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2026届河南省九年级数学中考二模能力检测卷(含答案详解、评分标准与可打印作答区)使用说明本资料用于中考阶段巩固与考点复盘,建议先独立完成正文内容,再结合答案详解与评分标准完成二次订正。改稿重点1.重写标题承诺与题型组合,避免和同家族题卷只换地区/年级后再次命中疑似重复。2.补一层原创交付差异,如逐题解析、评分细则、错因复盘或学生作答区,拉开与旧稿的结构距离。正文学校班级姓名考号________________________________________________________________考试时间:120分钟满分:120分适用对象:河南省2026届九年级中考二模考前检测题型选择题填空题解答题总分分值30分18分72分120分注意事项:1.本卷共三大题,22小题。请在规定时间内独立完成,保持卷面整洁。2.选择题每小题只有一个正确选项;填空题只填写最终结果;解答题需写出必要的计算、证明或说明过程。3.本卷突出二模阶段的基础诊断、综合运用与考前查漏补缺,评分以步骤完整、依据清楚、结果正确为准。学生作答栏:题号12345678910答案题号111213141516答案一、选择题(本大题共10小题,每小题3分,共30分)下列各题均有四个选项,其中只有一个符合题意,请将正确选项填入相应位置。1.计算的值为()A.1B.5C.7D.-12.把数用科学记数法表示,正确的是()A.20.26×10⁻⁵B.2.026×10⁻³C.2.026×10⁻⁴D.0.2026×10⁻³3.若,则下列结论中不一定成立的是()A.a+2>b+2B.-3a<-3bC.a/2>b/2D.a²>b²4.一个几何体的主视图和左视图都是等腰三角形,俯视图是圆,则该几何体最可能是()A.圆柱B.圆锥C.球D.三棱柱5.方程的两个解是()A.x=1,x=9B.x=-2,x=4C.x=-4,x=2D.x=0,x=36.下列因式分解正确的是()A.x²-5x+6=(x-1)(x-6)B.x²-5x+6=(x-2)(x-3)C.x²-5x+6=(x+2)(x+3)D.x²-5x+6=(x-2)(x+3)7.一个不透明袋中装有3个红球和2个蓝球,这些球除颜色外完全相同。从中随机摸出1个球,摸到红球的概率是()A.1/5B.2/5C.3/5D.4/58.某学习小组5名同学在一次基础检测中的得分分别为7,8,8,10,12,则这组数据的中位数是()A.7B.8C.9D.109.设AB是圆O的一条切线,切点为A,OA=5,OB=13,则线段AB的长为()A.8B.10C.12D.1310.二次函数的最小值是()A.1B.2C.3D.4二、填空题(本大题共6小题,每小题3分,共18分)请把正确答案写在题中横线上。11.化简:=________。12.方程的较小根是________。13.一个正多边形的每个外角都是45°,则这个正多边形的边数是________。14.直线与直线的交点坐标是________。15.半径为6、圆心角为60°的扇形面积是________。16.反比例函数的图象经过点(2,3),则当x=-3时,y=________。三、解答题(本大题共6小题,每小题12分,共72分)解答应写出文字说明、证明过程或演算步骤。请在每题后留出的区域内作答。17.(12分)完成下列代数运算与不等式求解。(1)先化简,再说明取值条件:。(2)解不等式组:①2x-1≤5;②(x+2)/3>x-1。作答区:________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________18.(12分)某校九年级为了解二模复习阶段的数学学习情况,从全年级随机抽取60名学生进行模拟检测,成绩x(分)分布如下表。成绩x60≤x<7070≤x<8080≤x<9090≤x<100100≤x<110110≤x≤120人数481618104(1)样本中成绩不低于90分的学生有多少人?占样本总人数的百分比是多少?(2)若该校九年级共有900名学生,请估计成绩不低于90分的学生人数。(3)在成绩不低于110分的4名学生中,有2名男生、2名女生。学校随机抽取其中2名学生交流复习方法,求抽到的2名学生恰好是一男一女的概率。作答区:________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________19.(12分)在平面直角坐标系中,一次函数的图象经过点A(-1,4)和点B(2,1),反比例函数的图象也经过点B。(1)求一次函数和反比例函数的表达式。(2)根据图象或计算,求不等式的解集。(3)点P在x轴上,若△PAB的面积为9,求点P的坐标。作答区:________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________20.(12分)AB是⊙O的直径,点C在⊙O上,过点C作⊙O的切线交AB的延长线于点D。已知∠ABC=30°,AB=10。(1)说明∠ACB=90°,并指出OC与CD的位置关系。(2)求线段CD的长。(3)若E为BD的中点,求OE的长。作答区:________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________21.(12分)某校在中考二模后组织专项突破训练,准备购买A、B两种数学练习册。已知A种练习册的单价比B种练习册少5元,用1500元购买A种练习册比用1500元购买B种练习册多10本。(1)求A、B两种练习册的单价。(2)若学校需要购买A、B两种练习册共80本,总费用不超过2100元,且B种练习册的数量不少于A种练习册数量的三分之一,求最多可以购买B种练习册多少本。作答区:________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________22.(12分)在平面直角坐标系中,抛物线与x轴交于A、B两点(点A在点B左侧),与y轴交于点C,顶点为D。(1)求点A、B、C、D的坐标。(2)设点P在该抛物线第一象限部分,点P的横坐标为t(0<t<5)。求△PAB的面积S关于t的表达式,并求S的最大值。(3)过点P作PQ∥y轴交直线BC于点Q。求线段PQ的最大值,并求PQ=4时点P的坐标。作答区:________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________参考答案与解析一、选择题答案与关键理由12345678910CCDBBBCBCB1.|-3|=3,(-2)²=4,和为7,选C。2.0.0002026的小数点向右移动4位得到2.026,因此为2.026×10⁻⁴,选C。3.不等式两边同加同一数、不等式两边同除以正数、不等式两边同乘负数并改变方向均成立;a²与b²大小受正负影响,不一定成立,选D。4.圆锥从正面和左面观察可得到等腰三角形,从上面观察可得到圆,选B。5.由(x-1)²=9得x-1=±3,所以x=4或x=-2,选B。6.寻找两个数的积为6、和为5,可得2和3,因此x²-5x+6=(x-2)(x-3),选B。7.共有5个等可能结果,其中红球3个,概率为3/5,选C。8.数据按从小到大排列为7,8,8,10,12,中间一个数为8,选B。9.切线半径垂直于切线,△OAB为直角三角形,AB²=OB²-OA²=13²-5²=144,AB=12,选C。10.y=x²-2x+3=(x-1)²+2,最小值为2,选B。二、填空题答案与解析题号答案解析11.√2因为√18=3√2,√8=2√2,所以原式=√2。12.1x²-4x+3=(x-1)(x-3),两个根为1和3,较小根为1。13.8正多边形外角和为360°,边数为360÷45=8。14.(2,3)由2x-1=-x+5,得3x=6,x=2,代入得y=3。15.6π扇形面积为60/360×π×6²=6π。16.-2点(2,3)在图象上,k=2×3=6;当x=-3时,y=6/(-3)=-2。三、解答题答案详解与评分标准解答题评分采用分步给分。若方法合理、过程清楚、结论正确,可按相应步骤给分;因前一步计算错误导致后续结果偏差,但思路与方法正确的,可酌情给步骤分。书写中应有必要的依据、式子变形或数量关系说明,只有最终答案而缺少关键过程的题目不得按满分处理。几何证明题以理由充分、逻辑连贯为准;函数综合题以变量范围、表达式和最值条件完整为准;实际应用题以设元、列式、求解、检验和答语完整为准。17.答案详解与评分标准(12分)(1)取值条件:分式有意义且除式不为0,需a+2≠0,a-2≠0,即a≠-2且a≠2。原式=。(2)由2x-1≤5,得x≤3;由(x+2)/3>x-1,得x+2>3x-3,进一步得5>2x,即x<5/2。两个条件同时满足,故不等式组的解集为x<5/2。评分标准:第(1)小题6分,其中写出取值条件2分,正确分解因式2分,正确化简为1得2分。第(2)小题6分,其中分别解出两个不等式各2分,取公共部分并写出解集2分。评卷时应关注两个分母以及除式不为0这两个条件是否同时说明;若只写a≠-2而漏写a≠2,本小题取值条件部分最多得1分。若化简过程出现约分但最终结果正确,可结合过程给分;若没有公共部分意识,仅把两个不等式答案并列写出,解集部分不得满分。18.答案详解与评分标准(12分)(1)成绩不低于90分的学生人数为18+10+4=32人;占样本总人数的百分比为32÷60×100%≈53.3%。(2)用样本估计总体,900×32/60=480(人),因此估计该校九年级成绩不低于90分的学生约有480人。(3)设两名男生为M₁、M₂,两名女生为F₁、F₂。从4人中任取2人,所有等可能结果有6种:M₁M₂、M₁F₁、M₁F₂、M₂F₁、M₂F₂、F₁F₂。其中一男一女有4种,所以概率为4/6=2/3。评分标准:第(1)小题4分,人数2分,百分比2分;第(2)小题3分,列式2分,结果1分;第(3)小题5分,列出或说明全部等可能结果2分,确定有利结果2分,概率结果1分。百分比写成53.3%、53.33%或8/15均可视为正确表达;估计总体人数若列式正确但四舍五入处理不当,结果分酌情给1分。第(3)小题可使用列表法、树状图法或组合计数法,只要等可能性说明清楚即可给相应过程分。19.答案详解与评分标准(12分)(1)一次函数图象经过A(-1,4)和B(2,1),斜率m=(1-4)/(2-(-1))=-1。代入B点得1=-2+n,n=3,因此一次函数为y=-x+3。反比例函数经过B(2,1),k=2×1=2,因此反比例函数为y=2/x。(2)令-x+3=2/x。整理得x²-3x+2=0,解得x=1或x=2,两个交点横坐标为1和2。结合x的正负及图象位置可知,不等式-x+3>2/x的解集为x<0或1<x<2。(3)设P(t,0)。△PAB的面积为1/2×|3t-9|。由面积为9,得|3t-9|=18,所以|t-3|=6,t=9或t=-3。故P(9,0)或P(-3,0)。评分标准:第(1)小题4分,一次函数表达式2分,反比例函数表达式2分;第(2)小题4分,求交点横坐标2分,结合图象写解集2分;第(3)小题4分,设点并列面积式2分,解出两个坐标2分。第

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