634幂的运算综合专项练习50题有答案过程ok

1、骞的运算专项练习50题（有答案）22,232.(4ab)x(-&b)2 27.计算：(-2m2)3+n7+m.3.(1)：-一:3 38.计算：(2n2n3)3?(mn2)210 .(-工)2+(-2).3+2X0222211 .已知：2x=4y+1,27y=3、T,求xy的值.4.已知ax=2,ay=3求：ax+y与a2xy的值.12.若2x+5y-3=0,求4x?32y的值.5.已知3m=x,3n=y,用x,y表示33m+2n.13.已知3X9mX27n=316,求m的值.(1+2)(1+2)- -2-(T2-(T，(-j)(-j)-1-16.若a=255,b=344,的大小.c=

2、433,d=522,试比较a,b,c,(2)(3x3)2?(-x);9.计算：-1+(-2)2X5-(3)m2?7mp2+(-7mp;(4)(2a-3)(3a+1).14.若(anbmb)3=a9b15,求2m+n的值.24.已知：3”9”2781m=3求m的值.15.计算：（x2?x3）25.已知6-b?2b+111且ya1?y4b=y5,求a+b的值.16.、r4/2n、2计算：（a）+a3n+2?a2.26.若2x+3y4=0,求9x1?27y.17.m=8,an=2,2 2试求a23n的值.27.计算:(3a2x4)3-(2a3x6)2.18.已知n+1932n=72,求n的值.28.

3、计算:3a3aZ Zb*b*4 419.已知xm=3,x0=5,求x2m+n的值.29.已知16n=4X2：27n=9X3m+32010,的值.20.已知3m=6,9n=2,求2m-4n+1,/士3的值.30.已知162X43X26=22.2,(102)n=1012.求m+n的值.y)5(y-x)43.（用哥的形式表示）(-a)5?(-a3)+(-a)2.22.若xm+2=16,xn=2,(xw0),求xm+n,xm-n的值.32.(ab-1)3?(2ab2)223.计算：(5a-3b4)2?(a2b)233.已知xa+b?x2a=x9,求(-3)b+(-3)3的值.34.a4?a4+(a2)

4、4-(-3x4)242.计算：(a2b6)n+5(anb3n)2-3(ab3)2n.35.已知5m+n2m-n.3=x6y15,求nm的值.43.（巴）5口,（旦2）50、0A，具,36.已知am=2, an=7,3m+2n一a3m的值.44.计算：/5面+广-2)2+(广一2)3(-b3巧37.计算:2n+2n(-3xy)x3y)2n45.已知的值.xa=2,xb=6.(1)求xab的值.(2)求x2ab38.计算:(x2y3)T?(x2y-3)46.已知2a?27b?37c=1998,其中a,b,c为整数,39.已知a2m=2,b3n=3,求(a3m)b2n)3+a2m?b3n的值求(a-

5、b-c)1998的值.40.已知n为正整数，且x3n=7,求(3x2n)3-4(x2)3n_,1998,、199947.-(-0.25)X(4)的值.41.若n的值.为正整数,且x2n=5,求(3x3n)2-34(x2)3n48.(1)(2a+b)2n+1?(2a+b)3?(2a+b)n4(2)(x-y)2?(y-x)550.计算下列各式，并把结果化为正整数指数哥的形式.a2b3(2a1b3);49.(1)(3x2y2z1)2?(5xy23)2(a2)3(bc(2)(4x2yz1)，2xyz)4/3-2+(yz)(3)2(2ab2c3)2+(ab)2哥的运算50题参考答案:31+5m=316,

6、1+5m=1Q1.解：原式=4-1-4=-1;2.原式=16a2b4x(一_iLa6b3)=-2a8b78 83.解：(1)原式=(-5)X3=-15;(2)原式=9x6?(-x)=-9x7;33)原式=7n3p2+(7mp)=nip；(4)原式=6a2+2a-9a-3=6a2-7a-3.故答案为-15、-9x、-mp6a2-7a-34.解：ax+y=ax?ay=2x3=6;ay=a2x+ay=22+3=43 35.解：原式=33mx32n,=(3m)3x(3n)：=x3y26.解：a=(25)11=3211;b=(34)11=8111;c=(43)11=4811;d=(52)11=2511;

7、可见，bcad7.解：(2n2)3+n7+m,=(-2)3x(m2)3+n6,=-8ms+n6,6=-7m解得m=314.解：:(anbmb)3n=9,3m+3=15解得：m=4n=3,3=(a)3(bm3b33nb3m+38.解：(2m2n3)3?(mn2)2=8m6n9?m-2n4=8nin5.215.m+n=27=128解：原式=(x5)2610616.4n解:=a+a4n-3n-2,=a=an-2(a2n)2+a3n+%2?a2+x=x+x=x3n+2?a2a6=x4?a2n-2+2=an=a17.解:am=8,2m-3n=(an=,2 22+(an)3,.原式=64-1=512.8

8、8故答案为51218.解：9n+132n=9n+19n=9n(91)=9nX8,而72=9X8,当9n+132n=72时，9nx8=9X8,.9=9,n=119.解：原式=(xm)2?xn=32X5=9X59 .解：原式=(-4)+4X1=010 .解：原式=1-(1)+2X14343=-2+2=011.解：. 2x=22y+2,x=2y+2又27y=32x=4y+1,.33y=3x3y=x1=4520.解：由题意得，9n=32n=2,32m=62=36,故32什4n+1=32mx3+34n=363+4=2721.解：(xy)5(yx)43=(xy)5(xy)43=(xy)5?(xy)12=(

9、xy)1722 .解：,xm+2n=16,xn=2,.xm+2n+xn=xm+n=16-2=8,xm+2n+x3n=xn=16+23=223 .解：(5a-3b4)2?(a2b)2=25a6b8?a4b2=25a10b6联立组成方程组并求解得1y=ly=lxy=312.解：4x?32y=22x?25y=22x+5y2x+5y-3=0,即2x+5y=3,原式=23=813.解：3X9mX27m,=3X32mx33m,1+5m=3,25b25b2 2ITa a24.解：由题意知，3m?9m?27m?81m,sm？sZm?sSm?34m_0m+2m+3m+4m=3,-30=3,m+2m+3m+4m=

10、30整理，得10m=30解得m=325.解：x6b?x2b+1=x且ya1?y4b=y5,34.解：原式=a8+a89x8,=2a8-9x835.解：(x5m+n2m-na-1+4-b=5a-1+4-b=5解得:则a+b=1026.解：2x+3y-4=0,.2x+3y=4,9x1?27y=32x2?33y=32x+3y2=32=927.解:28.解:29.解:.(24).24m=2：:(3a2x4)3-(2a3x6)2=27a6x12-4a6x12=23a6x12:原式=?.a2b3=a a2 2b b4 43b3b:16m=4X22广2,)m=22X22,2n-2+2.2n2+2=4m-n=

11、2m0,(33)n27n=9X3m+：.(33)n=32x3m+：.33n=3m+：.3n=m+5D,由得：.nF2mnF2mL L3nFirr+3nFirr+5 5解得：m=1,n=2,(nm)=(2T)20102010=130.解：162X43X26=28X26X26=220=22m;(102)n=102n=1。12.2m-2=20,2n=12,解得：m=11,n=6,m+n=11+6=1731.原式=(-a)a17+a2=-a15.5?a12+(-a)2=-a512+(-a)232.解：（a、-1）3?(2ab2)=(a6b3)?(5m+n2m-n)5nH5nH口二6 62m-n=152

12、m-n=15ITF3n=n=- -9 9)3=x15m+31y6m-3n=*6丫15则nm=(-9)3=-36.解：am=2,.3m+2n2n-3n=243an=7,am)3?(an)49+8=3。8 837.解：(3x2n+2yn)3+=-27x=-27x6n+63n(3)6n+63n6n2n=-27x6y38.解：(x2?y-3)1=x2y3?x4y6,=x6y3,2-(an)2+(am)3=8X492n-x3y)2?(x2?y3)39.解：(a3m)2(b2)3+a2m?b3n,，2m3=(a)3n22m3n(b)+a=a4b14 4a a4 4=4b4b33.解：,a+b?2b-a9a

13、+b+2ba=9,解得：b=3,(-3)b+(-3)3=(-3)X(27)=-543+(-3)3=2X(-3)3=2=23-32+2X3,=540.解：原式=27x6n=23x6n=23(x3n)2=23X7X7=112741.解：=x2n=5,(3x3)2-34(x2)=9xn-34xn2n、3=-25(x)_3=-25X5=-312542.解：原式/6n4x3n=a2nb6n+5a2nb6n3=6a2nb6n-3a2nb6n=3a2nb6n43 .解：原式=(35x50?()3 34 444 .解：原式=an-5(a2n+2b6m-4)=3n3b6m-4+3n3(b6m4)=a3n3b6m

14、-4a3n-3b6m4=045.解：(1)xa=2,xb=6,(a2b6)50 x100=x1501.xab=xa+xb=2+6=Jl;3 3(2)xa=2,xb=6,x2ab=(xa)2+xb=22+6=23 346.解：2a?33b?37c=2X33X37,a=1,b=1,c=1,原式=(1TT)1998=147.解：原式=-(工)1998X(4,、1998=-(3x4)x4 4=-1X(4),=448.解：(1)原式=(2a+b)(2n+1)=(2a+b)3n;(2)原式=-(x-y)2?(x-y)/、7=-(xy)?y2z6(2)(a-2)3(bc-1)=a6b3c3,_ab_ab=-.3 3，c