PHP实现两种排课方式

第PHP实现两种排课方式两种排课方式：

固定每周的固定时间上课（例：共上20节，每周六、周日早上8点-10点上课。假如今天周六凌晨1点，那么排课也需要从今天开始）总共上几个周，每周上课时间比较个性化（例：共上三周，第一周周一周二早上8点-10点上课；第二周周三周四下午8点-10点上课；第三周周日中午11点-12点上课。）

第一种排课比较好实现，简要代码如下：

*生成日期列表

*@paramint$startDate开始日期时间戳格式

*@paramarray$timeList课时计划列表

"start_at":"09:09",//开课时间

"end_at":"10:09",//结束时间

"week_at":1//周几

"start_at":"12:09",//开课时间

"end_at":"13:09",//结束时间

"week_at":1//周几

"start_at":"09:09",

"end_at":"10:09",

"week_at":5

*@paramint$amount课时计划数量

*@paramint$skipHoliday跳过节假日

*@returnarray

publicfunctiongenerateDateList($startDate,$timeList,$amount,$skipHoliday=0)

//计算开始日期是周几

$startDateWeek=intval(date('N',$startDate));

//规范化课时数据week_at做key的三维数组

foreach($timeListas$item){

$weekAt=$item['week_at'];

array_splice($item,0,0,$weekAt);

$key=array_shift($item);

$weeksTime[$key][]=$item;

$item=null;

unset($timeList);

if(empty($weeksTime)){

$this-addError('课时计划数据为空');

returnfalse;

//设置跳过假期,获取开始日期之后的节假日

if($skipHoliday){

$holiday=newHoliday();

$holidayData=$holiday-getHolidayList($startDate);

$holiday=null;

unset($holiday);

$nowTime=time();

$list=array();

for($weekStartTime=$startDate,$count=0;$count$amount;$weekStartTime+=86400*7){

//$currentWeek:周几

foreach($weeksTimeas$currentWeek=$weekTime){

foreach($weekTimeas$time){

//算出对应的日期时间戳

$currentDateTime=$weekStartTime+(($startDateWeek=$currentWeek($currentWeek-$startDateWeek):(7-$startDateWeek+$currentWeek))*86400);

//对应的日期=开始时间+((开始时间对应周=数据对应的周几？(数据对应的周几-开始时间对应周)：（7-开始时间对应周+数据对应的周几）)*86400)

//假期跳过排课

if($skipHoliday!empty($holidayData)){

$startUnix=$currentDateTime+$time['start_at']*3600;//开始时间

$endUnix=$currentDateTime+$time['end_at']*3600;//结束时间

$skip=false;

//选择跳过节假日，且节假日与当前课程时间有重叠跳过

foreach($holidayDataas$item){

if(($item['start_at']$endUnix$item['end_at']$startUnix)||($item['start_at']===$startUnix$item['end_at']===$endUnix)){

$skip=true;

continue;

if($skip){

continue;

$currentDate=date('Y/m/d',$currentDateTime);

$startAt=strtotime($currentDate.$time['start_at'].':00');

$endAt=strtotime($currentDate.$time['end_at'].':00');

if($startAt$nowTime||$endAt$nowTime){

$this-addError('上课时间不能小于当前时间');

returnfalse;

$list[]=[

'date_at'=$currentDateTime,//日期

'week_at'=$currentWeek,//周几

'start_at'=$startAt,

'end_at'=$endAt

$count++;

if($count=$amount){

break3;

$weeksTime=null;

unset($weeksTime);

return$list;

}

（例子，只用来展示数据结构）假如总共5节课时，从6-25日开始排课，每周一、周六上课：

（例子，只用来展示数据结构）排课结果为：

第二种排课方式稍微麻烦一点，简要代码如下：

*生成日期列表

*@paramint$startDate开始日期时间戳格式

*@paramarray$taskList任务列表

"start_at":"09:09",//开始上课时间

"end_at":"10:09",//结束时间

"week_at":1,//周几

"week_number":1//第几周

"start_at":"09:09",

"end_at":"10:09",

"week_at":2,

"week_number":1

"start_at":"09:09",

"end_at":"10:09",

"week_at":1,

"week_number":3

*@returnarray

publicfunctiongenerateDateList($startDate,$taskList)

//计算开始日期是周几

$startDateWeek=intval(date('N',$startDate));

$list=[];

$nowTime=time();

$weekSign=$week=0;

foreach($taskListas$key=$task){

if($task['week_number']$weekSign$task['week_number']!=$week){

$weekSign=$task['week_number']-$week;

//计算每条数据对应的日期$key==0：确定第一周第一节课是在本周还是下一周

if($key==0||$task['week_number']==$week){

if($task['week']=$startDateWeek){

$task['date_at']=$startDate+

(($weekSign-1)*7+($task['week']-$startDateWeek))*86400;

}else{

$task['date_at']=$startDate+

(($weekSign)*7-($startDateWeek-$task['week']))*86400;

}else{

if($task['week']$startDateWeek){

$task['date_at']=$startDate+

(($weekSign)*7+($task['week']-$startDateWeek))*86400;

}else{

$task['date_at']=$startDate+

(($weekSign)*7-($startDateWeek-$task['week']))*86400;

$startDateWeek=intval(date('N',$task['date_at']));

$week=$task['week_number'];

$startDate=$task['date_at'];

$dateAt=date('Y/m/d',$task['date_at']);

$startAt=strtotime($dateAt.'00:00:00');

if($task['start_at']){

$startAt=strtotime($dateAt.$task['start_at'].':00');

$endAt=strtotime($dateAt.'23:59:59');

if($task['end_at']){

$endAt=strtotime($dateAt.$task['end_at'].':00');

if($startAt$nowTime||$endAt$nowTime){

$this-addError('上课时间不能小于当前时间');

returnfalse;

$task['start_at']=$s