山西省太原市2026届高三年级模拟考试（一）物理+答案

太原市2026年高三年级模拟考试（一）

物理参考答案与评分建议

一、选择题：本题共7小题，每小题4分，共28分。在每小题给出的四个选项中，只有一

项是符合题目要求的。

题目1234567

答案DDCADCB

二、多项选择题：本题包含3小题，每小题6分，共18分。在每小题给出的四个选项中，

至少有两个选项正确，全部选对的得6分，选对但不全的得3分，有选错的得0分。

题目8910

答案ACADBD

三、实验题：本题包含2小题，共16分。

11.（8分）

（1）0.650（3分）

d

（2）（2分）

t1

（3）（3分）

12.（8分）

L

（1）p（2分）

S

1

（2）（2分）

I

pb

（2分）

aS

pb（分）

_R02

S

四、计算题：本题包含3小题，共38分。解答应写出必要的文字说明、方程式和重要演算

步骤，只写出最后答案的不能得分。有数值计算的题，答案中必须明确写出数值和单位。

13.（9分）

（1）瓶内气体发生等容变化

p1p2（分）

=···············································································3

T1T2

T1=t1+273K=400K

T2=t2+273K=300K

（分）

p2=1.5atm··········································································1

（2）瓶内原有气体，据理想气体状态方程

,

p1Vp3V（分）

=··········································································2

T1T2

mV,V

漏-

=·········································································（2分）

m原V,

m漏1

=···············································································（1分）

m原3

14.（12分）

（1）S拨向1，电容器充电

q

C=·················································································（2分）

E

q=CE················································································（1分）

（2）S拨向2，电容器放电，线框加速运动并切割磁感线产生感应电动势，

直到电容器两极间电压与线框的感应电动势相等时，电容器放电结束，线

框获得的速度最大，此时电容器的电压为U,电容器的电荷量为q1

U=BLv··············································································（1分）

对于线框，由动量定理

2ΣiLBΔt=mv_0································································（1分）

（分）

Δq=q_q1=2ΣiΔt·····························································1

v······································································（1分）

1

（3）根据图像可得电容器储能公式为CU2·······························（1分）

2

根据能量守恒定律

2

CECUmv+Q总·················································（2分）

PQ边在加速过程中发出的热量

QQ总·············································································（1分）

Q·································································（1分）

15.（17分）

（1）离子带负电····································································（3分）

（2）离子从ab边界进入磁场到N点做匀速圆周运动，根据几何条件，

离子在磁场中的轨迹半径为r1

r1=R··················································································（1分）

v2

1（分）

qv1B=m··········································································1

r1

离子从N点到P点做类平抛运动

qE1=ma1·············································································（1分）

R=v1t1················································································（1分）

Ra1t·············································································（1分）

2（分）

E=E1=2kRB·····································································1

（3）离子从距M点0.8R处射入磁场，做匀速圆周运动，半径为r2，

Rsinθ+r2=0.8R·································································（1分）

Rcosθ+r2=R·····································································（1分）

sin2θ+cos2θ=1

r2=0.2R

离子做匀速圆周运动周期为T磁1，运动时间为t磁1

v2=0.2BkR

π

t=············································································（1分）

磁12Bk

离子从C点进入电场到Q点做类平抛运动，运动时间为t2，OC与OM的

夹角θ=37°

Rsinθ+R=v2t2···································································（1分）

0.8RkE2t······································································（1分）

从Q点离开电场的速度大小为v3，方向与OQ夹角为α

v2

v3=

cosα

，，

t2=α=45ov3=0.22BkR

离子从Q点离开电场进入QON直线上方磁场做匀速圆周运动，运动半径为r3，

周期为T磁2，运动时间为t磁2，根据几何条件

R··············································································（1分）

t磁············································································（1分）

离子从