JAVA猜数字游戏问题.doc

此文档收集于网络，如有侵权，请联系网站删除import java.awt.*; import javax.swing.*; import java.awt.event.*; import java.util.*;class gameFrame extends JFrame int i = 1; / 记录猜数字次数int j = 20-i; / 记录剩余的猜数字次数int n = new Random().nextInt(100);JPanel in = new JPanel(new GridLayout(1, 4); / 输入文本框所在行面板，hp,tfin,buttonArea将加入此面板 JPanel hp = new JPanel(new BorderLayout(); / 标签 help 将加入此面板;此面板将加入 in 面板 JLabel help = new JLabel(请输入0100之间的数字:); / 输入框前面的提示文本 JPanel tfin = new JPanel(new BorderLayout(); / 输入框将加入此面板，“确定”按钮将加入此面板;此面板将加入 in 面板 JTextField input = new JTextField(); / 输入框 JButton ensure = new JButton(确定); / 确定输入按钮 JPanel buttonsArea = new JPanel(new GridLayout(1, 2); / 按键区（答案，重玩），此面板将加入in 面板 JPanel re = new JPanel(new BorderLayout(); / 重玩按钮区，repeat 按钮将加入此面板 JButton repeat = new JButton(重玩); / 重玩按钮 JPanel an = new JPanel(new BorderLayout(); / answer 按钮区 JButton answer = new JButton(答案); / answer 按钮 JTextArea a = new JTextArea(); / 提示文本显示区域 JPanel p = new JPanel(new BorderLayout(); / 文本域面板 gameFrame() / 构造方法 hp.add(help, BorderLayout.CENTER); tfin.add(input, BorderLayout.CENTER); tfin.add(ensure, BorderLayout.EAST); re.add(repeat, BorderLayout.CENTER); re.add(new JLabel( ), BorderLayout.WEST); an.add(answer, BorderLayout.CENTER); an.add(new JLabel( ), BorderLayout.WEST); buttonsArea.add(re); buttonsArea.add(an); in.add(hp); in.add(tfin); in.add(buttonsArea); this.add(in, BorderLayout.NORTH); a.setEditable(false); a.setLineWrap(true); a.setWrapStyleWord(true); a.setFont(new Font(font1, Font.BOLD, 15); p.add(new JScrollPane(a); this.add(p, BorderLayout.CENTER); input.addActionListener(new MyMonitor(); ensure.addActionListener(new MyMonitor(); repeat.addActionListener(new MyMonitor2(); answer.addActionListener(new MyMonitor3(); this.addWindowListener(new MyWindowMonitor(); this.setBounds(400, 200, 550, 450); this.setResizable(false); this.setTitle(猜数字示例); this.setVisible(true); class MyWindowMonitor extends WindowAdapter / X 监听器 public void windowClosing(WindowEvent e) setVisible(true); System.exit(0); class MyMonitor2 implements ActionListener / repeat 重玩按钮监听器 public void actionPerformed(ActionEvent ex1) i = 1;a.setText(); n = new Random().nextInt(100); class MyMonitor3 implements ActionListener / answer 按钮监听器 public void actionPerformed(ActionEvent ex2) String str1 = new String(正确答案是： + n); a.append(str1+n ); class MyMonitor implements ActionListener / 确定按钮监听器 public int n1;long startTime=System.currentTimeMillis();long endTime=System.currentTimeMillis();long t=endTime-startTime;String strshow=(您总共猜了+i+次,您猜数字总共花了 +(endTime-startTime)+秒+n); public void actionPerformed(ActionEvent e) if (j = 0) a.append(还要继续，请点击“重玩”按钮！n); input.setText(); else String str = input.getText(); input.setText();a.append(str +：);try n1 = Integer.parseInt(str); catch (NumberFormatException e1) n1 = -1; if (n1=100) a.append(无效输入！请重 新输入吧！n); else if (n1 = n) a.append(猜对了！n+strshow);if(t n) if (j = 0) String s = new String(猜大了！n还要继续，请点击“重玩”按钮！n+strshow); a.append(s); i+;else String s = new String(猜大了! n你还有 + j + 次机会！n+strshow); a.append(s); i+; else if (n1 n) if (j= 0) String s = new String(猜小了！n还要继续，请点击“重玩”按钮！n+strshow); a.append(s);i+;else St