100道初一数学计算题

100道初一数学计算题实用文档1.1-(-2)/(-1/2)=22.-3*(-1)=34-(-2)=95*(-1)^2003=-56.-2+(-3)=27.-13-3*(-1)=-108.-32/(-3)=10.66679.(-3)^2*(-2/3)=410.-32/(-1/2)^2=-12811.(-2)^2-2+(-2)^3+2^3=412.(-5/2)*(-4)^2-0.25*(-5)*(-4)^3=8013.42/(-1/4)-54/(-5)^3=-5.6414.-26-(-2)^4-32/(-1/2)^7=-2315.-(-2)^2-3/(-1)^3+2*(-2)^3=-1816.-14-1/2*2-(-3)^2/6=-13.517.[1-(1-0.5*0.5)]*(2-(-3))=1.518.(-2)/(-3)^2+(-3)+2=-2.111119.-2/(-1)+(-2)*(-2)=120.-3^2-3*(-4^2+2)-(-3)^2/(-2)=23321.(-10)^2+[(-4)^2-(3+3^2)*2]=5122.(-1)^4-(1-0.5)*[2-(-2)^2]=-0.523.-0.5^2+2=2.2524.(-2)^2002*(-2)=225.(-2)^3-3*[(-4)^2+2]-(-3)^2/(-2)=-1126.(-0.25)^2009*4^2004=0.000127.0.25*(-2)^3=-1.528.1/2-4/(-3)+1=-0.16729.-32*12.2/(-0.3)+(-2/3)*(-3)/(1)=410.333330.(-2)*(-0.5)*(-2)*(-8)/2=1631.1/8-2/(-4)-(3/2)^2=-5.2532.(5-6)-(7-9)=-733.(-3)*(-9)-(-8)*(-5)=-2734.15/(-1/2)=-3035.-5-9+17-3=036.-24-(-4)^2/(-1)+(-3)=-2237.25*(-0.125)*(-4)*(-1)*(-8)*1=20038.Givena+1+(b-2)^2=k,find(a+b)^2011+a^2010-3ab+a.+5和n-3互为相反数，求m+n的值。解：根据已知条件，有|m+5|=-n+3，即m+5和-n+3互为相反数，因此m+5=3-n。将其代入原式，得到m+n=(3-n)+n=3。因此，m+n的值为3。(67)1+(-2)+(-2)-3-5;If22x+ynissimilartonm,thenthevalueofx32017+y2018-(m+n)is(68)(-5)×(-7)-5×(-6)(69)(-2/3)÷(-8/5)÷(-0.25)(70)-2*(-1)+(-2)/(-2)(71)(-3)/2×(-1/2)+4-22×(-1/3)(72)(+/-)×(-12)(73)(-1/2)×(-4)^2-0.25×(-5)×(-4)^3(74)(-1/3)-1+(-2/3)-(-3/4);(75)(-3)/2×(-1/2)+4-22×(-1/3)(76)(-5)×(-8)×(-10)×(-15);(77)(-3)×(-4)×(-5)+(-5)×(-7)(78)(-0.1)×(-1)×(-100)-0.01×(1000).(79)2/1328×(-1)×(-1/4)×(-3/7);(80)(-1/11+1/23)×(-20);(81)(-3)×(-0.12)×(-2)×33;(82)(5/2-3/7)×(-36).(83)-×(12-2-0.6)/65(84)(+1)×|(-1)|×2×(-5);(85)(-1)×3/(-13);(86)-9×(11)-12×(-8);(87)(-2)×(-1/3);(88)(-13.52);(89)(-1);(90)(-3.25)×(+4.2-7.8);(91)(+185.8)×(+36);(92)(-4)×(-7)×(-25);(93)(-1)×8×(-4);(94)20/20×a=1;(95)(-1)×(-8);(96)(-31)×0.125×(-2)×(-8);(97)8×(-1)-(-4)×(-1)+(-8)×