第7章受扭构件计算

1、1第七章第七章受扭构件承载力计算受扭构件承载力计算23(a)(b)(c)(d)He0MT=He0H边框架主梁次梁4T tp5 678coryvst1ystyvst1corystAAAAufsfsfufll scorbcorh)(2corcorcorhbuscorhcorb910tTfhbTWTcp2max max bhT313.0208.010,1h/btcrfhbT211)3(62bhbWtttcrWfT ttcrWfT7 . 0123bh1F1F2F2F2F3F3F3F3F2b32bttcrWfbhbbbbbbhbbhbbbFbFbhFT)3(6)3/2(22212)2/)(2)3/(22

2、)3/2()2/()3/(2maxmax32113tftftwtWWWW)(22bbhWfftf)3(62bhbWtw)(22 bbhWfftfbfhbhfbfbbfhfhfh1415 cordATtq2ctgAuTFRcorcor2tan2sATNcorcossin2dcorctAT16coryvstAsfAT1217coryvst1ttscu2 . 135. 0+AsfAWfTTT18yvtsvsvsvffsbA/28. 0min.ttu7.0WfT2, 2,6 . 0min,取VbTVbTffVbTbhAyttlstltl19TwwTttwwTwwTttffTwwTttff20Vc/Vc

3、0Tc/Tc0ABCGD1.51.00.500.51.01.5t1.5 t) (c0cc0cVVTT21Vc/Vc0Tc/Tc0ABCGD1.51.00.500.51.01.5t1.5 t) (c0cc0cVVTT2200/15 . 1cccctTTVV005 . 1 ,cctcctVVTT05 . 015 . 1TbhVWtt0007 . 035. 0bhfVWfTtcttc0 . 10.5tVc/Vc0Tc/Tc0ABCGD1.51.00.500.51.01.5t1.5 t) (c0cc0cVVTT23cort1styvttt0v1svt0tAA2 . 135. 025. 1)5 . 1

4、(7 . 0sfWfThsfnAbhfVyvtst1vsv1sv1sAsAsA2400/15 . 1cccctTTVVVc/Vc0Tc/Tc0ABCGD1.51.00.500.51.01.5t1.5 t) (c0cc0cVVTT005 . 1 ,cctcctVVTT0) 1( 2 . 015 . 1TbhVWtt000175. 135. 0bhfVWfTtcttc0 . 10.5t250 . 35 . 1 ,AA2 . 135. 025. 1)5 . 1 (175. 10cort1styvttt0v1svt0thasfWfThsfnAbhfVyvtst1vsv1sv1sAsAsA26时，按内插

5、法确定。时，当时，当6)(420. 08 . 06)(25. 08 . 04)(t0t0wwwccwwwccwwwthbhfWTbhVthbhfWTbhVthbhtfWTbhV7 . 0t027280/MM0/TT29smAnAstl/nAst/smstlAnA/3031时，按内插法确定。时，当时，当6)(420. 08 . 06)(25. 08 . 04)(t0t0wwwccwwwccwwwthbhfWTbhVthbhfWTbhVthbh32tt07 . 0fWTbhV0 . 2VbT,6 . 0min,式中yttlstltlffbVTbhAyvtminsv,sv28. 0ffbsAsv330t35. 0bhfV )0 . 35 . 1 (1875. 00tbhfVtWfTt175. 03405 . 015 . 1TbhVWtt0) 1( 2 . 015 . 1TbhVWtt0 . 35 . 1 ,AA2 . 135. 025. 1)5 . 1 (175. 10cort1styvttt0v1svt0thasfWfThsfnAbhfVyvcort1styvttt0v1svt0tAA2 . 135. 025. 1)