高一化学离子反应与离子共存教案

《电解质在水溶液中的电离和离子方程式书写》教案（一）电解质的概念（二）电离的概念

（三）从电离的角度认识酸碱盐（四）强电解质与弱电解质Cl

·H

（五）电离方程式

R = +

+ R = ++

Cl

=2

++

=

++

=

Rn+

+

=

+

+

=

2++

AB

=

+

=

+

+

Cl

=

++

K=

+ Al3++++ 例如：一元弱酸： +多元弱酸分步电离：

+，

+

一元弱碱：·H

4+多元弱碱：多元弱碱一步完成。

2+（六）电解质的概念辨析

（七）电解质溶液导电性的强弱

（八）离子反应的概念

Cl24

Cl2424

2++Cl

BaCl

BaCl

2+

（九）离子反应发生的条件 24

===H

23===CO（十）离子方程式

Cl=====H

（十一）离子方程式的书写

+

+2+2++

::

:

:Ca(OH),:,,, :

bdIe+H+

.+H:.ClCl..

...).

===2Fe

===Fe

23===CO===Ca

23===CO23===CO===Na===2Na

24

24

2424

23

Cl

23

23

AlMg

【基础】

A B.

AB AB

AB AB

____________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________·HO_____________________________________________________________(6)NaCl_____________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________)________________________________________________________)__________________________________________________________

AB A

B

A

B

·H

===H A===HB===H2423===H A24

BCl23 A===HB===Ca

AB===CO

A B

A===2Fe

B23===CO===Cu24 A B 【巩固】 ABCl

Cl

Cl

A B A

B A B A BCl A.B. A===HB===Ca

AlCl

Al

I

mA

________

B

________

________

b

n

n

n(K

A B/2/2 ABAB. A===COB===Ag===2Fe

AMgB===Fe

Cl=====CO

AB

A B AKClBKClCl________________________________________________

KCl__________________________________(________(________________ A B Cl AB

AB

A B

________________________________ +1 2++ ++N5++3O A

B

________________________________________________ ===H===Ba

===2Fe

2424__________(__________________________________________________________________________________________________

AB

________

A

________(

____________________________________________ A

===Zn

B===Cu

23===2Fe

A24ClKCl

BClK23===H

A23

BClMg AMgCl

B23KK(AB AClB===Ca===Cu===Fe

A

B===Cu

===2Fe

===H A 24B 23

Al

ClKK

Cl

24Cl

ACl24BKClMgCl24Cl23____________________________________________________________________________________________________________________________________________________________

_____________________________