聚类分析例题及解答

聚类分析作业例题:countrypopulatndensityurbanreligionlifeexpflifeexpmliteracypop_incrAfghanistan20,50025.018Muslim4445292.8Bangladesh125,000800.016Muslim5353352.4Cambodia10,00055.012Buddhist5250352.9China1,205,200124.026Taoist6967781.1HongKong5,8005,494.094Buddhist807577-0.1India911,600283.026Hindu5958521.9Indonesia199,700102.029Muslim6561771.6Japan125,500330.077Buddhist8276990.3Malaysia19,50058.043Muslim7266782.3N.Korea23,100189.060Buddhist7367991.8Pakistan128,100143.032Muslim5857352.8Philippines69,800221.043Catholic6863901.9S.Korea45,000447.072Protstnt7468961.0Singapore2,9004,456.0100Taoist7973881.2Taiwan20,944582.071Buddhist7872910.9Thailand59,400115.022Buddhist7265931.4Vietnam73,100218.020Buddhist6863881.8进行聚类分析，步骤如下：1、标准化的欧式距离聚类各类所属>cutree(hc2,2)AfghanistanBangladeshcambodHcichinaHongKonglnd~iaindonesia1112'312mpstnMalaysiaN.KoreaPakistanPhilippines£.Koneasingipo-reTaiwanThai11andVietnani1223类平均法系统聚美I藉=更|—■Itsaew巨I藉=更|—■Itsaew巨——甜O告「心odn36.EsIIPMUO工IuaJdcuJISEa一=LHrT落仁Qpu-EE专>

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IMWFT得出以上结果，以欧氏距离为计算距离方法，把以上17个亚洲国家地区按6个变量欧氏距离划分为三类。第一类为：Bangladesh第二类为：China最短距离法系统聚类第三类为：Malaysia2、尝试其他类间距离方法s叩匚-dd-一一id™(na»uoPLI_EeLI苞>£uo碧A™旻茅豆±E-poqERoLlsgpco-6LJEIXIu{0^」rDLI6M匚省尧CL卷一(□卷*巴odfci顷仁仍6UO*顷UO_L仁仲宙「最长距离法系统聚美I忍JW.N「岩&6畚I顷匚0*5仁0丁—」EdE「I带£d二-L-dIE%仁OPU「焉母AL档五IUEMCUI—IES-S「{□_§&—J_妨碧四顷旨①fl仁兼-仁趋」女—总切互CUCLL岩匚一一一一一一9;Cl中间距离法煮统聚类su'g三£™眼U£LIEcci£<D>EgUEMral菖wu>P羞更一™卷翌眼睫.Npods仁-s昌菖。工u«Dtfo_poquja3。rUM翌e一ES——_|宣旻食I—E一皇---口Z售|<舟K蝎重心法系统聚类E™更-(□EOMN看匚一dd=_£竺SUB三EE专A度一6匚岩colI8EOMS巴odE.?/—POKUO工IutodrDrItciuoqlwurqsOJPR一pmIIII—Ua3ls_uccij_5』<匚杉一尧d----*愣其他类间距离方法得出以上结果，以欧氏距离为计算距离方法，把以上17个亚洲国家地区按6个变量欧氏距离也可以划分为以下三类：第一类为：Bangladesh第二类为：China第三类为：Malaysia3、用样本主成分画图clusplot(fanny(x=a,k=3))silhouetteplotoffannyhn=1了3clustefsC)-201230.0020.40.6081.0Sihouettewidths；Component1Thesetwocamponentsexplain8Averagesi