设计程序以打印任意一年的日历.doc

1. 设计程序以打印任意一年的日历，要求每个季度的三个月并排打印，每个月的一个星期在一行打印，格式如下：年 号123456789101112C语言源程序代码：#includestruct mdat int mdays;int mhead;int mlast;/*声明并定义结构体mdat(mouth data)数组a,用它的成员mdays来统计一个月的天数;用它的成员mhead来统计一个月,月头的天数;用它的成员mlast来统计一个月,月尾的天数;用它的成员mline来统计一个月,一个月在日历上有几行;*/int main(void)void data(struct mdat a12 ,long year);/*声明返回值为空的数据处理函数函数data,此函数用来计算,得到并赋值给结构体mdat数组a12中,对应元素的相应成员*/void print(struct mdst a);/*声明返回值为空的的输出函数print,其作用是根据a12结构体mdat数组所提供的信息,对一年的年历进行输出*/long year,jihao = 0;struct mdat a12;a0.mdays = 31;a2.mdays = 31; a4.mdays = 31;a6.mdays = 31;a7.mdays = 31;a9.mdays = 31;a11.mdays = 31;a1.mdays = 30;a3.mdays = 30;a5.mdays = 30;a10.mdays = 30;a8.mdays = 30;/*对一年中天数固定的月份,天数进行赋值*/printf(请输入你要查看年历的年份,并以回车键结束输入:);scanf(%d,&year);/*输入年份语句*/printf(n);if (year 0)jihao=0-year;year = 7+(year%7);/*对于year 32768)year = year % 7;if (year = 0)tdays = 0;elsetdays = (year - 1) * 365 + ( year - 1 ) / 4;a0.mhead = 7 - ( tdays % 7 );a0.mlast = ( a0.mdays - a0.mhead ) % 7;if (a0.mlast = 0)a0.mlast = 7;/*计算并赋值结构体数组元素a0的各个成员*/for ( i = 1; i 12; i+ )ai.mhead = 7 - ai-1.mlast;ai.mlast = (ai.mdays - ai.mhead) % 7;if (ai.mlast = 0)ai.mlast = 7;if (ai.mhead = 0)ai.mhead = 7;/*for (i = 0;i 12;i+)printf(a%2d.mhead=%2d, a%2d.mdays=%2d, a%2d.mlast=%2d,i,ai.mhead,i,ai.mdays,i,ai.mlast);printf(n);*/*调试过程中为查看收集到的数据是否正确将他们输出*/*利用循环语句计算并赋结构体数组各元素成员的值*/void print(struct mdat a12) int num12=1,1,1,1,1,1,1,1,1,1,1,1,i,j,k=-2,l,m,n=0;for(m = 0;m 10;m = m + 3)k= k + 3;for (l = 0;l 36; l = l + 7)for ( j = m; j n )n = k;for (i = k;i k + 3;i + )printf ( %2d ,i);printf( );printf(nn);/*一个月正上方的月号的输出,需要先判断是否可以输出,再进行输出*/if ( numj = aj.mhead)for (i=0; i 7-aj.mhead ; i+)printf( );/*一个月没一星期前的空格输出*/for (;numj = aj.mhead+l;numj+)if (numj = aj.mdays)printf( %2d , n