简单objectToJson.doc

前些天，我同学让我帮他看一关于list转换为$.ajax的json数据的问题。 刚开始他让我看他做的我让他alert（data）结果是类的地址做成的数组。 然后我突发奇想，既然类默认调用toString的时候是打印地址，那么我可不可以重写一下toString()的那个方法，在toString()中让他返回组装的json数据，结果果然凑效。 但我不知道为什么很少人这么写，所以发表出来一是大家分享一下，二是听听大家对这种写法的意见。People.java 人实体类* 作者：zoupengfei * 时间： 2011-8-5 */package jsondemo.entity;import java.util.ArrayList;import java.util.List;public class People private String name;private int age;private String addr;private List majors=new ArrayList();public List getMajors() return majors;public void setMajors(List majors) this.majors = majors;public String getName() return name;public void setName(String name) = name;public int getAge() return age;public void setAge(int age) this.age = age;public String getAddr() return addr;public void setAddr(String addr) this.addr = addr;Overridepublic String toString() StringBuffer sb=new StringBuffer(1000);sb.append();sb.append(name:);sb.append();sb.append(,age:);sb.append(this.age);sb.append(,addr:);sb.append(this.addr);sb.append(,majors:);sb.append(this.majors);sb.append();return sb.toString();Major.java专业实体类 * 作者：zoupengfei * 时间： 2011-8-5 */package jsondemo.entity;public class Major private String name; private int level;public int getLevel() return level;public void setLevel(int level) this.level = level;public String getName() return name;public void setName(String name) = name;Overridepublic String toString() StringBuffer sb=new StringBuffer(1000);sb.append();sb.append(name:);sb.append();sb.append(,level:);sb.append(this.level);sb.append();return sb.toString();ListToJson.java servlet类 * 作者：zoupengfei * 时间： 2011-8-5 */package jsondemo.servlet;import java.io.IOException;import java.io.PrintWriter;import java.util.ArrayList;import java.util.List;import javax.servlet.ServletException;import javax.servlet.http.HttpServlet;import javax.servlet.http.HttpServletRequest;import javax.servlet.http.HttpServletResponse;import jsondemo.entity.Major;import jsondemo.entity.People;public class ListToJson extends HttpServlet public ListToJson() super();public void destroy() super.destroy(); public void doGet(HttpServletRequest request, HttpServletResponse response)throws ServletException, IOException response.setContentType(text/html);PrintWriter out = response.getWriter();this.doPost(request, response);out.flush();out.close();public void doPost(HttpServletRequest request, HttpServletResponse response)throws ServletException, IOException response.setContentType(text/html);PrintWriter out = response.getWriter();List peoples=new ArrayList();for(int i=0;i100;i+)People p=new People(); List majors=new ArrayList(); Major m=new Major(); m.setName(major1-+i); m.setLevel(1); Major m2=new Major(); m2.setName(major2-+i); m2.setLevel(2); majors.add(m); majors.add(m2); if(i%2=0) majors.add(m); majors.add(m2); p.setMajors(majors);p.setAddr(addr-+i);p.setName(name-+i);p.setAge(i);peoples.add(p); out.print(peoples);out.flush();out.close();public void init() throws ServletException web.xml This is the description of my J2EE component This is the display name of my J2EE component ListToJson jsondemo.servlet.ListToJson ListToJson /ListToJson index.jsp getjson.js 获取ajax的json数据 ;(function($)$.jsonmanage=init:function() $(#b).toggle( function () $.ajax( url:ListToJson, type:post, datatype:json, success:function(data) var d=eval(+data+); var table=$(#show); var th=$( nameageaddrmajors); table.append(th); for(var i=0;id.length;i+) var majors=di.majors; var tr=$(); var td1=$(); td1.append(); var td2=$(); td2.append(di.age); var td3=$(); td3.append(di.addr); var td4=$(); var select=$(); for(var j=0;jmajors.length;j+) var option=$(); option.val(majorsj.level); option.append(); select.append(option); td4.append(select); if(i%2=0) tr.addClass(even); else tr.addClass(odd); tr.append(td1).append(td2).append(td3).append(td4); table.append(tr); ); , function() var table=$(#show); table.empty(); ); )(jQuery);showjson.jsp 页面展示 base href= My JSP index.jsp starting page link rel=stylesheet href=/csslib/style.css /script type=t