工程电磁场实验报告

工程电磁场实验报告电气工程及其自动化10(1)XXXB09380121源程序代码:/Prep7/pnum,area,1/Prep7/pnum,area,1HC=9.55e5!9.55e5BR=1.26!4000!Rseidualinducmp,murx,1,4000!theironmp,murx,2,1!theairmp,murx,3,1!thecoilet,1,13l=0.06w=0.01fw=0.015fl=0.005L=0.1W=0.1a=0.06l=0.05w=0.01l1=0.04w1=0.02fl=0.015fw=0.0075fww=0.006X=!铁芯离开绕阻气隙(X1=！铁芯上下气隙）(X2=！铁芯离开原位置位移)rectng,0,a,0,arectng,w,l,w,lrectng,w1,l1,w1,l1rectng,l1+X,l1+fl+X,w1+fw,l1-fw(rectng,l1+0.001,l1+fl,w1+fww+X1,l1-fww-X1)(rectng,l1+0.001,l1+fl,w1+fw+X2,l1-fw+X2)rectng,l1,l,w1+fww,l1-fwwALLSEL,ALLAOVLAP,ALLAADD,7,6AADD,9,11asel,s,area,,10aatt,1,,1esize,0.0005amesh,allasel,s,area,,1aatt,1,,1esize,0.0005amesh,allasel,s,area,,2aatt,2,,1esize,0.0005amesh,allasel,s,area,,8aatt,3,,1esize,0.0005amesh,alldl,4,2,asymdl,3,2,asymdl,2,2,asymdl,1,2,asymasel,s,,,1esla,scm,am,elemfmagbc,'am'allsel,allfinish/soluasel,s,area,,8bfa,all,js,,,4e6,0magsolvfinish实验一X0.00010.0010.0020.0030.0040.0050.0060.0070.0080.009forcex1-1.58E+02-2.42E+02-2.76E+02-2.96E+02-3.03E+02-3.09E+02-3.08E+02-3.08E+02-3.10E+02-2.99E+02forcey1-8.93E-0.1-8.79E+009.35E+007.43E+008.44E+008.34E-027.21E+00-1.07E+008.26E+007.35E+00F1理论分析：水平受力其实是两端磁场线相互作用的结果，方向为负，所以F1大于F2，当铁芯外移，左侧磁通量减少，故合力=F1-F2，增大。F1铁芯F2铁芯F2实验二X10.00010.00040.00080.00120.00160.002forceX-8.65E+03-1.58E+03-6.41E+02-3.50E+02-2.13E+02-1.35E+02forceY9.63E+01-5.41E+011.16E+01-1.95E+00-2.97E+002.72E+00理论分析：从图中看出，当气隙越小，漏磁越少，而根据F=B^2*S/(2*μ)，所以横轴受力越大，而垂直受力由于两端的作用力抵消，大小基本不变。实验三X20.0010.00070.00040.00010-0.0001-0.0004-0.0007-0.001forceX-2.49E+02-2.42E+02-2.41E+02-2.38E+02-2.38E+02-2.41E+02-2.36E+02-2.46E+02-2.45E+02forceY8.23E+024.83E+022.50E+025.74E+01-5.76E-01-6.06E+01-2.61E+02-4.83E+02-8.07E+02理论