浙江2026-2027学年高二上学期10月四校联考信息技术试卷

（501-3A.49+1=50B.101101C.41D.n16n44.1kHz161量为5MBmp3A. B. C. D.7c3，则输入aPython

7z0,1,2n=int(input())ifn<=20:z=0ifn<=50:z=1z=2A. B. D.pyhonforiins:if a=[3,5,9,6,7,2,b=[1,9,3,4,8,6,flag=Trueans=[]foriinrange(6,-1,-1):ifflaganda[i]<b[i]:flag=Falseelifa[i]>b[i]:A．[2,4,6,2,1,4, B．[6,2,6,C．[2,4,6, D．[6,4,1,6,4,jm(password)用来对加密字符进行解密，代码如下：defjm(password):key={"b":"d","d":"a","a":"c","c":i=whilei<len(password)-ifi>=0andkey[password[i]]==password[i+1]:password=password[:i]+password[i+1:]i-=i+=return 非选择题（3138148151026补链为“CGACTPythonRNAAUUGUC”的互补链是▲cpldefcpl(sequ,type):dicDNA={"A":"T","T":"A","G":"C","C":dicRNA={"A":"U","U":"A","G":"C","C":forntin iftype==ans=dicDNA[nt]+anseliftype=="RNA":ans=dicRNA[nt]+ansreturnans#datadata[["ACGTAGDNA""GCUAGGRNA"]]代码略forseqindata:sequ,type=seq[0],seq[1]comp= print(typesequ14b 请在①处选择选择合适的选项（多选） （注：全部选对的得2分，选对但不全的得0 请在②处填入合适的代码 importpandasasimportmatplotlib.pyplotas plt.rc('font',**{'family': df["班级"]=0#在最后一列增加"班级"列，该列值均为0foriin 为▲（多选，填字母）。（21选错的得0分）importmatplotlib.pyplotaspltmatplotlibplt.rc('font',**{'family':(3)若要筛选出某班学生，以方便了解该班投票情况,请在④处合适的代码▲ Pythonhw[1411,8,5,2120，则最少需要▲defread_f():a=[]#读取"gj.txtaa=[17,13,12,11,...],代码略defisum(x):t=foriin returnvol20hw=read_f() hw_num=[0]*(vol+1)fornuminhw_num[num]= v=vols=0whileifhw_num[v]==0ors==0:v=v-1or(v==or(v==sandhw_num[v]==elifhw_num[s]==0orv+s> s=s-1hw_num[v]-=hw_num[s]-=1hw_num[v+s]+=1 s=vol-print若省略加框处代码，货车体积vol为20，则下列工件体积数据中，能检查出该程序错误的有▲ A.[7,12,3,8,17,7, B.[10,7,8,7,8,,10,C.[10,10,5,14,11, D.[13