版权说明:本文档由用户提供并上传,收益归属内容提供方,若内容存在侵权,请进行举报或认领
文档简介
1、8B/10B Coding 64B/66B Coding,Transmission Systems 8B/10B Coding 64B/66B Coding CIP Demonstrator Test Setup,Transmission system General,Clock,Data, 1 Gbps = 1 ns = 20 cm,Transmission system Propagation Delay,Clock,Data,Unequal propagation delay 10 cm 1 Gbps,Transmission system Clock Data Recovery,Clo
2、ck,Data,CDR,If there are enough edges in the data then the clock can be recovered from the data using a PLL,PLL,PLL,Combine Clock and Data!,Code Properties,Provide enough edges in the data to enable Clock Recovery,Transmission system Receiver Threshold,Clock,Data,CDR,Receiver Threshold refers to “Gr
3、ound” which must be the same potential as “Ground” at the transmitter!,Jitter!,Use Differential signalling!,Transmission,Clock,Data,CDR,Receiver Threshold is halfway positive and negative signal,Common mode voltage difference between transmitter and termination at the receiver can result in excessiv
4、e currents,Icm,Use AC Coupling Capacitors Need DC Balance!,1,DC Balance,1,0,1,0,1,1,0,1,0,1,1,1,1,1,1,1,1,?,0,Define a maximum Run Length Sent equal amount of 1s and 0s (Running Disparity),Receiver Automatic Gain Control,Gain,Time,Gain,Time,Again: maximum Run Length,Code Properties,Provide enough ed
5、ges in the data to enable Clock Recovery Maximum Run Length and DC Balance,History of 8B/10B coding,8B/10B coding,Maximum run length = 5 Running Disparity = DC Balance 8 bits = 256 different values 10 bits = 1024 different values 8B10B code is built out of: (5 to 6 bit code) + (3 to 4 bit code),8B/1
6、0B coding,Not all 1024 values are useful. For example “0100000011” has run length 6 For most of the 256 (8B) values a positive and a negative 10B value is selected depending on the “Current Running Disparity” For example: D7.0 = 1110001011 (Current RD-) D7.0 = 0001110100 (Current RD+) So about 512 u
7、seful values are selected from 1024 There are still a few codes left!,8B/10B coding table,256 “Data” Characters:,8B/10B coding table,There were still a few codes left! 12 “Special” K Characters:,Comma Characters “The only patterns that have 5 consecutive 1s or 0s,010101001101100111000001010110111010
8、010100100111010011001001110100111001,8B/10B code “K” Characters,Comma characters K28.1/K28.5/K28.7 are used word alignment,010101001101100111000001010110111010010100100111010011001001110100111001,D31.3,D11.3,D0.0,K28.5,D16.2,Create “ordered sets” For example Fibre Channel Start Of Frame (SOF) = K28.
9、5/D21.5/D23.0/D23.0 K30.7 = Error Propagate K28.3 = Carrier Extend,?.?,8B/10B code properties,Provide enough edges in the data to enable Clock Recovery Maximum Run Length and DC Balance Add special characters Comma for word alignment Control characters,64B/66B Coding,64B/66B (IEEE std 802.3ae-2002,
10、Clause 49),20% of the bandwidth for 8B/10B is overhead For 64B/66B overhead is 3%,2 bit Sync Header,64 bit (Scrambled),2 bit Sync Header 00 Code Error 01 64 bit = Data field 10 64 bit = Mixed Data / Control field 11 Code Error,Once every 66 bits there is at least a “01” or a “10” transition = Receiv
11、er Block Sync (it may take a while),64B/66B Scrambler,Scrambler: X58+X39+1 Tries to mix up the data to avoid long sequences of 1s and 0s Note: there is no guarantee that on a bad day the output of the scrambler produces all 0s or all 1s,1,0,D0:8,D1:8,D2:8,D3:8,D4:8,D5:8,D6:8,D7:8,64B/66B,0,1,64 bit
12、Data Field (Scrambled),Typ:8,Z0:7,Z1:7,Z2:7,Z3:7,Z4:7,Z5:7,Z6:7,1,0,64 bit Mixed Control /Data Field (Scrambled),Z7:7,Pure Control (Type = 0 x1E),Typ:8,1,0,Mixed Control/Data (Type = 0 x87; T0),Typ:8,Z2:7,Z3:7,Z4:7,Z5:7,Z6:7,Z7:7,1,0,Typ:8,Z3:7,Z4:7,Z5:7,Z6:7,1,0,Z7:7,Typ:8,Z4:7,Z5:7,Z6:7,1,0,Z7:7,T
13、yp:8,Z5:7,Z6:7,1,0,Z7:7,Typ:8,Z6:7,Z7:7,7,Z1:7,Z2:7,Z3:7,Z4:7,Z5:7,Z6:7,Z7:7,6,D0:8,D0:8,D1:8,5,D0:8,D1:8,D2:8,4,D0:8,D1:8,D2:8,D3:8,3,D0:8,D1:8,D2:8,D3:8,D4:8,2,Total of 15 Mixed Control /Data Field is defined,Mixed Control/Data (Type = 0 x99 ; T1),Mixed Control/Data (Type = 0 xaa ; T2),Mixed Contr
14、ol/Data (Type = 0 xb4 ; T3),Mixed Control/Data (Type = 0 xcc ; T4),Mixed Control/Data (Type = 0 xd2 ; T5),etc.,Pure Data,2 bit Sync Header,64 bit (Scrambled),64B/66B Example,0,1,Z5,Z6,Z7,D0,D1,D2,D3,D4,D5,D6,D7,T,1,0,D0,D1,D2,Z4,Z5,Z6,Z7,Transmitting a sequence of 18 bytes could look like:,T,1,0,D1,
15、D2,D3,D4,D5,D6,D7,0 x78: S0 Start,0 xB4: T3 Terminate,Pure Data Frame,64B/66B Physical Coding Sub layer (PCS) Transmit bit ordering,Tx_Data(0),Tx_Data(15),Gearbox Adapts between (4x16=) 64 bit width and 66 bit width frames,Comparison,CIP Demonstrator Test Setup,CIP Test Bed,Delay?,Tx 8B/10B Encoded,
16、Rx 8B/10B Encoded,CIP Demonstrator Test Setup,K28.5,D16.2,K23.7,Dx.y,IDLE,CharExt,Tx 8B/10B Encoded,K28.5,D16.2,K28.5,D16.2,IDLE,IDLE,K28.5,D16.2,K28.5,D16.2,IDLE,IDLE,K28.5,D16.2,K23.7,Dx.y,IDLE,CharExt,K28.5,D16.2,K28.5,D16.2,IDLE,IDLE,K28.5,D16.2,IDLE,K28.5,D16.2,IDLE,Start,Stop,Stanford Research,2 x 10 Km fiber 100 us 2 x 100 Km fiber 1 ms, 100 Hz,Rx 8B/10B Encoded,First Res
温馨提示
- 1. 本站所有资源如无特殊说明,都需要本地电脑安装OFFICE2007和PDF阅读器。图纸软件为CAD,CAXA,PROE,UG,SolidWorks等.压缩文件请下载最新的WinRAR软件解压。
- 2. 本站的文档不包含任何第三方提供的附件图纸等,如果需要附件,请联系上传者。文件的所有权益归上传用户所有。
- 3. 本站RAR压缩包中若带图纸,网页内容里面会有图纸预览,若没有图纸预览就没有图纸。
- 4. 未经权益所有人同意不得将文件中的内容挪作商业或盈利用途。
- 5. 人人文库网仅提供信息存储空间,仅对用户上传内容的表现方式做保护处理,对用户上传分享的文档内容本身不做任何修改或编辑,并不能对任何下载内容负责。
- 6. 下载文件中如有侵权或不适当内容,请与我们联系,我们立即纠正。
- 7. 本站不保证下载资源的准确性、安全性和完整性, 同时也不承担用户因使用这些下载资源对自己和他人造成任何形式的伤害或损失。
最新文档
- 2026届河北省石家庄市桥西区重点中学下学期初三生物第二次阶段检测试题考试试卷含解析
- 黑龙江省大庆市林甸县2026年初三第六次质量检查英语试题含解析
- 2026届山西省朔州市朔城区第四中学初三下学期六校(4月)联考英语试题试卷含解析
- 环保目标达成行动方案承诺书(3篇)
- 山西省太原市小店区志达中学2026届初三下学期第二次质量考评语文试题试卷含解析
- 公益活动按期开展切实履行承诺书8篇范文
- 财务数据分析模板企业经营决策支持
- 产品质量控制流程及抽样检测标准
- 企业人事招聘信息公告编制工具
- 产品说明书撰写标准模板提高信息传达效率
- 2026年江西电力职业技术学院单招职业技能考试题库带答案详解
- 2026年常州机电职业技术学院单招职业倾向性考试题库带答案详解(完整版)
- 2026年宁夏石嘴山市单招职业适应性考试题库附参考答案详解(综合卷)
- 幼儿园内部控制工作制度
- 眉山天府新区2026年上半年公开招聘专职网格管理员(77人)考试参考试题及答案解析
- 2026年复产复工安全生产部署专题会议纪要
- 出水井施工方案(3篇)
- 健康照护师操作测试考核试卷含答案
- 2026湖南省卫生健康委直属事业单位招聘185人考试参考试题及答案解析
- 航空航天及设备制造标准化操作规程手册
- 【2025年】裁剪工岗位职业技能资格考试联系题库-含答案
评论
0/150
提交评论