基于MATLAB的简易矩阵计算器

1、精选优质文档-倾情为你奉上MATLAB程序设计程序设计报告设计题目：简易矩阵计算器班 级：姓 名：余颖智学 号：目录1. 设计目标2. 设计内容3. 设计思想4. 设计说明5. 设计步骤及程序代码6. 运行计算器7. 总结1. 设计目标1.熟悉MATLAB的主要控件使用方法。2.熟悉MATLAB的GUI设计流程。2.设计内容设计一个简易的矩阵计算器，通过对简单应用矩阵计算器的设计，编制、调试实现矩阵相加减，矩阵的转置等简单运算，以学习应用MATLAB编写程序原理，加深对MATLAB的学习及应用。3.设计思想基于MATLAB中GUI界面的设计，通过创建类成员函数成员变量，编辑控件创建消息映射，调

2、用信息函数完成数据的输入输出，实现计算功能。生成简单的应用软件。4.设计说明1) 包含的功能有：加、减、乘、转置等。2) 输入的原始数据分别为A或B矩阵，分别显示在不同标签中，运算的结果则显示在输出部分。3) 计算功能基本上是用系统内部函数。4) 程序能够自动判断输入数据的正确性，如不能输入（1）。5.设计步骤及只要代码1) 打开MATLAB，点击，出现GUI的2) 设计计算器版面直至3) 对功能键进行设计执行A矩阵加B矩阵，其执行代码如下A = eval(get(handles.Matrix_A,'String');B = eval(get(handles.Matrix_B,

3、'String');iA jA=size(A);iB jB=size(B);if iA = iB | jA = jB |(iA = iB & jA = jB) R='error.Matrix dimensions must agree.' set(handles.Answer,'string',R) guidata(hObject, handles);else result=A + B ; R =num2str(result); set(handles.Answer,'string',R) guidata(hObject,

4、 handles);end执行A矩阵减B矩阵，其执行代码如下A = eval(get(handles.Matrix_A,'String');B = eval(get(handles.Matrix_B,'String');iA jA=size(A);iB jB=size(B);if iA = iB | jA = jB |(iA = iB & jA = jB) R='error.Matrix dimensions must agree.' set(handles.Answer,'String',R) guidata(hObje

5、ct, handles);else result = A - B ; R = num2str(result); set(handles.Answer,'String',R) guidata(hObject, handles);end执行A矩阵与B矩阵相乘，其执行代码如下A = eval(get(handles.Matrix_A,'String');B = eval(get(handles.Matrix_B,'String');iA jA=size(A);iB jB=size(B);if jA=iBR='error.Inner matrix

6、 dimensions must agree.'set(handles.Answer,'String',R)guidata(hObject, handles);elseresult = A * B ;R = num2str(result);set(handles.Answer,'String',R)guidata(hObject, handles);end执行A右除B矩阵，其执行代码如下A = eval(get(handles.Matrix_A,'String');B = eval(get(handles.Matrix_B,'St

7、ring');iA jA=size(A);iB jB=size(B);if iA=iB 、 R='error.Matrix dimensions must agree.' set(handles.Answer,'String',R) guidata(hObject, handles);else result = A B ; R = num2str(result); set(handles.Answer,'String',R) guidata(hObject, handles);end执行A.*B，其执行代码如下A = eval(get(h

8、andles.Matrix_A,'String');B = eval(get(handles.Matrix_B,'String');result = A .* B ;R = num2str(result);set(handles.Answer,'String',R)guidata(hObject, handles);执行A./B，其执行代码如下A = eval(get(handles.Matrix_A,'String');B = eval(get(handles.Matrix_B,'String');result

9、= A ./ B ;R = num2str(result);set(handles.Answer,'String',R)guidata(hObject, handles);执行A的转置，其执行代码如下A = eval(get(handles.Matrix_A,'String');result = A' ;R = num2str(result);set(handles.Answer,'String',R)guidata(hObject, handles); 执行A右除B，其执行代码如下A = eval(get(handles.Matrix_

10、A,'String');B = eval(get(handles.Matrix_B,'String');iA jA=size(A);iB jB=size(B);if iA=iB þ R='error.Matrix dimensions must agree.' set(handles.Answer,'String',R) guidata(hObject, handles);else result = A / B ; R = num2str(result); set(handles.Answer,'String&#

11、39;,R) guidata(hObject, handles);end执行求A的行列式，其执行代码如下A = eval(get(handles.Matrix_A,'String');iA jA=size(A);if iA =jA R='error.Matrix must be square.' set(handles.Answer,'String',R) guidata(hObject, handles);else result = det(A) ; R = num2str(result); set(handles.Answer,'St

12、ring',R) guidata(hObject, handles);end 执行求A的逆，其执行代码如下A = eval(get(handles.Matrix_A,'String');iA jA=size(A);if iA =jA R='error.Matrix must be square.' set(handles.Answer,'String',R) guidata(hObject, handles);else if det(A) = 0 R='error.Matrix is singular to working pre

13、cision.' set(handles.Answer,'String',R) guidata(hObject, handles); else result = inv(A) ; R = num2str(result); set(handles.Answer,'String',R) guidata(hObject, handles); endend执行求A的非共轭转置，其执行代码如下A = eval(get(handles.Matrix_A,'String');result = A.' ;R = num2str(result);s

14、et(handles.Answer,'String',R)guidata(hObject, handles); 执行求解系数阵为方阵且非奇异的线性方程组，其执行代码如下A = eval(get(handles.Matrix_A,'String');B = eval(get(handles.Matrix_B,'String');iA jA=size(A);iB jB=size(B);if iA = iB R='error.' set(handles.Answer,'String',R) guidata(hObject

15、, handles);else if iA =jA R='error.Matrix must be square.' set(handles.Answer,'String',R) guidata(hObject, handles); else if det(A) = 0 R='error.Matrix is singular to working precision.' set(handles.Answer,'String',R) guidata(hObject, handles); else result = AB ; R =

16、num2str(result); set(handles.Answer,'String',R) guidata(hObject, handles); end endend 执行求A的秩，其执行代码如下 A = eval(get(handles.Matrix_A,'String');result = rank(A) ;R = num2str(result);set(handles.Answer,'String',R)guidata(hObject, handles); 执行求A的平方，其执行代码如下A = eval(get(handles.Matr

17、ix_A,'String');iA jA=size(A);if iA =jA R='error.Inputs must be a scalar and a square matrix.' set(handles.Answer,'String',R) guidata(hObject, handles);elseresult = A2 ; R = num2str(result); set(handles.Answer,'String',R) guidata(hObject, handles);end 执行求A的立方，其执行代码如下A

18、= eval(get(handles.Matrix_A,'String');iA jA=size(A);if iA =jA R='error.Inputs must be a scalar and a square matrix.' set(handles.Answer,'String',R) guidata(hObject, handles); else result = A3 ; R = num2str(result); set(handles.Answer,'String',R) guidata(hObject, handl

19、es);end 执行求A的特征值，其执行代码如下A = eval(get(handles.Matrix_A,'String');iA jA=size(A);if iA =jA R='error.Matrix must be square.' set(handles.Answer,'String',R) guidata(hObject, handles);else result = eig(A) ; R = num2str(result); set(handles.Answer,'String',R) guidata(hObject

20、, handles);end 执行求A开平方根，其执行代码如下A = eval(get(handles.Matrix_A,'String');result = sqrt(A);R = num2str(result);set(handles.Answer,'String',R) 执行计算矩阵范围（默认为2范数），其执行代码如下A = eval(get(handles.Matrix_A,'String');result = norm(A);R = num2str(result);set(handles.Answer,'String',R)guidata(hObject, handles); 执行对A的分解，其执行代码如下A = eval(get(handles.Matrix_A,'String');