Digital Logic Circuits 数字逻辑电路智慧树知到期末考试答案2024年_第1页
Digital Logic Circuits 数字逻辑电路智慧树知到期末考试答案2024年_第2页
Digital Logic Circuits 数字逻辑电路智慧树知到期末考试答案2024年_第3页
Digital Logic Circuits 数字逻辑电路智慧树知到期末考试答案2024年_第4页
Digital Logic Circuits 数字逻辑电路智慧树知到期末考试答案2024年_第5页
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DigitalLogicCircuits数字逻辑电路智慧树知到期末考试答案2024年DigitalLogicCircuits数字逻辑电路Amodulus-12countermusthave

A:3flip-flopsB:synchronousclockingC:12flip-flopsD:4flip-flops答案:4flip-flopsThreecascadedmodulus-10countershaveanoverallmodulusof

A:1000B:30C:100D:10000答案:1000

Atypicalmacrocellconsistsof

A:afixedlogicarrayB:aGraycodecounterC:gatesandashiftregisterD:gates,multiplexers,andaflip-flop答案:gatesandashiftregisterTwotypesofSPLDsare

A:GALandSRAMB:CPLDandPALC:PALandFPGAD:PALandGAL答案:PALandGALTheLUT,usedintheLUT-CPLDarchitecture,isbasicallyamemorythatcanbeprogrammedusing

A:answers(a),(b),and(c)B:SOPfunctionsC:POSfunctionsD:productofcomplements答案:SOPfunctionsDatathatarestoredatagivenaddressinarandom-accessmemory(RAM)arelostwhen

A:newdataarewrittenattheaddressB:

answers(a)and(c)C:thedataarereadfromtheaddressD:powergoesoff答案:answers(a)and(c)Dataarestoredinarandom-accessmemory(RAM)duringthe

A:enableoperationB:addressingoperationC:readoperationD:writeoperation答案:writeoperationNonvolatileFPGAsaregenerallybasedon

A:fusetechnologyB:EEPROMtechnologyC:SRAMtechnologyD:antifusetechnology答案:antifusetechnologyToparallelloadabyteofdataintoashiftregisterwithasynchronousload,theremustbe

A:oneclockpulseforeach0inthedataB:oneclockpulseC:eightclockpulsesD:oneclockpulseforeach1inthedata答案:oneclockpulseThemodulusofacounteris

A:themaximumpossiblenumberofstatesB:thenumberofflip-flopsC:theactualnumberofstatesinitssequenceD:

thenumberoftimesitrecyclesinasecond答案:theactualnumberofstatesinitssequenceThestorageelementofaDRAMisa

A:transistorB:capacitorC:diodeD:resistor答案:capacitorTheoutputofaMealymachinedependsonits

A:nextstateB:inputsC:presentstateD:answers(a)and(c)答案:inputsThemostcommonADCseenintelecommunicationsbasedonaudiosignalsis

A:dual-slopeADCB:sigma-deltaADCC:flashADCD:successiveapproximationADC答案:sigma-deltaADCThebasicelementsofanFPGAare

A:both(a)and(b)B:configurablelogicblocksC:PALarraysD:I/Oblocks答案:both(a)and(b)Thefinaloutputofthesynthesisphaseofadesignflowisthe

A:timingsimulationB:devicepinnumbersC:bitstreamD:netlist答案:netlistThefactorthatdeterminestheadequacyofaGALforalogicdesignis

A:both(a)and(b)B:thenumberofinputsandoutputsC:thenumberofinvertersinvolvedD:thenumberofequivalentgatesordensity答案:both(a)and(b)A3-bitbinarycounterhasamaximummodulusof

A:6B:16C:8D:3答案:8Inafunctionalsimulation,theusermustspecifythe

A:inputwaveformsB:outputwaveformC:specifictargetdeviceD:HDL答案:inputwaveformsA10MHzclockfrequencyisappliedtoacascadedcounterconsistingofamodulus-5counter,amodulus-8counter,andtwomodulus-10counters.Thelowestoutputfrequencypossibleis

A:2.5kHzB:25kHzC:10kHzD:5kHz答案:2.5kHzAmemorywith512addresseshas

A:9addresslinesB:512addresslinesC:12addresslinesD:1addressline答案:9addresslinesToenterabyteofdataseriallyintoan8-bitshiftregister,theremustbe

A:fourclockpulsesB:eightclockpulsesC:twoclockpulsesD:oneclockpulse答案:eightclockpulsesThemaximumcumulativedelayofanasynchronouscountermustbe

A:lessthantheperiodoftheclockwaveformB:morethantheperiodoftheclockwaveformC:both(a)and(c)D:equaltotheperiodoftheclockwaveform答案:lessthantheperiodoftheclockwaveformInacomputer,theBIOSprogramsarestoredinthe

A:RAMB:DRAMC:SRAMD:ROM答案:ROMThequantizationprocess

A:convertsasequenceofbinarycodestoareconstructedanalogsignalB:filtersoutunwantedfrequenciesbeforesamplingtakesplaceC:convertsasampleimpulsetoalevelD:convertsthesample-and-holdoutputtobinarycode答案:convertsthesample-and-holdoutputtobinarycodeThelogicmoduleinanFPGAlogicblockcanbeconfiguredfor

A:both(a)and(c)B:registeredlogicC:parallelmodelogicD:combinationallogic答案:both(a)and(c)InVerilogHDL,~(1010)is(0101),and!(1010)is0.

A:错B:对答案:对Twocascadeddecadecountersdividetheclockfrequencyby10.

A:错B:对答案:错Astatemachineisasequentialcircuithavingalimitednumberofstatesoccurringinaprescribedorder.

A:对B:错答案:对LogicsimplificationisstillusefulinnowadaysFPGAdesigns.

A:对B:错答案:错ANORgatecanbeconsideredasanORgatefollowedbyaninverter.

A:错B:对答案:对Acounterwithfourstageshasamaximummodulusofsixteen.

A:错B:对答案:对Themodulusofan8-bitJohnsoncounteriseight.

A:对B:错答案:错Ashiftregisterwithfourstagescanstoreamaximumcountoffifteen.

A:对B:错答案:对Deltamodulationisbasedonthedifferenceoftwosuccessivesamples.

A:正确B:错误答案:正确Ashiftregistercounterisashiftregisterwiththeserialoutputconnectedbacktotheserialinput.

A:错B:对答案:对Ashiftregistercannotbeusedasatimedelaydevice.

A:对B:错答案:错TwotypesofDACarethebinary-weightedinputandtheR/2Rladder.

A:对B:错答案:对Aserialshiftregisteracceptsonebitatatimeonasingleline.

A:错B:对答案:对Ahighersamplingrateismoreaccuratethanalowersamplingrateforagivenanalogsignal.

A:错B:对答案:对Toachieveamaximummodulusof32,sixteenstagesarerequired.

A:对B:错答案:错SynchronouscounterscannotberealizedusingJ-Kflip-flops.

A:错B:对答案:错Fan-outisthenumberofsimilargatesthatagivengatecandrive.

A:错B:对答案:错Addressmultiplexingcanreduce

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