第7章第2题作业答案用乘子法求解下列问题VIP

7c 25T+ + + + = w xxxxxxv w xx w xxxxxxv wxxwxx vwx 2 2 1 2 2121 2 2 2 2 1 2 2 1 2 2121 22 2 2 1 2 2 2 1 )2( )12( 2 )12( 2 )3()2( )2( )12( 2 )12( )2( 2 1 )3()2( ),( 7c 25T 2 2 1 )2( H =+= =+= 0)12()3(2 0)12( )2( 212 2 211 1 xxvx x xxvx x 2 e ZF 7 3 2 21 = xb,xa 5 1 2e 7c 25Ts =+ =+ 0)2( 32 0)2( 3 2 2 bavwbab bav w baaa 1 =+ =+ 0)2(2 0)2( bavb bava 2 ZF 2 T pT 52 , 52 2 + = + = v b v a ZF 11 +h s V/ T pbBZE 7c 25Ts L ! k H a | )(k a ZF 1 2 T9 )1( +k b 9 T )1(2 2)3( )(2)( )1( + + = + kk k avwa b ZF 1 1 T9 )1( +k a 9 T 3 )( )1()()1( )1( )1( vaw baa k kkk + += + T |-a |a kk + )()1( 5TM )1()1( , + kk b a TZF 5Rb 7c 25Ts 7 S H )0( a V | i -1 0 100b p a b Q p 3 2 21 +=+= bx,a x 5 pV / 1Q 7 2 ,2 2 )1()1( = vw, b 5 pZF 1 | 0001.0,1 )0( = a 99087.1 83454.0 = b, a 00913.1 16546.1 (1) 2 )1( 1 = x, x 7c 25Ts 7 O Hq 131267.0)2( )1( )1( 2 2)1( 1 = w xx vw, 35641.1)12( 62534.2)2(,0max )1( 2 )1( 1 )1()2( )1( 2 2)1( 1 )1()2( = = xxvv xxww 2Q 7 35641.1 ,62534.2 2 )2()2( = vw, b 5 pZF 1 | 0001.0,1 )0( = a 99641.1 04066.1 = b, a 00359.1 95934.0 (2) 2 )2( 1 = x, x 7c 25Ts 7 O Hq )2( )2( 2 2)2( 1 )2( w xx vw, 52622.1)12( 46659.2)2(,0max )2( 2 )2( 1 )2()3( )2( 2 2)2( 1 )2()3( = = xxvv xxww 3Q 7 52622.1 46659.2 2 )3()3( = vw, b 00123.1 00921.1 (3) 2 )3( 1 = x, x 7 O Hq )3( )3( 2 2)3( 1 )2( w xx vw, 49184.1,50571.2 )4()4( = vw 7c 25Ts 4Q 00041.1 99787.0 (4) 2 )4( 1 = x, x 7 O Hq )4( )4( 2 2)4( 1 )2( w xx vw, 50119.1,49799.2 )5()5( = vw V 9Q 00000.1 0