Problem G 平面上的点和线——Point类、Line类 (IV).docx

Problem G 平面上的点和线Point类、Line类 (IV)Time Limit:1 SecMemory Limit:128 MBSubmit:2620Solved:1677SubmitStatusWeb BoardDescription在数学上，平面直角坐标系上的点用X轴和Y轴上的两个坐标值唯一确定，两点确定一条线段。现在我们封装一个“Point类”和“Line类”来实现平面上的点的操作。根据“append.cc”，完成Point类和Line类的构造方法和show()方法，输出各Line对象和Point对象的构造和析构次序。接口描述：Point:show()方法：按格式输出Point对象。Line:show()方法：按格式输出Line对象。Input输入的第一行为N，表示后面有N行测试样例。每行为两组坐标“x,y”，分别表示线段起点和终点的x坐标和y坐标，两组坐标间用一个空格分开，x和y的值都在double数据范围内。Output输出为多行，每行为一条线段，起点坐标在前终点坐标在后，每个点的X坐标在前，Y坐标在后，Y坐标前面多输出一个空格，用括号包裹起来。输出格式见sample。C语言的输入输出被禁用。Sample Input40,0 1,11,1 2,32,3 4,50,1 1,0Sample OutputPoint : (1, -2) is created.Point : (2, -1) is created.Point : (0, 0) is created.Point : (0, 0)Point : (0, 0) is created.Point : (0, 0) is created.Line : (0, 0) to (0, 0) is created.Point : (0, 0) is created.Point : (0, 0) is created.Line : (0, 0) to (0, 0) is created.Point : (0, 0) is created.Point : (0, 0) is created.Line : (0, 0) to (0, 0) is created.Point : (0, 0) is created.Point : (0, 0) is created.Line : (0, 0) to (0, 0) is created.=Line : (0, 0) to (1, 1)=Line : (1, 1) to (2, 3)=Line : (2, 3) to (4, 5)=Line : (0, 1) to (1, 0)=Point : (1, -2) is copied.Point : (2, -1) is copied.Line : (1, -2) to (2, -1) is created.Point : (1, -2) is copied.Point : (0, 0) is copied.Line : (1, -2) to (0, 0) is created.Point : (2, -1) is copied.Point : (0, 0) is copied.Line : (2, -1) to (0, 0) is created.Point : (0, 0) is copied.Point : (2, -1) is copied.Line : (0, 0) to (2, -1) is created.Line : (1, -2) to (2, -1)Line : (1, -2) to (0, 0)Line : (2, -1) to (0, 0)Line : (0, 0) to (2, -1)Line : (0, 0) to (2, -1) is erased.Point : (2, -1) is erased.Point : (0, 0) is erased.Line : (2, -1) to (0, 0) is erased.Point : (0, 0) is erased.Point : (2, -1) is erased.Line : (1, -2) to (0, 0) is erased.Point : (0, 0) is erased.Point : (1, -2) is erased.Line : (1, -2) to (2, -1) is erased.Point : (2, -1) is erased.Point : (1, -2) is erased.Line : (2, 3) to (4, 5) is erased.Point : (4, 5) is erased.Point : (2, 3) is erased.Line : (1, 1) to (2, 3) is erased.Point : (2, 3) is erased.Point : (1, 1) is erased.Line : (0, 0) to (1, 1) is erased.Point : (1, 1) is erased.Point : (0, 0) is erased.Line : (0, 0) to (0, 0) is erased.Point : (0, 0) is erased.Point : (0, 0) is erased.Point : (0, 0) is erased.Point : (2, -1) is erased.Point : (1, -2) is erased.HINTAppend Code#include#includeusing namespace std;class Pointdouble ax,ay;public:friend class Line;Point(Point &a)ax=a.ax;ay=a.ay;coutPoint : (ax, ay) is copied.endl;Point(double x=0,double y=0):ax(x),ay(y)coutPoint : (ax, ay) is created.endl;/Point():ax(0),ay(0)Point()coutPoint : (ax, ay) is erased.endl;void show()coutPoint : (ax, ay)endl;class LinePoint p,q;public:Line():p(0,0),q(0,0)coutLine : (p.ax, p.ay) to (q.ax, q.ay) is created.endl;Line(Point &a,Point &b):p(a),q(b)coutLine : (p.ax, p.ay) to (q.ax, q.ay) is created.endl;Line(double x1,double y1,double x2,double y2):p(x1,y1),q(x2,y2)coutLine : (p.ax, p.ay) to (q.ax, q.ay) is created.endl;Line()coutLine : (p.ax, p.ay) to (q.ax, q.ay) is erased.endl;void SetLine(double x1, double y1, double x2, double y2)p.ax=x1;p.ay=y1;q.ax=x2;q.ay=y2;void show()coutLine : (p.ax, p.ay) to (q.ax, q.ay)num;Line linenum;for(i = 1; i