C语言试题库答案.doc

试题库答案一、填空1、确定性、可行性、输入、输出、有穷性2、正确性、时间代价、空间代价、健壮性、可读性3、程序流程图、N-S盒图、PAD图4、正确性、鲁棒性、效率、易用性、可理解性、可测试性、可维护性、可重用性、5、机器语言、汇编语言、高级语言、超高级语言6、源程序编辑、源程序编译、连接、运行、调试第2章 C语言概述一判断题1-5 abbab6-10 aaabb第3章数据类型与数据运算一判断题1-5 bbbbb 6-8 abb二多项选择题1、(BC) 2、(AC) 3、(AD) 4、(CD) 5、(AC) 6、(CD) 7、(AD) 8、(BC)三单项选择题1-5 DBCBB 6-8 ADC四编程题1、#include void main()int a=120;printf(%d,%o,%xn,a,a,a);2、#include #include void main()float a,s,v;scanf(%f,&a);s=6*a*a;v=a*a*a;printf(s=%f,v=%fn,s,v);3、#define PI 3.14#include #include void main()float r,s,v;scanf(%f,&r);s=4*PI*r*r;v=4/3*PI*r*r*r;printf(r=%4.1f,s=%4.1f,v=%4.1fn,r,s,v);4、#include void main()int i1=65,i2=97;printf(%c,%d,%o,%xn, i1, i1, i1, i1);printf(%c,%d,%o,%xn, i2, i2, i2, i2);5、#include void main()float x;scanf(%f,&x);printf(a=%.3f,a=%.3en,x,x);第4章 常用库函数一、单选题1-5 DADDB 6-10 CDACC 11-15 CACAC 16-20 AADBC21-25 DDBDB 26-29 CBCD二、多选题1、BD 2、BCD 3、CD 4、ACD 三、填空1、261 2、1234四、程序阅读 分析下来函数段，写出其对应的执行结果。1、65，89 2、x+y+z=48 3、68 4、1095、17 6、123.46 7、100，c 8、2，8，10，16五、操作题1. 若输入：sun则输出：sun若输入:sun则输出：su2.运行结果为：a=123,b=-3721a= 123 a=123 a=123b= -3721 b=-003721 b=-3721 b= -3721a= 123,b= -3721a=123 ,b=-3721 sun, su,sun,sun123.456001,1.234560e+002,123.4561.235e+002,001.2e+00,1.23456e+0023. 运行结果：若输入：32b则输出：a=32c=b4. 运行结果：goodsun day5. 运行结果为：若输入：Good则输出：Good6. 运行结果为：helloworldworldhellowoeldgood7. 运行结果为：goodgoodwelcome8. 运行结果为：n=-1n=19. 运行结果为：good better bestabE1835510. 运行结果为：Good BetteR BesrABEgood better besrabe11. 运行结果为：good better bestabEGOOD BETTER BESTABE12. 运行结果为：若输入：a则输出：A第5章C程序设计基本结构一判断题1-5 bbbaa 6-10 abbbb 11-15 bbbab 16-20 abaab 21-25 bbaaa 26-30 bbbba 31-35 abbbb 36-40 bbbba二选择题1-5 DAADC 6-10 BCCBC 11-15 BBCCB 16-20 BACCC 21-25 CCADA26-30 AADAD 31-35 DAAAA 36-40 CCDCA 41-45 CCCCB 46-50 ABBBC三填空题1. -11 2. 2*x 3. 585858 4. 21四改错题1. #includevoid main()int a,b,c,max;scanf(%d%d%d,&a,&b,&c);if(ab)max=a;else if(maxc) max=b;else max=c;printf(max=%d,max);2.double类型和float类型转换错误。3. #include void main()int sum=0,n;n=0;while (n=100)sum+=n;n+=2;printf(1100之间所有偶数的和为：%d,sum);4. break退出时出错。五输出结果题(1). 1 (2). 4599(3)10 20 0.(4).2 1(5).-4 (6).3(7).yes(8).1(9).5 0 3(10).20,0 (11).585858(12).13(13) .C G(14).1 3 2 (15).1 (16). Passwarn (17).25 (18). maxis:21(19). 当输入c时，输出C,当输入*，无输出。(20). 1,0,0,1 (21) .(1) x=4,y=2*x-1=7 (2) x=-4,y=x=-4 (3) x=10,y=3*x-11=19(22) sum=55 (23) . 8,14,1 (24) . 1 3 5 7 (25) .k=1234六编程题1. 方法1#include stdio.hvoid main()int s,i;s=0;for(i=1;i=100;i+=3)s=s+i;printf(s=%dn,s);方法2#include stdio.hvoid main()int s,i; s=0;i=1;while(i=100)s=s+i; i+=3; printf(s=%dn,s);2.方法1#include stdio.hvoid main()int s1,s2,i;s1=s2=0; for(i=1;i=100;i+)if(i%2=1) s1=s1+i; /*奇数之和*/ else s2=s2+i; /*偶数之和*/ printf(s1=%d,s2=%dn,s1,s2);方法2#include stdio.hvoid main()int s1,s2,i;s1=s2=0; for(i=1;i=99;i+=2) s1=s1+i; /*奇数之和*/for(i=2;i=100;i+=2) s2=s2+i; /*偶数之和*/printf(s1=%d,s2=%dn,s1,s2);方法3#include stdio.hvoid main()int s1,s2,i;s1=s2=0;i=1;while(i=99)s1=s1+i; /*奇数之和*/ i+; s2=s2+i; /*偶数之和*/ i+;printf(s1=%d,s2=%dn,s1,s2);3. 方法1#include stdio.hvoid main()float p;int i,k;p=1;scanf(%d,&k);for(i=1;i=1)p=p*k; k-;printf(p=%fn,p);4.方法1#include stdio.hvoid main()float s1,s2,s;int i;s1=s2=0; for(i=1;i=101;i+=4) s1=s1+1.0/i; /*正数之和*/for(i=3;i=99;i+=4) s2=s2+1.0/i; /*负数之和*/s=s1-s2;printf(s=%fn,s);方法2#include stdio.hvoid main()int i,p;float s;s=0;p=1;for(i=1;i=101;i+=2) s=s+p*1.0/i; /*p用于控制累加项的正负*/ p=-p; /*改变正负号*/ printf(s=%fn,s);5. #include stdio.hvoid main()int i;float s;s=0;for(i=1;i=99;i+=2) s=s+1.0/i; /*不能写作1/i*/printf(s=%fn,s);6. 方法1 辗转相除法。以其中一个数作被除数，另一个数作除数，相除求余数。若余数不为0，则以上一次的除数作为新的被除数，以上一次的余数作为新的除数，继续求余数。直至余数为0时，对应的除数就是最大公约数。#include stdio.hvoid main()int m,n,r,g,h,p;scanf(%d%d,&m,&n);p=m*n;while(r=m%n)!=0) /*余数不为0时循环*/m=n; /*以上一次的除数作为新的被除数*/ n=r; /*以上一次的余数作为新的除数*/ g=n; /*余数为0时的除数即最大公约数*/h=p/g; /*两数之积除以最大公约数就是最小公倍数*/printf(g=%d,h=%dn,g,h);方法2：辗转相除法。#include stdio.hvoid main()int m,n,r,g,h,p;scanf(%d%d,&m,&n);p=m*n;while(1) /*循环条件总为真*/r=m%n； if(r=0) break; /*余数为0时终止循环*/m=n; /*以上一次的除数作为新的被除数*/ n=r; /*以上一次的余数作为新的除数*/ g=n; /*余数为0时的除数即最大公约数*/h=p/g; /*最小公倍数*/printf(g=%d,h=%dn,g,h);7. 解法1：#include stdio.hvoid main()int a,d; scanf(%d,&a); while(a!=0)d=a%10; /*求得个位*/ printf(%1d,d); /*输出宽度为1*/ a=a/10; /*去掉原来的个位*/解法2：#include stdio.hvoid main()int a,b,d; scanf(%d,&a);b=0;/*b用于存放倒置之后的数*/ while(a!=0)d=a%10; /*求得个位*/b=b*10+d; a=a/10; /*去掉原来的个位*/printf(%dn,b);8.方法1:#include stdio.hvoid main()int i,j,k;for(i=1;i=4;i+) /*输出前4行*/for(j=1;j=4-i;j+) printf( );for(k=1;k=1;i-) /*输出后3行*/for(j=1;j=4-i;j+) printf( );for(k=1;k=2*i-1;k+) printf(*);printf(n);方法2:#include stdio.hvoid main()int i,j,k;for(i=1;i=4;i+) /*输出前4行*/for(j=1;j=4-i;j+) printf( );for(k=1;k=2*i-1;k+) printf(*);printf(n); for(i=1;i=3;i+) /*输出后3行*/for(j=1;j=i;j+) printf( );for(k=1;k=a&ch=A&ch=a&ch=A&ch100|(score0) printf(n输入有误,请重新输入：); scanf(%f,&score); switch(int)(score/10) case 10: case 9: grade=A;break; case 8: grade=B;break; case 7: grade=C;break; case 6: grade=D;break; case 5: case 4: case 3: case 2: case 1: case 0: grade=E; printf(成绩是%5.1f，相应的等级是%c。n,score,grade); 说明：对输入的数据进行检查，如小于0或大于100，要求重新输入。(int)(score/10)的作用是将 (score/10) 的值进行强制类型转换，得到一个整型值。 11. #include stdio.hvoid main() long m,n,i=1,j,s; scanf(%ld,%ld,&m,&n); for(;i=m&i=n) j=m; else j=n; for(;!(j%m=0&j%n=0);j+); printf(s=%ld,j=%ldn,s,j); 12. #include stdio.hvoid main() int n,sum=0,i=1,s=2; scanf(%d,&n); while(i=n) sum=sum+s;s=s+2*pow(10,i); i+; printf(sum=%dn,sum); 13.#include stdio.hvoid main() int i,n;double h=100,s=100; scanf(%d,&n); for(i=1;i=0;i-) printf(%d ,ai);2、将if(i%5=0)改为if(i%5=0)3、将int i=0,sum;改为int i=0,sum=0;4、在for语句与while语句之间添加i=0;5、将for(j=i+1;jN-1;j+)改为for(j=i+1;jN;j+)6、将for(i=1;i=N;i+)改为for(i=1;i=N-1;i+) 7、将while(bott=top)改为while(flag=0&bott=A&si=a&si=A&si=a&si=06、 bufferk=n%10 bufferi!=bufferk-1-i7、mijmij8、l=ai0aij9、(i=j)(i=4-j)10、 int i,flag stri=getchar( ) str1i!=stri11、 j+=2 aiaj12、 0 0 xi+13、 count=0 !str2k+114、i+,j-stri=strj四、输出结果题1、8 5 2；2、0；3、1234；4、3；5、10010；6、3 5 7；7、18；8、-850，2,0 ；9、40；10、BBB；11、1,23,456；12、FGH 换行输出KL；13、EnglishGood五、编程题1、#includevoid main()int i,k;int arr10;printf(input the arrary:);for (i=0;i10;i+)scanf(%d,&arri);printf(input k:);scanf(%d,&k);for (i=0;i10;i+)if (arri=k)printf(result is %d.n,i+1);break;if (i=10)printf(Cannot found!n);2、#includevoid main()int a5=2,4,6,8,10;int b5=1,3,5,7,9;int c10;int i,j,k;i=j=k=0;while (i5 & j5)if (ai=bj)ck+=ai+;elseck+=bj+;while (i5)ck+=ai+;while (j5)ck+=bj+;printf(result array is:n);for (i=0;i10;i+)printf(%dt,ci);3、#include#include void main()int arr20;int i,j;printf(input 20 integers:n);for (i=0;i20;i+)scanf(%d,&arri);for (i=0;i20;i+)for (j=0;j20;j+)if (i!=j & arri%arrj=0)printf(%dt,arri);break;printf(n);4、#includevoid main()int arr15,arr26;int i,j;printf(input 5 nubmer:);for (i=0;i5;i+)scanf(%d,&arr1i);printf(input 6 numbers:);for (i=0;i6;i+)scanf(%d,&arr2i);for (i=0;i5;i+)for (j=0;j6;j+)if (arr1i=arr2j)printf(%dt,arr1i);break;5、#includevoid main()int arr15,arr26;int i,j,flag;printf(input 5 nubmer:);for (i=0;i5;i+)scanf(%d,&arr1i);printf(input 6 numbers:);for (i=0;i6;i+)scanf(%d,&arr2i);for (i=0;i5;i+)flag=0;for (j=0;j6;j+)if (arr1i=arr2j)flag=1;break;if (flag=0)printf(%dt,arr1i);for (i=0;i6;i+)flag=0;for (j=0;j5;j+)if (arr2i=arr1j)flag=1;break;if (flag=0)printf(%dt,arr2i);6、#includevoid main()int A44;int i,j,sum=0;printf(input the matrix:);for (i=0;i4;i+)for (j=0;j4;j+)scanf(“%d”,&Aij);for (i=0;i4;i+)sum+=Aii;printf(%5dn,sum);7、#include void main()float score105, stuave10,courseave5;int i,j;printf(“Please input the scores :”);for (i=0;i10;i+)stuavei=0; for (j=0;j5;j+)scanf(“%f”,&scoreij);stuavei+=scoreij;stuavei/=5.0;for (j=0;j5;j+)courseavej=0;for (i=0;i10;i+)courseavej+=scoreij;courseavej/=10.0;printf(“the average scores of each student are:n ”);for (i=0;i10;i+)printf(“%5.2fn”,stuavei);printf(“the average scores of each course are:n ”);for (i=0;i5;i+)printf(“%5.2fn”,courseavei);8、#includevoid main()int CountA,CountB,CountC,CountD;int i;char str80;printf(input a string:n);gets(str);CountA=CountB=CountC=CountD=i=0;while (stri!=0)if (stri=A & stri=a & stri=0 & stri=9)CountC+;elseCountD+;i+;printf(The number of upper and lower character and number and others are:n);printf(%5d%5d%5d%5dn,CountA,CountB,CountC,CountD);第7章 函数一、判断题1-5 bbbba 6-10 aabab 11-15 babbb 16-20 bbbbb二、程序填空题1. j=1y-j=j*x2. rowarowcolum3. xiixi-1j-1+xi-1j4. mijmij5. i+,j- -stri=strj(或*(str+i)=*(str+j)6. n=0|n=1f=ff(n-1)*n7. c=c*is=s+f1(i)8. i10&ai9. return 1fun2(n)10. k=sqrt(x) prime(j)11. Fibonacci(k-1)+Fibonacci(k-2)三、输出结果题1. 3 55 33 52. 53. 1 3 24. 485. 126. 3,2,2,37. The absolute value of 3 is 3.The absolute value of -4 is 4.8. hlo四、编程题1. #include #define N 10void Reverse (int A,int n)int temp;int i;for (i=0;in/2;i+)temp=Ai;Ai=An-1-i;An-1-i=temp;void main()int ArrN;int i;for (i=0;iN;i+)Arri=i;Reverse (Arr,N);for (i=0;iN;i+)printf(%5d,Arri);printf(n);2. #includeint sum_fact(int number)int sum=1;int i;for (i=2;inumber;i+)if (number%i=0)sum+=i;sum+=number;return sum;void main()printf(result is %d.n,sum_fact(6);3. #include#include int isNumber(char s1)char p80;int i=0;strcpy(p,s1);if (p09 | p09 | pib)return 1;else if (a=b)return 0;elsereturn -1;i=j=0;while (p1i!=0 & p2j!=0)if (p1i=p2j)i+;j+;elsebreak;if (p1ip2j)return -1;else if (p1i=p2j)return 0;elsereturn 1;void main()char s180,s280;while (1)printf(please input two string:n);gets(s1);gets(s2);printf(%dt%dn,isNumber(s1),strcmp(s1,s2);4. #includeint fac(int n)int result;int i;result=1;for (i=2;i=n;i+)result*=i;return result;void main()int m,n;printf(input m & n:);scanf(%d%d,&m,&n);printf(result is %d,fac(m)/fac(n)/fac(m-n);5. #include#define m 2#define n 2void com(int arrmn,int *a,int *b,int *c)int i,j;*a=*b=*c=0;for (i=0;im;i+)for (j=0;j0)(*a)+;else if (arrij=0)(*b)+;else(*c)+;void main()int arrmn,a,b,c;int i,j;printf(input the matrix:n);for (i=0;im;i+)for (j=0;jn;j+)scanf(%d,&arrij);com(arr,&a,&b,&c);printf(positive: %dn negative:%dt zero:%dn,a,b,c);6. double fun(int n)double s=0.0;int i;for(i=0; in;i+)if(i%5=0&i%11=0)s=s+i;s=sqrt(s);return s;7. long fun(int n)int i;long s=0;for(i=2;i=n-1;i+)if(n%i=0)s+=i*i;return s;8. int fun(int score,int m,int up)int i,j=0;float av=0.0;for(i=0;im;i+)av=av+scorei/m;for(i=0;iav)upj+=scorei;return j;9. void fun(int x,int pp,int *n)int i,j=0;for(i=2;i=x;i=i+2)if(x%i=0)ppj+=i;*n=j;10. void fun(int m,int k, int xx)int i,j,n;for(i=m+1,n=0;nk;i+)for(j=2;ji;j+)if(i%j=0)xxn+=i;break;11. int fun(int wN)int i,j,k=0;int s=0;for(i=0;iN;i+)for(j=0;jN;j+)if(i=0|i=N-1|j=|j=N-1)s=s+wij*wij;return s;12. void fun(int w,int p,int n)int i,j,t;for(i=p;i=0;j-)wj+1=wj;w0=t;13. float fun(int n)int i,s1=0;float s=0.0;for(i=1;i=n;i+)s1=s1+i;s=s+1.0/s1;return s;14. int fun(char str)int i,j=0;for(i=0;stri!=0;i+)if(stri!= )strj+=stri;strj=0;15. double fun(int n)int i;double s=0.0,s1=0.0;for(i=1;i=n;i+)s1=s1+pow(i,0.5);s=s+s1;return s;第8章 预处理命令一、判断题1-5 baabb 6-7 ab 第9章 指针一、判断题1-5 bbbba 6-9 bbaa 二、单项选择题1-5 BDCCD 6-10 BDDBD 11-15 BABCC 16-20 DCBAB三、程序改错题1、将p_max = a;p_min = b;改为p_max = &a;p_min = &b; 2、在两个for语句之间添加 p=a; 3、将*a+=i;改为*p+=i; 4、将int a,b,c, pmax, pmin;改为int a,b,c, *pmax, *pmin;5、将printf(“%d, %dn”,p1,p2);改为printf(“%d, %dn”,*p1,*p2);6、将p=&a;改为p=a;7、把int *p4;改为int(*p)4;四、程序填空题1、rowarowcolum2、s1i!= 0s2i!=03、*p!=0 NULL五、输出结果题1、f2、19 3、3 55 33 54、105、56、1 97、10 10 10 108、79、6六、编程题1、int StrComp(char *s1,char *s2)int i,j;while (s1i!=0 & s2j!=0 & s1i=s2j)i+;j+;return s1i-s2j;2、 #include#includevoid fun(char *s,int *a,int *b)int i;*a=*b=0;while (si!=0)if (si=A & si=a & si=z)*b+;void main()char s100;int upper=0,lower=0;printf(请输入一串字符：n);gets(s);fun(s,&upper,&lower);printf(upper=%d,lower=%d,upper,lower);3、#include void main()int X4=3,11,8,22;int product,i;int *p;p=X;product=1;for (i=0;i4;i+)product=product*(*(p+);printf(%dn,product);4、#include#define m 2#define n 2void com(int arrmn,int *a,int *b,int *c)int i,j;*a=*b=*c=0;for (i=0;im;i+)for (j=0;j0)(*a)+;else if (arrij=0)(*b)+;else(*c)+;void main()int arrmn,a,b,c;int i,j;printf(input the matrix:n);for (i=0;im;i+)for (j=0;jn;j+)scanf(%d,&arrij);com(arr,&a,&b,&c);printf(positive: %dn negative:%dt zero:%dn,a,b,c);5、#include void fun(int (*s)10, int *b, int *n,int mm,int nn) int i,j,k=0;for(i=0;imm;i+)for(j=0;jnn;j+)bk+=sij;*n=k;void main()int w1010=33,33,33,33,44,44,44,44,55,55,55,55,i,j;int a100=0,n=0;printf(The mat