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1、姓名:_ 班级:_ 学号:_-密-封 -线- 中级网络工程 师简单单选考试卷模拟考试题考试时间:120分钟 考试总分:100分题号一二三四五总分分数遵守考场纪律,维护知识尊严,杜绝违纪行为,确保考试结果公正。1、mpls根据标记对分组进行交换,其标记中包含_。 ( )a.mac地址b.ip地址c.vlan编号d.分组长度2、icmp协议属于tcp/ip刚络中的_协议,icmp报文封装在_包中传送。( )a.数据链路层b.网络层c.传输层d.会话层3、icmp协议属于tcp/ip刚络中的_协议,icmp报文封装在_包中传送。( )a.ipb.tcpc.udpd.ppp4、ospf协议适用于4种网

2、络。下面的选项中,属于广播多址网络(broadcast multi-access)的是_,属于非广播多址网络(none broadcast multi-access)的是_。( )a.ethernetb.pppc.frame relayd.rarp5、ospf协议适用于4种网络。下面的选项中,属于广播多址网络(broadcast multi-access)的是_,属于非广播多址网络(none broadcast multi-access)的是_。( )a.ethemetb.pppc.frame relayd.rarp6、ssl协议使用的默认端口是_。 ( )a.80b.445c.8080d.4

3、437、两个公司希望通过internet传输大量敏感数据,从信息源到目的地之间的传输数据以密文形式出现,而且不希望由于在传输节点使用特殊的安全单元而增加开支,最合适的加密方式是_,使用会话密钥算法效率最高的是_。( )a.链路加密b.节点加密c.端端加密d.混合加密8、两个公司希望通过internet传输大量敏感数据,从信息源到目的地之间的传输数据以密文形式出现,而且不希望由于在传输节点使用特殊的安全单元而增加开支,最合适的加密方式是_,使用会话密钥算法效率最高的是_。( )a.rsab.rc-5c.md5d.ecc9、在域名系统中,根域下面是顶级域(tld)。在下面的选项中,_属于全世界通用

4、的顶级域。 ( )a.orgb.cnc.microsoftd.mil10、某网站向ca申请了数字证书。用户通过_来验证网站的真伪。在用户与网站进行安全通信时,用户可以通过_进行加密和验证,该网站通过_进行解密和签名。( )a.ca的签名b.证书中的公钥c.网站的私钥d.用户的公钥11、某网站向ca申请了数字证书。用户通过_来验证网站的真伪。在用户与网站进行安全通信时,用户可以通过_进行加密和验证,该网站通过_进行解密和签名。( )a.ca的签名b.证书中的公钥c.网站的私钥d.用户的公钥12、某网站向ca申请了数字证书。用户通过_来验证网站的真伪。在用户与网站进行安全通信时,用户可以通过_进行

5、加密和验证,该网站通过_进行解密和签名。( )a.ca的签名b.证书中的公钥c.网站的私钥d.用户的公钥13、第三层交换根据_对数据包进行转发。 ( )a.mac地址b.ip地址c.端口号d.应用协议14、ipv4协议头中标识符字段的作用是_。 ( )a.指明封装的上层协议b.表示松散源路由c.用于分段和重装配d.表示提供的服务类型15、在下面4种病毒中,_可以远程控制网络中的计算机。 ( )a.worm.sasser.fb.win32.cihc.trojan.qq3344d.macro.melissa16、当tcp实体要建立连接时,其段头中的_标志置1。 ( )a.synb.finc.rst

6、d.urg17、在ipv6的单播地址中有两种特殊地址,其中地址0:0:0:0:0:0:0:0表示_,地址0:0:0:0:0:0:0:1表示_。( )a.不确定地址,不能分配给任何节点b.回环地址,节点用这种地址向自身发送ipv6分组c.不确定地址,可以分配给任何地址d.回环地址,用于测试远程节点的连通性18、在ipv6的单播地址中有两种特殊地址,其中地址0:0:0:0:0:0:0:0表示_,地址0:0:0:0:0:0:0:1表示_。( )a.不确定地址,不能分配给任何节点b.回环地址,节点用这种地址向自身发送ipv6分组c.不确定地址,可以分配给任何地址d.回环地址,用于测试远程节点的连通性1

7、9、ftp命令中用来设置客户端当前工作目录的命令是_。 ( )a.getb.listc.1cdd.!list20、包过滤防火墙对通过防火墙的数据包进行检查,只有满足条件的数据包才能通过,对数据包的检查内容一般不包括_。 ( )a.源地址b.目的地址c.协议d.有效载荷21、以下关于加密算法的叙述中,正确的是_。 ( )a.des算法采用128位的密钥进行加密b.des算法采用两个不同的密钥进行加密c.三重des算法采用3个不同的密钥进行加密d.三重des算法采用两个不同的密钥进行加密22、ripv2对ripv1协议有三方面的改进。下面的选项中,ripv2的特点不包括_。在ripv2中,可以采用

8、水平分割法来消除路由循环,这种方法是指_。( )a.使用组播而不是广播来传播路由更新报文b.采用了触发更新机制来加速路由收敛c.使用经过散列的口令来限制路由信息的传播d.支持动态网络地址变换来使用私网地址23、ripv2对ripv1协议有三方面的改进。下面的选项中,ripv2的特点不包括_。在ripv2中,可以采用水平分割法来消除路由循环,这种方法是指_。( )a.不能向自己的邻居发送路由信息b.不要把一条路由信息发送给该信思的来源c.路由信息只能发送给左右两边的路由器d.路由信息必须用组播而不是广播方式发送24、为了限制路由信息传播的范围,ospf协议把网络划分成4种区域(area),其中_

9、的作用是连接各个区域的传输网络,_不接收本地自治系统之外的路由信息。( )a.不完全存根区域b.标准区域c.主干区域d.存根区域25、为了限制路由信息传播的范围,ospf协议把网络划分成4种区域(area),其中_的作用是连接各个区域的传输网络,_不接收本地自治系统之外的路由信息。( )a.不完全存根区域b.标准区域c.主干区域d.存根区域26、给定一个c类网络/24,要在其中划分出3个60台主机的网段和2个30台主机的网段,则采用的子网掩码应该分别为_。 ( )a.28和24b.28和255.

10、255.255.240c.92和24d.92和4027、ieee 802.11i所采用的加密算法为_。 ( )a.desb.3desc.idead.aes28、下面给出的网络地址中,属于私网地址的是_。 ( )a.14b.3c.8d.2429、arp表用于缓存设备的ip地址与mac地址的对应关系,采用arp表的好处是_。 ( )a.便于测试网络连接数b.减少网络维护工作量c.限制网络广播数量d.解决网

11、络地址冲突30、网络/20中可分配的主机地址数是_。 ( )a.1022b.2046c.4094d.819231、a transport layer protocol usually has several responsibilities. one is to create a process-to-processcommunication udp uses(1)numbers to accomplish this. another responsibility is to provide controlmechanisms at the transport lev

12、el, udp does this task at a very minimal level. there is no flow control mechanismand there is no(2)for received packet. udp, however, does provide error control to some extent. if udpdetects an error in the received packet, it will silently drop it.the transport layer also provides a connection mec

13、hanism for the processes. the(3)must be able to sendstreams of data to the transport layer. it is the responsibility of the transport layer at(4)station to make theconnection with the receiver chop the stream into transportable units, number them, and send them one by one. itis the responsibility of

14、 the transport layer at the receiving end to wait until all the different units belonging to thesame process have arrived, check and pass those that are(5)free, and deliver them to the receiving process asa stream.(1)是( )a.hopb.portc.routed.packet32、a transport layer protocol usually has several res

15、ponsibilities. one is to create a process-to-processcommunication udp uses(1)numbers to accomplish this. another responsibility is to provide controlmechanisms at the transport level, udp does this task at a very minimal level. there is no flow control mechanismand there is no(2)for received packet.

16、 udp, however, does provide error control to some extent. if udpdetects an error in the received packet, it will silently drop it.the transport layer also provides a connection mechanism for the processes. the(3)must be able to sendstreams of data to the transport layer. it is the responsibility of

17、the transport layer at(4)station to make theconnection with the receiver chop the stream into transportable units, number them, and send them one by one. itis the responsibility of the transport layer at the receiving end to wait until all the different units belonging to thesame process have arrive

18、d, check and pass those that are(5)free, and deliver them to the receiving process asa stream.(2)是( )a.connectionb.windowc.ackmowledgementd.destination33、a transport layer protocol usually has several responsibilities. one is to create a process-to-processcommunication udp uses(1)numbers to accompli

19、sh this. another responsibility is to provide controlmechanisms at the transport level, udp does this task at a very minimal level. there is no flow control mechanismand there is no(2)for received packet. udp, however, does provide error control to some extent. if udpdetects an error in the received

20、 packet, it will silently drop it.the transport layer also provides a connection mechanism for the processes. the(3)must be able to sendstreams of data to the transport layer. it is the responsibility of the transport layer at(4)station to make theconnection with the receiver chop the stream into tr

21、ansportable units, number them, and send them one by one. itis the responsibility of the transport layer at the receiving end to wait until all the different units belonging to thesame process have arrived, check and pass those that are(5)free, and deliver them to the receiving process asa stream.(3

22、)是( )a.jobsb.processesc.programsd.users34、a transport layer protocol usually has several responsibilities. one is to create a process-to-processcommunication udp uses(1)numbers to accomplish this. another responsibility is to provide controlmechanisms at the transport level, udp does this task at a

23、very minimal level. there is no flow control mechanismand there is no(2)for received packet. udp, however, does provide error control to some extent. if udpdetects an error in the received packet, it will silently drop it.the transport layer also provides a connection mechanism for the processes. th

24、e(3)must be able to sendstreams of data to the transport layer. it is the responsibility of the transport layer at(4)station to make theconnection with the receiver chop the stream into transportable units, number them, and send them one by one. itis the responsibility of the transport layer at the

25、receiving end to wait until all the different units belonging to thesame process have arrived, check and pass those that are(5)free, and deliver them to the receiving process asa stream.(4)是( )a.sendingb.routingc.switchingd.receiving35、a transport layer protocol usually has several responsibilities.

26、 one is to create a process-to-processcommunication udp uses(1)numbers to accomplish this. another responsibility is to provide controlmechanisms at the transport level, udp does this task at a very minimal level. there is no flow control mechanismand there is no(2)for received packet. udp, however,

27、 does provide error control to some extent. if udpdetects an error in the received packet, it will silently drop it.the transport layer also provides a connection mechanism for the processes. the(3)must be able to sendstreams of data to the transport layer. it is the responsibility of the transport

28、layer at(4)station to make theconnection with the receiver chop the stream into transportable units, number them, and send them one by one. itis the responsibility of the transport layer at the receiving end to wait until all the different units belonging to thesame process have arrived, check and p

29、ass those that are(5)free, and deliver them to the receiving process asa stream.(5)是( )a.callb.statec.costd.error36、ipv6地址33ab:0000:0000:cd30:0000:0000:0000:0000/60可以表示成各种简写形式,以下写法中,正确的是_。 ( )a.33ab:0:0:cd30:/60b.33ab:0:0:cd3/60c.33abcd30/60d.33abcd3/6037、kerberos由认证服务器(as)和票证授予服务器(tgs)两部分组成,当用户a通过k

30、erberos向服务器v请求服务时,认证过程如图6-22所示,图中处为(1),处为(2)。(1)是( )a.ktgs(asks)b.ks(vskav)c.kv(askav)d.ks(t)38、kerberos由认证服务器(as)和票证授予服务器(tgs)两部分组成,当用户a通过kerberos向服务器v请求服务时,认证过程如图6-22所示,图中处为(1),处为(2)。(2)是( )a.kav(t+1)b.ks(t+1)c.ks(t)d.kav(t)39、ipsec的加密和认证过程中所使用的密钥由_机制来生成和分发。 ( )a.espb.ikec.tgsd.ah40、自动专用ip地址(automatic private ip address,apipa)是iana(internet assignednumbers authority)保留的一个

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