN; i+) Ci.OutPut(); coutendl;cout按总分排序后，成绩位于前20%的学生如下：n;for(i=0; i0.2*N; i+) Ci.OutPut();return 0;2、试建立一个类CArray，将数值k插入到一个有序（升序）数据集中，并保持有序性不变。例如，原有序数据集为1，2，3，4，6，7，8，9，10，插入5后变为1，2，3，4，5，6，7，8，9，10；插入20后变为1，2，3，4，6，7，8，9，10，20。#include #include using namespace std;class CArray int k, num; int *p; public :CArray(int n, int t, int m) k = n;p = new intm;if(!p) cout内存分配失败！n; exit(-1);memcpy(p, t, (m-1)*sizeof(int);num = m;CArray() if(p) delete p;void insert() for(int i=0; i k) break;for(int j=num-1; ji; j-) pj = pj-1;pi = k;void print() for(int i=1; inum; i+) coutpi-1t;if(i % 5 = 0) coutn;int main() int n, test = 1, 2, 3, 4, 6, 7, 8, 9, 10;coutn;CArray t1(n, test, 10);t1.insert();cout插入n后，的数组为：n; t1.print();coutendl;return 0;实验十1、定义矩形类Rect，其数据成员left和right是Point类的对象，分别表示矩形的左上角坐标和右一角坐标。试为Rect类重载运算符“”,实现两个矩形对象面积大小的比较，并编写一个完整的程序，验证重载运算符的正确性。#include stdafx.h#include #include #define N 2using namespace std;class Point float x, y;public :Point(float x, float y) this-x = x;this-y = y;friend class Rect; ;class Rect Point left, right; public:Rect(float left=0, float top=0, float right=0, float bottom=0) : left(left, top), right(right, bottom)float Area() return fabs(left.x - right.x) * (left.y - right.y);void InPut(int i) cout输入第ileft.xleft.yright.xright.y;void OutPut(int j) cout第j个矩形坐标为：(left.x,left.y),(right.x,right.y)(Rect &R) return this-Area() R.Area() ? true : false;bool operator Area() R.Area() ? true : false;int main() Rect RN;for(int i=0; iN; i+) Ri.InPut(i+1);for(int j=0; jN; j+) Rj.OutPut(j+1);coutendlcoutR1) cout第2个矩形的面积，即：R0.Area()R1.Area()endl;if(R0 R1) cout第1个矩形的面积第2个矩形的面积，即：R0.Area()R1.Area()endl;return 0;2、定义字符串类String,重载=、+=、-=、=和！=运算符，并在主函数中检查重载运算符的正确性。#include stdafx.h#include #include #include using namespace std;class String char *s; int length; public:String(char *s=NULL) if(s) length = strlen(s);this-s = new charlength + 1;if(!s) couts, s); else length = 0; this-s = NULL;String() if(s) delete s;char *get() return s;String& operator =(String &t) if(t.length) char *k = new chart.length + 1;if(!k) coutlength) delete s;s = k; else if(this-length) delete s;s = NULL;this-length = t.length;return *this;String& operator +=(String &t) if(t.length) char *c = new chart.length + this-length + 1;if(!c) couts);strcat(c, t.s);if(this-length) delete this-s;this-s = c;this-length += t.length; return *this;String& operator -=(int n) if(n = 0 & n length) char *c = new charlength-n+1;if(!c) couts, length-n);*(c+length-n) = 0;delete this-s; this-s = c;this-length -= n; else if(n = this-length) if(this-length) delete this-s;this-s = NULL;this-length = 0; else coutlength) char *c = strstr(this-s, t.s);if(c) if(t.length = this-length) delete this-s;this-s = NULL;this-length = 0; else char *d = new charthis-length-t.length+1;if(!d) couts, c-s); strcpy(d+(c-s), c+t.length);delete this-s;this-s = d;this-length -= t.length;return *this;bool operator =(String &t) if(this-length & t.length) if(strcmp(this-s, t.s) return false;else return true; else if(this-length = t.length) return true; return false;bool operator !=(String &t) if(this-length & t.length) if(strcmp(t.s,this-s) return true;return false; else if(this-length = t.length) return false; return true;void print() if(this-length) couts;else cout空;int main() String s1(vb), s2(java), s3(c#), s4(c+), s5(liguohui), s6(li), s7, s8(li);couts1=; s1.print(); cout;s2=; s2.print(); s1 = s2;cout; 当s1=s2后; s1=; s1.print(); cout; s2=; s2.print();coutnns3=; s3.print(); cout; s4=; s4.print(); s3 += s4;cout; 当s3+=s4后; s3=; s3.print(); cout; s4=; s4.print();coutnns5=; s5.print(); cout; s6=; s6.print(); s5 -= s6;cout; 当