linux的shell脚本实验报告

1、第二次实验内容一、实验名称：Linux下shell编程二、实验类型：设计三、实验目的：1 熟悉Linux的shell几种变量使用2 熟练掌握Linux的shell编程几种结构3 熟练掌握Linux下shell脚本的编写四、实验准备参考教材，课件第7章内容及笔记。要求实验内容全部写到实验报告上（B5纸）。五、实验内容1. 练习使用shell四种变量，参考课件例题。用户自定义变量，环境变量，位置变量，特殊变量这四种变量类型的使用，书中有例题。2. 调试课件所有shell脚本的例题。3. 编写如下脚本：l 编写脚本if1，测试其功能。 echo -n word 1: read word1echo -

2、n word 2: read word2if test $word1 = $word2 then echo Matchfiecho End of program.l 编写脚本chkargs，测试其功能if test $# -eq 0 then echo You must supply at least one argument. exit 1fiecho Program running.l 编写脚本if2，测试其功能if test $# -eq 0 then echo You must supply at least one argument. exit 1fiif test -f $1 th

3、en echo $1 is a regular file in the working directory else echo $1 is NOT a regular file in the working directoryfil 编写脚本if3，测试其功能echo -n word 1: read word1echo -n word 2: read word2echo -n word 3: read word3if $word1 = $word2 -a $word2 = $word3 then echo Match: words 1, 2, & 3 elif $word1 = $word2

4、then echo Match: words 1 & 2 elif $word1 = $word3 then echo Match: words 1 & 3 elif $word2 = $word3 then echo Match: words 2 & 3 else echo No matchfil 编写smartzip 脚本，测试其功能#!/bin/bashftype=file $1case $ftype in$1: Zip archive*)unzip $1 ;$1: gzip compressed*)gunzip $1 ;$1: bzip2 compressed*)bunzip2 $1

5、;*) echo File $1 can not be uncompressed with smartzip;esacl 编写脚本dirfiles，测试其功能。for i in *do if -d $i then echo $i fidonel 编写脚本until1，测试其功能。用while改写之。secretname=jennyname=nonameecho Try to guess the secret name!echountil $name = $secretname /while改写位 while “$name” != “$secretname” ,其他地方不变do echo -n

6、Your guess: read namedoneecho Very good.l 编写脚本brk,测试其功能。for index in 1 2 3 4 5 6 7 8 9 10 do if $index -le 3 ; then echo continue continue fi# echo $index# if $index -ge 8 ; then echo break break fidonel 编写脚本command_menu，测试其功能。echo -e n COMMAND MENUnecho a. Current date and timeecho b. Users current

7、ly logged inecho c. Name of the working directoryecho -e d. Contents of the working directorynecho -n Enter a, b, c, or d: read answerechocase $answer in a) date; b) who; c) pwd; d) ls; *) echo There is no selection: $answer;esacl 编写脚本demo_shift，测试其功能。echo arg1= $1 arg2= $2 arg3= $3shiftecho arg1= $

8、1 arg2= $2 arg3= $3shiftecho arg1= $1 arg2= $2 arg3= $3shiftecho arg1= $1 arg2= $2 arg3= $3shiftl 编写shell脚本sum1，求命令行上整数和。即：$./sum1 5 12 4 6，给出和的结果。sum=0for i in $*do let sum=sum+idoneecho “和是:$sum”l 编写脚本filetest，判断当前目录下所有文件类型，如果是普通文件，显示文件内容；如果是目录文件，显示目录列表；如果是大小为0的文件，删除它；否则，显示“sorry， The file is not

9、recognized!”for i in *do if -d $i then ls $ielif -f $i then if -s $i then cat $ielse rm $i fielse echo n “sorry,the file cant be recognized”fidonel 编写shell脚本user，判断当前登录用户是否为“学号命名”的用户，是，提示：hello “学号用户”,welcome!，否，提示“you should login using your username! ”Read nameIf $USER = $name Then echo “hello $US

10、ER”else echo “you should login using your username!”fil 编写shell脚本menu，使用shell编写一个菜单，分别实现列出以下内容：（1）显示目录内容、（2）切换目录、（3）创建文件、（4）编辑文件、（5）删除文件的l 功能。在此例中将用到循环语句、分支语句和输入输出语句。Echo “a.display the directory”Echo “b.change the directory”Echo “c.create a file”Echo “d.delete the file”Echo “if you input nothing,yo

11、u will exit”Read itemUntil -z $item Do Case $item in a) Echo “input the directory”Read direLs $dire;b) Echo “input the directory you want go into”Read direCd $dire;c) Echo “input the file you want to create”Read fTouch $f;d) Echo “input the file you want to delete”Read fRm $f;EsacEcho “a.display the

12、 directory”Echo “b.change the directory”Echo “c.create a file”Echo “d.delete the file”Echo “if you input nothing,you will exit”Read itemdonel 编写脚本，实现一个简单计算器。+ addition- subtractionx multiplication/ division脚本执行形式：$ ./cal.sh 21 / 3Let l=$1 /最简单的一种形式，而且还特别高效Echo $1;第二种方式：Re=”+ - * /”For var in $reDo If $var = “*” ThenNum2=$1#* Num1=$1%* Else Num2=$1#*$var Num1=$1#