(完整)空间解析几何与向量代数习题与答案

经典word整理文档，仅参考，双击此处可删除页眉页脚。本资料属于网络整理，如有侵权，请联系删除，谢谢！第七章空间解析几何与向量代数Aa(6,7,6)M(4,2MMM和1212mi5jk,n2i4jk,pijk在xyamnp及；及abab(2)(a)babaijk,bi2jkMM(,M(MM,MM1231223与轴。a2),b(abzyz2x4y2z0x222绕x2xy2绕x4x9y36xy2x22绕xy22yx2yx2z4(xy)222zxy)22xy29214y3xyz9xz12220zyxyax(a0)ax22222xxy3z1215，x2z1y3z2x2y4z703x5y2z10x4y3z521xy3z0xyz10xyz0x2yz7x1y3z；2xyz7112x2y2z3314xyz10B2xyz40（abc0a,,c。abbcca(a,b)。abab,.|a|b(atb)且nanxa。2xy5z03，M(M(6x2y3z7012x2yz10xyz2xyz20112y1xyz1L：z1100MM(12yz2x022在xoyz3ik,jk2x4yz04xyz13xy2z90Ca,,c，,,a,,cabc00x2y12M11302x1y3z(3x4yz0112x1yzxyz2630110gxoyaxbab(a,b)。lim3xx0x2y绕yL:1z(y2第七章空间解析几何与向量代数习题答案A676,,1111113412212，,,MMcos2,cos,cos231xyab31(2(2)(3(2)3)，22()2ijk^a3MM1MM223ijk1223a6,,}217217217a(((x2y2z2)xyz2x2y2z2x222x4x2y2z23699绕y轴：4x2z2y2364922z0a222z3x7y5z402、1(x1(yz09yz20y50x1y2z3xy2z42152313、16x14y11z6508x9y22z590B322abc0a(abc)0，即,ababac0aa0abaccaabbc(,)ababsin(a,b)ababcos(a,b)6|atb|(atb)(atb)|a|t|b|t(ab)2222ab2t|b|21。bina,nbnj6k)n{,B,B0或1y0x3y0x3nMMnn121ijk取3nMMn27411623M(6x3yz701nM(x,y,z)MM1和121x4y1z23036274x2yz1(2xyz2)0x3y4z010。xx10xyz1WFMM0((100g)(600g5880J12xoy2902yx2x0z3被y2z2z01921||SOAB217x31y37z11704xyz1C,OAaOBbOCc,ABbaACcaBCcb,，ab,,0caaaba即与ACAB,,ABC(P(P，x1y2121PMPM1122020122(2)1(2)423，358x1y2z1.x1yz4mnpm4np0(mnpMM1120，03401即430mnpx1yz4:::19:mnp4、解：已知两直线的方向向量为S，故垂直于两方向向量的向量可取为S12nSSi6j6k126602210(0,0,2)xyzxyzx2y2z103d1122222(,,)MxyzM(x,y,0)||gMMgxx,yy，，z。MM0000000又1Mx2y2000(x)()1yxzyz()()12222axbaaxb2a2x(axba)(axbaxbaa))(limx0limlimxx(axba)x0x0(aa2xabxb2)aaabxb222ab2limlim