浙江大学c程2002B试卷E.doc

C ProgrammingTEST PAPERTime: 8:30-10:30 am. June 20, 2003Important note: your answers must be written on the answer sheetSection 1: Single Choice（1 mark for each item, total 10 marks）1. The precedence of operator _ is the lowest one.A0|y0) is equivalent to _.A!(x0)&!(y0)B!x0&!y0C!x0|!y0D!(x0)|!(y0)4. The value of expression _ isnt 0。A1/2B!0C!EOFDNULL5. If x is a float variable, the value of expression (x=10/4) is _ 。A2.5B2.0C3D26. If variables are defined and assigned correctly, the expression _ is wrong.Aa&bBabC&xDa, b7. According to the declaration: int a10, *p=a; the expression _ is wrong.Aa9Bp5C*p+Da+8. _ is wrong.Achar str10; str=string;Bchar str =string;Cchar *p=string;Dchar *p; p=string;9. If all variables have been defined and declared in the following program, all the variables which can be used in function fun() are _. #include void fun(int x) static int y; return; int z; void main( ) int a,b; fun(a); Ax, yBx, y, zC a,b,y,zDa,b,x,y,z10. According to the declaration: int p5, *a5; the expression _ is correct.Ap=aBp0=a C*(a+1)=p Da0=2Section 2: Fill in the blanks（2 mark for each item, total 30 marks）1. According to the declaration: int a234，the number of elements of array a is _24_.2. Writing conditional expression_（x0）?1: (x=0)? 0:-1_ to calculate the value of y. 1 x0y= 0 x=0 -1 x03. The value of expression 1105 is _1_.4. The value of expression (101)&4 is_0_.5. The value of expression sizeof(“hello”) is_6_.6. The output of the following statements is _k=10,s=25_.int k, s;for(k=1, s=0; k10; k+)if (k%2=0) continue; s += k; printf(k=%d s=%d, k, s);7. The output of the following statements is _47_. #define MM(x,y) (x*y) printf(%d, MM(2+3,15);8. The output of the following statements is _k=1 s=30_.int k=1, s=0;switch (k) case 1: s+=10; case 2: s+=20; break; default: s+=3; printf(k=%d s=%d, k, s);9. The output of the following program is _1#2#3#_.# include int f( ) static int k; return +k;void main( ) int k; for(k=0;k3;k+) printf(%d#, f( );10. The output of the following program is _5_.f (int x) if(x=1) return 1;else return f(x-1)+f(x-2);void main( ) printf(%d, f(4);11. The output of the following statements is _2, 1_.int k=1, j=2, *p, *q, *t; p=&k; q=&j;t=p; p=q; q=t;printf(%d, %d,*p, k);12. The output of the following statements is _10#30#_.int c =10, 30, 5;int *pc;for(pc=c; pcc+2; pc+)printf(%d#, *pc);13. The output of the following statements is _FOUR, P_.char *st =ONE,TWO,FOUR,K;printf(%s, %cn, *(st+2), *st+1);14. The output of the following program is _0, 4_. #include void p(int *x,int y) + *x; y=y+2;void main() int x=0, y=3; p(&y, y); printf(%d, %d, x, y); 15. Writing the declaration _ with typedef, which makes CP a synonym for a character pointer array, 10 elements. typedef char *CP10;Section 3: Read each of the following programs and answer questions (5 marks for each item, total marks: 30)1. The output of the following program is _33#366#3699#_. #include void main( ) int k, x, s, t; x=3; s=0; t=x; for(k=1; k=3; k+) t=t*10+x;s=s+t; printf(%d#, s); 2. When input: 7 3 0 3 0 3 1 2 9 7 6 0, the output is _3#-1#_. #include void main( ) int j, k, sub, x; int a5; for(j=1; j=2; j+) for(k=0; k5; k+) scanf(“%d”, &ak); scanf(“%d”, &x); sub=-1; for(k=0; k5; k+) if(ak=x) sub=k; printf(%d#, sub); 3. The output of the following program is _1#0#2#3#_. #include void main( ) long number, wt, x; x=number=10230; wt=1; while(x!=0) wt=wt*10; x=x/10;wt=wt/10; while(number!=0) printf(%d#, number/wt); number=number%wt; wt=wt/10; 4. When input: 3 9 8 6 5 3 7 1 2 4 2 1 2 3 4, the output is _a00=9#a12=7#a11=4#_.#include stdio.hvoid main( ) int flag,i,j,k,col,n,ri,a66; for(ri=1; ri=2; ri+) scanf(%d,&n); for(i=0; in; i+) for(j=0; jn; j+) scanf(%d,&aij); flag=0; for(i=0; in; i+) col=0; for(j=0; jn; j+) if (aicolaij) col=j; for (k=0; kn; k+) if(aicol=n) printf(a%d%d=%d#, i, col,aicol); flag=1; if(!flag) printf(NO#); 5. When input: how are you? , the output is _How Are You?_.#include void main( ) int word;char ch; word=0;while(ch=getchar()!=?)if(ch= ) word=0;else if(word=0)word=1;if(ch=a)ch=ch-a+A;putchar(ch);6. If the following data are stored in text file a.txtone?two?1234?output?And the following data are stored in text file b.txtone?two?1204?input?The output of the following program is _3#0#2#_.# include # include void main() int count; char ch1,ch2; FILE *f1, *f2; if (f1 = fopen(a.txt,r) = NULL)printf(Cant open file : %sn, a.txt); exit(0);if (f2 = fopen(b.txt,r) = NULL)printf(Cant open file : %sn, b.txt); exit(0); count=0;while (!feof(f1)|!feof(f2) ch1=fgetc(f1); ch2=fgetc(f2); if(ch1!=ch2) printf(%c#%c#,ch1,ch2); printf(%d#, count); break; if(ch1=?) count+; fclose(f1); fclose(f2);Section 4: According to the specification, complete each program (2 mark for each blank, total: 30 marks)1If input is n(n0), calculate the value of s = 1/1! + 1/2! + 1/3! + + 1/n!.#include void main( ) int j, k, n; float f, s;scanf(%d, &n); (1) ; for (k=1 ; k=n; k+) (2) ; for(j=1; (3) ; j+) (4) ; s=s+1.0/f; printf(sum=%f, s);(1) s=0(2) f=1(3) j0), if its a prime number, print YES, otherwise print NO. (Prime numbers: an integral number not divisible without a remainder by any integral number other than itself and one. One isnt a prime number, but two is a prime number)。#include #include void main( ) int n; int prime(int m); scanf(%d, &n); if( (5) ) printf(YESn); elseprintf(NOn);int prime(int m) int i,n; if(m=1) return 0; n=sqrt(m); for(i=2; i=n; i+) if( (6) ) return (7) ; (8) ; (5) prime(n)(6) m%i=0(7) 0(8)return 13The definition of function f2 () is equivalent to the definition of function f1 ().int f1(char s ) int k=0; while(s