河南濮阳市南乐县2025-2026学年第一学期期中学情调研试卷

12025--2026学年度第一学期期中学情调研试卷一年级数学检测时间：40分钟 满分:100分+10分题序一二三四五六附加题总分等级得分EQ\*jc0\*hps14\o(\s\up13(kàn),看)EQ\*jc0\*hps14\o(\s\up13(kàn),清)EQ\*jc0\*hps14\o(\s\up13(qīng),题目)EQ\*jc0\*hps14\o(\s\up13(tí),)EQ\*jc0\*hps14\o(\s\up13(mù),),EQ\*jc0\*hps14\o(\s\up13(wǒ),我)EQ\*jc0\*hps14\o(\s\up13(huì),会)EQ\*jc0\*hps14\o(\s\up13(suàn),算)。(20分)1+2= 2+3= 1-1= 4-2=2-0= 0+3= 2+1= 4-0=3+1= 5-3= 2+2= 3-3=5-1= 1+1= 4-3= 1+4=0+1= 5-4= 4+0= 3-2=EQ\*jc0\*hps14\o(\s\up13(kāi),开)EQ\*jc0\*hps14\o(\s\up13(dòng),动)EQ\*jc0\*hps14\o(\s\up13(nǎo),脑)EQ\*jc0\*hps14\o(\s\up13(jīn),筋)，EQ\*jc0\*hps14\o(\s\up13(wǒ),我)EQ\*jc0\*hps14\o(\s\up13(huì),会)EQ\*jc0\*hps14\o(\s\up13(tián),填)。(每空1分，共32分)1.(教材改编)数一数，填一填。每次多()个。(2)每次少()个。22.在○里填上“>”“<”或“=”。1+3○2 3○5-2 2-2○1 2○0+43-1○2 0+2○2 6○4+1 3+2○73.在○里填上“+”或“-”。5○1=4 0○3=3 2○3=5 2○1=14.(名校期末真题)数字花。5.相加得() 相加得() 相加得()相减得()相减得()相减得()三EQ\*jc0\*hps14\o(\s\up13(yòng),用)EQ\*jc0\*hps14\o(\s\up13(xīn),心)EQ\*jc0\*hps14\o(\s\up13(fēn),分)EQ\*jc0\*hps14\o(\s\up13(xi),析)，EQ\*jc0\*hps14\o(\s\up13(wǒ),我)EQ\*jc0\*hps14\o(\s\up13(huì),会)EQ\*jc0\*hps14\o(\s\up13(xuǎn),选)。(填序号)(每题2分，共6分)1.(名校期末真题)拨到5，还需要拨()个珠子。①1 ②2 ③32.下面不能与用同一个算式表示的是()。3.在□+1>4中,□里最小可以填()。①5 ②4 ③33四EQ\*jc0\*hps14\o(\s\up13(àn),按)EQ\*jc0\*hps14\o(\s\up13(yāo),要)EQ\*jc0\*hps14\o(\s\up13(qiú),求)EQ\*jc0\*hps14\o(\s\up13(zuò),做)EQ\*jc0\*hps14\o(\s\up13(yì),一)EQ\*jc0\*hps14\o(\s\up13(zuò),做)。(每题4分，共12分)1.树叶上原来有()只蚂蚁，又来了()只，一共有多少只蚂蚁?□○□=□读作:。2.荷叶上原来有()只青蛙，有()只跳进水里了，荷叶上还剩多少只青蛙?□○□=□读作:。3.(名校期末真题)画图表示算式的含义并写出得数。3+1=□ 3-2=□五EQ\*jc0\*hps14\o(\s\up13(kàn),看)EQ\*jc0\*hps14\o(\s\up13(tú),图)EQ\*jc0\*hps14\o(\s\up13(liè),列)EQ\*jc0\*hps14\o(\s\up13(shì),式)EQ\*jc0\*hps14\o(\s\up13(jì),计)EQ\*jc0\*hps14\o(\s\up13(suàn),算)。(6分)1. 2.□+□=□ □-□=□ □-□=□六EQ\*jc0\*hps14\o(\s\up13(jiě),解)EQ\*jc0\*hps14\o(\s\up13(jué),决)EQ\*jc0\*hps14\o(\s\up13(wèn),问)EQ\*jc0\*hps14\o(\s\up13(tí),题)。(24分)1.一共舞了几头狮子?(4分)□○□=□2.(新趋势·学科融合)毛毛虫去哪儿了?原来是变成蝴蝶飞走啦！还剩几只毛毛虫?(8分)(1)(2) □○□=□□○□=□3.每只小动物分1盒，还差几盒?(4分)□○□=□(新情境·传统文化)剪纸——一刀一剪的中国式浪漫。(8分)(1)王阿姨一共剪了几张剪纸?(2)李阿姨剪了几张福字?□○□=□ □○□=□EQ\*jc0\*hps14\o(\s\up13(fù),附)EQ\*jc0