C语言程序改错练习题 计算正整数各位数字之积 含答案题库

答案：c答案：B答案：54321答案：B答案：123答案:3答案：A答案：A答案：B答案：D答案：789]答案：312答案：A答案：C答案：26答案：57答案：double/*------------------------------------------------------【程序改错】--------------------------------------------------------功能：计算正整数num的各位上的数字之积。例如：输入252，则输出应该是20。------------------------------------------------------*/#include<stdio.h>longfun(longnum){/**********FOUND**********/longk;do{k*=num%10;/**********FOUND**********/num\=10;}while(num);returnk;}voidmain(){longn;printf("Pleaseenteranumber:\n");/**********FOUND**********/scanf("%ld",n);/**********FOUND**********/printf("%ld\n",fun(longn));}/*------------------------------------------------【程序设计】--------------------------------------------------功能：给定n个数据,求最小值的下标（如果最小值出现多次,求出第一次出现的位置即可）。------------------------------------------------*/#include<stdio.h>voidwwjt();intstation(ints[],intn){/**********Program**********//**********End**********/}main(){inta[100],n,i,t;scanf("%d",&n);for(i=0;i<n;i++)scanf("%d",&a[i]);t=station(a,n);printf("themin_valuepositionis:%d\n",t);wwjt();}voidwwjt(){FILE*IN,*OUT;intn;inti[10];into;IN=fopen("in.dat","r");if(IN==NULL){printf("ReadFILEError");}OUT=fopen("out.dat","w");if(OUT==NULL){printf("WriteFILEError");}for(n=0;n<10;n++){fscanf(IN,"%d",&i[n]);}o=station(i,10);fprintf(OUT,"%d\n",o);fclose(IN);fclose(OUT);}/*------------------------------------------------【程序设计】--------------------------------------------------功能：从键盘输入一个大于3的整数，调用函数fun判断其是否素数，然后在main函数中输出相应的结论信息。例如：7saprime.8isnotaprime.请编写fun函数。素数是仅能被1和自身整除的数-------------------------------------------------*/#include<stdio.h>voidwwjt();intfun(intn){/**********Program**********//**********End**********/}main(){intm,flag;printf("inputaninteger:");scanf("%d",&m);flag=fun(m);if(flag)printf("%disaprime.\n",m);elseprintf("%disnotaprime.\n",m);wwjt();}voidwwjt(){FILE*IN,*OUT;intiIN,iOUT,i;IN=fopen("5.IN","r");if(IN==NULL){printf("PleaseVerifyTheCurrerntDir..itMayBeChanged");}OUT=fopen("5.out","w");if(OUT==NULL){printf("PleaseVerifyTheCurrentDir..itMayBeChanged");}for(i=0;i<10;i++