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九年级数学中考二模A卷请保持卷面整洁,答题步骤清楚。2026届九年级数学中考二模A卷模拟试卷(含答案详解与评分标准)学校:________________班级:____________姓名:____________考号:________________考试时间:120分钟满分:120分题型选择题填空题解答题总分分值24分18分78分120分注意事项1.本卷共24题,分选择题、填空题和解答题三部分。请在规定时间内完成全卷。2.答题前请将学校、班级、姓名、考号填写清楚。选择题请把选项填入答题表。3.计算题应写出主要过程;几何证明应写明依据;结果能化简的应化简。4.作图可先用铅笔,确定后加深;不得在题目旁写与答案无关的内容。选择题答题表题号12345678答案一、选择题(本大题共8小题,每小题3分,共24分)1.(3分)计算|−3|+(−2)²的结果是()A.1B.5C.7D.−12.(3分)把0.00035用科学记数法表示为()A.3.5×10⁻³B.35×10⁻⁵C.3.5×10⁻⁴D.35×10⁻⁴3.(3分)多项式x²−5x+6分解因式正确的是()A.(x−2)(x−3)B.(x+2)(x−3)C.(x−1)(x−6)D.(x+2)(x+3)4.(3分)一个不透明袋中有3个红球、2个黄球、5个蓝球,这些球除颜色外完全相同。从中任取1个球,取到的球不是蓝球的概率是()A.1/5B.1/2C.3/5D.2/55.(3分)点在一次函数y=−2x+3的图象上的是()A.(0,−3)B.(1,1)C.(2,1)D.(−1,−1)6.(3分)菱形的两条对角线长分别为8cm和6cm,则这个菱形的面积是()A.14cm²B.20cm²C.24cm²D.48cm²7.(3分)若关于x的一元二次方程x²+2x+k=0有实数根,则k的取值范围是()A.k≤1B.k<1C.k≥1D.k>18.(3分)一个圆锥的底面半径为3cm,母线长为5cm,则它的侧面积是()A.8πcm²B.12πcm²C.10πcm²D.15πcm²二、填空题(本大题共6小题,每小题3分,共18分)9.(3分)计算:√18−√8=__________。10.(3分)方程(x−2)/3=(x+1)/5的解为x=__________。11.(3分)若一元二次方程x²−4x+m=0有两个相等的实数根,则m=__________。12.(3分)一组数据7,9,9,10,12,14的众数是__________。13.(3分)正六边形的一个外角的度数是__________。14.(3分)半径为4cm、圆心角为90°的扇形面积是__________cm²。三、解答题(本大题共10小题,共78分)15.(6分)先化简,再求值:〔x/(x−2)²−1/(x−2)〕÷〔2/(x−2)〕,其中x=4。作答:________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________16.(6分)解不等式组:2x−1≤5,(x+3)/2>1,并写出它的所有整数解。作答:________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________17.(6分)某校九年级进行一分钟跳绳抽测,随机抽取50名学生,成绩分组和人数如下表。成绩x(次)120≤x<140140≤x<160160≤x<180180≤x<200人数816188(1)求样本中成绩不低于160次的学生所占百分比;(2)若全校九年级共有600名学生,估计成绩不低于160次的学生人数。作答:________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________18.(6分)某地出租车收费标准为:3千米以内收费10元;超过3千米的部分,每千米收费2.4元。设行驶路程为x千米(x>3),车费为y元。求:(1)y关于x的函数表达式;(2)行驶8千米应付多少元;(3)若一次乘车付费34元,行驶路程是多少千米。作答:________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________19.(8分)在△ABC中,AB=AC,点D、E在BC上,且BD=CE。求证:(1)AD=AE;(2)∠BAD=∠CAE。作答:________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________20.(8分)已知:P为⊙O外一点,PA、PB分别与⊙O相切于A、B两点,OP=10cm,⊙O半径为6cm。求:(1)切线长PA;(2)四边形PAOB的面积。作答:________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________21.(8分)已知二次函数y=x²−4x+3。求:(1)图象的顶点坐标和对称轴;(2)图象与x轴的交点坐标;(3)当y≤0时,x的取值范围。作答:________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________22.(8分)同一时刻,直立木杆高1.5m,影长2m;教学楼的影长为18m。(1)求教学楼的高度;(2)若在教学楼顶安装一根旗杆后,总影长变为22m,求旗杆的高度。作答:________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________23.(11分)在平面直角坐标系中,矩形ABCD的顶点为A(0,0),B(8,0),C(8,6),D(0,6)。点P从A出发沿AB向B运动,点Q从B出发沿BC向C运动,二者同时出发,速度均为1个单位/秒,运动时间为t秒(0≤t≤6)。(1)写出P、Q两点的坐标;(2)求△DPQ的面积S与t的函数关系式;(3)求S的最小值及对应的t值;(4)当S=24时,求t的值。作答:________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________24.(11分)某文创店销售纪念笔,单件进价为10元。市场调查显示:售价为20元/件时,每天可售80件;售价每提高1元,每天少售4件。设售价为x元/件(20≤x≤35),日销售量为q件,日利润为W元。(1)写出q关于x的函数表达式;(2)写出W关于x的函数表达式;(3)售价为多少元时日利润最大?最大日利润是多少元?(4)若计划日利润不低于864元,求售价x的取值范围。作答:_______________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________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参考答案与解析评分说明:本卷满分120分。选择题每题3分,只有一个正确选项;填空题每题3分,结果等价且化简正确可得满分;解答题按关键过程、计算结果和书写结论分步给分。解答题中,若使用与参考解法不同但推理正确的方法,应按相同知识点和关键结论给分;若前一步计算错误但后续方法正确,可按实际完成的有效过程给相应过程分。板块题号范围分值主要考查内容选择题1—824分数与式、概率、函数、几何基础填空题9—1418分二次根式、方程、统计、几何量解答题15—2478分运算、证明、函数、相似、综合应用题号分值评分重点156分分式通分、除法转化、约分、代入求值166分两个不等式分别求解,公共解集和整数解完整176分读表求人数,计算百分比,用样本估计总体186分根据分段收费建立一次函数,代入和反解均需写过程198分利用等腰三角形底角相等,判定三角形全等并推出结论208分切线垂直半径,勾股定理求切线长,面积分割计算218分配方法求顶点,因式分解求交点,结合图象判断范围228分同一时刻物高与影长成比例,两次比例计算要区分总高度2311分建立坐标,列面积函数,配方求最值,解方程并检验范围2411分建立销售量和利润函数,配方求最大值,解利润不等式一、选择题答案与解析题号12345678答案CCABBCAD1.|−3|表示−3到0的距离,值为3;(−2)²=4,两个结果相加为7。其余选项未同时满足绝对值和乘方运算规则,选C。评分:选C得3分。2.科学记数法要求写成a×10ⁿ,且1≤a<10。0.00035的小数点向右移动4位得到3.5,因此指数为−4,故0.00035=3.5×10⁻⁴,选C。评分:选C得3分。3.二次项系数为1,常数项为6,一次项系数为−5。寻找两个数2和3,其积为6、和为5,所以x²−5x+6=(x−2)(x−3),选A。评分:选A得3分。4.随机取1个球时,每个球被取到的可能性相同。不是蓝球包含红球和黄球,共3+2=5个,总球数为10个,概率为5/10=1/2,选B。评分:选B得3分。5.判断点是否在函数图象上,只需检验横坐标代入后所得纵坐标是否一致。把x=1代入y=−2x+3,得y=1,故(1,1)在图象上,选B。评分:选B得3分。6.菱形的两条对角线互相垂直,面积等于两条对角线乘积的一半。故S=8×6÷2=24cm²,选C。评分:选C得3分。7.一元二次方程有实数根的条件是判别式Δ≥0。本题中Δ=2²−4×1×k=4−4k,令4−4k≥0,得k≤1,选A。评分:选A得3分。8.圆锥侧面展开后是扇形,其面积公式可写为S=πrl,其中r为底面半径,l为母线长。代入r=3,l=5,得S=15πcm²,选D。评分:选D得3分。二、填空题答案与解析9.答案:√2。解析:√18−√8=3√2−2√2=√2。评分:填√2得3分。10.答案:13/2。解析:5(x−2)=3(x+1),5x−10=3x+3,2x=13,x=13/2。评分:结果正确得3分。11.答案:4。解析:两个相等实数根时Δ=0,(−4)²−4m=0,m=4。评分:结果正确得3分。12.答案:9。解析:数据中9出现2次,其他数各出现1次,众数为9。评分:结果正确得3分。13.答案:60°。解析:正n边形的一个外角为360°/n,正六边形外角为360°/6=60°。评分:结果正确得3分。14.答案:4π。解析:扇形面积S=(90/360)×π×4²=4πcm²。评分:结果正确得3分。三、解答题答案详解与评分标准15.解:〔x/(x−2)²−1/(x−2)〕÷〔2/(x−2)〕=〔x/(x−2)²−(x−2)/(x−2)²〕×(x−2)/2=〔2/(x−2)²〕×(x−2)/2=1/(x−2)。当x=4时,原式=1/(4−2)=1/2。给定的x=4满足x≠2,代入有效。评分标准:通分正确得2分;把除法转化为乘法并约分正确得2分;代入x=4求值得1分;写出最终结论得1分。若未注明x≠2但化简过程正确,不扣过程分。16.解:由2x−1≤5,得2x≤6,x≤3。由(x+3)/2>1,得x+3>2,x>−1。所以不等式组的解集为−1<x≤3。若用数轴表示,−1处为空心点,3处为实心点,中间部分为公共解。整数解为0,1,2,3。评分标准:分别求出两个不等式的解各得
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