电大经济数学基础1形成性考核册答案2

经典word整理文档，仅参考，双击此处可删除页眉页脚。本资料属于网络整理，如有侵权，请联系删除，谢谢！xx0xx2x0k,x0fx0k1yx在x22x5f2xπfxf()__________22xD）x21A．e2．Cx．Dx1xB）xxxx1xlim1lim1limxsin1lim1xxx0x00xydy（B11ln10dxD．1dxC．dxdxB．2xxln10A．xxxB0AA)x．B00x0xx001f()xxf（BA．．B1111x．Dx2x2xx23x22)x2121limx1x1==x21x1112x1limx25x6x3231lim=x26x84)x4242x2x2x21x1x(1x1x1x1=112limx0lim=x0=1x1x1x1x0x01/1735232x3x5220023003xx224lim3x2x42xxxx23xlimlim33553135153xlimx0x0x0lim5x5xx0x242)2)x2limx22)4142)2)x2x2x21xsinx0xa,fx0，x0xfx0在fx0在fx0在limflimfx0x01b)bx又x0x01xx0x0b1即a为实数、b1fx0在fx0在limflimfx0x0aab1又ab1fx0在1yx2logx2yy2x22x2xx2axbcxdb)d)d)d)adbc=yyy=d)2d)2d)22/171123211232yyy]123x511y))1yxxyxxexxex222yeaxy)eeeaxaxaxax=dyydxbeaxax1yexxx1e3131y))e()x313212x1xx2xx2x221e31xdyydx(x2x22yxex2（7），求解：sxi2xex22xny(x)c(e)ose)x2x22ysinxyny]cosxnnn1n1y1x2y1x1x211y1x)2x)))22x1x21x1x11x1x121x)212x)=22x1x1x1x22221x2x132y2cotyxx11132x26ysin1)))(2)2sin1)xx0115x26x63/1711112sin111sin1)xx356356x2xx2x2cosxx26xcosx262yy是x或xyxy3x122x))222x2yyy30y2x3y2yxy2x3dyydxdx2yxe4xyxyxe4y)exy)4xyxyyxe)4xyxy4xyyxy12xyx)yyx)221x21x22xx)22x)22x22y()1x2x)x)22221x1x1111312yyyy()))xx及22222xx1122213113153y(xx)1353(x)(xx222222244222f2x2xcf22x.dxc.4/171fFcx2x)c22dex02dx111P0dtP.121x2x1A．D1222222C）．111lnxdxd()2dxd(2)dxdxB．C．xxxxCx，B．x1x2xC．D．dxA．1x20122B．161500C．D．A．11B）．11xdx1x2dxexdxA．1013x2xdxdxex31312xx2x()()cxdxxe1e(x12xx132224223512xxxc3522x24dxx21dx12x111dxx2xc2x22212x122xc5/17sinxxx2x2dx12xd(2x)2sinxdx22213x)c2cosxc223xdx2x2x2x1xxx2x4d()221x12xx24cxc221ex21xdx2dxx21111ed()112x2xx1111221211xe22211152221ee213dxx2x11011231222110123e22124001112422x204ex4x101e24dx4x21006/17121ex2xdxe14xex4ed(x2140111ee244044ee122445412431045A3232a__________________23A21613AB32ABT=________nB)A2ABB2ABBA22nB)ABXXXB)A11001001A020A__________00120031003CA．若ABABACAOBCB．若CAO,BOOA34B52为为TCTA24423553B．C．nC`B)ABB)ABABBAA．111，B．111C．D．7/171231011111D．023101B．A．C．0022003123222A333B444A．0210112=531035021100030000301254=01212312424512214361013223132712312424577245521221436107061010=解13223132704732732231123A111，B112AB。011011AB解因为23123222A111112((22312011010123123B112000110118/17AB2007124A21)1101241241102112412421131274322111001404701492,30049当)242532158543A17420411232532117420585432532141123215585431742041123312414A1,3174200271563095210271563174200952100000000002334332,3→∴)2。132A301111132100132100097310043101213311AI3010101110012329/171321000111120431011321000111120013493242113223113058010237001349100113113010237A2371∴12300134934963=421．21163100100130421010→211001AI421010211001123100130100130011261→0214021431211021400112612,3100130011261100130010271001012322231001012130271012-=11212,B3523AXAB．1210121001311052013112221AI213350152A1∴31125210XBA1=∴233111BABBBBA，121212BAABBAAB，112210/17BBABABAABABABB∴12121212BBA即12BBABBABABBABABB1212121212BBA即12AAAAAA，T，TTAATTAATTAAAATTTAAT∴∵)ATAAATTT=TTAAT∴AA∵TTAATTAATTAA∴TnABBA。ABAABB∵T，TAB若ABABTABBABAABBA而TTABBAABBABAAB若TTTAB∴An为为BnBBTBAB11AABBTT1BAB1TABBT1TBABTTBAB1TTBAB∴111/1741f4x_________________).y2________xppq(p)10e2E=E2pp111D111____________1111116bt__________t1.A013200t10(,BAC．xx21fxf(（C）．1A．x1x．C．Dx2．Bx2Aexexexex11dx011dx01x01x0A．B．2322AXbD）．mn))m)nmn))nA．xxa1xxa21C）．232x2xxa1233aaa0aaa0aaa0aaa01A．C．D．12312323123yexydyeeedyedxedyedxeecxy,yxyx,yxdxdyxdx3y212/173ydyxedx3ydyxdeyxeedxyxeec2x2x3xx3xx2yy3x122dxdxyex1ecex1edxcx1x1dxc32lnx132x12lnx1x11x1x1c222yy2xsin2xx1x1xdxdxe2xsin2xedxclnxlnxye2xsin2xedxc1x2xsin2xdxcx2xcxxcxye02xy,e2xeyedyedxy2x1eecy2x2用x0112eec，c00211eey2x22ye00x,11yyexxxex11yeecxxx1xelnxeedxcxlnx13/171x1ececxxx用x0：0ecce1yecxx7x2xx013xx3x2x0412342xx5x3x01234102111321021011101111021011100002113123212153x2xxx1xxx34342342xxxx1123x2xx4x241x7x4x5234123421111A121421745121421214221231121111174505373053731,2164105551214212142137337320537300000010155500000321512255500000416xxx555134A秩A337x2xx55534x3414/17xx5x4x212xx3xx123413x2x2x3x323417x5x9x10x2341234115422131132233759101154201139301139302261814212313413A1154210851011393000000000801139332142212100000000088时，x18x5xx1x313x9x