天然气管道输送 C语言编程计算

1、.；1.#includestdio.hmain()float PH,D,S,J,F;F=0.72;scanf(“%f,%f,%f”,&PH,&D,&S); J=(PH*D)/(2*S*F);printf(“%f”,J);2.#includestdio.hmain()float D,d,J;scanf(“%f,%f”,&D,&J); d=D-2*J;printf(“%f,d);3.#includestdio.hmain()float PB,P,W;scanf(“%f,%f”,&P,&W); PB=P/W;printf(“%f”,PB);4.#includestdio.hmain()float P

2、1,P,P2,J;scanf(“%f,%f, %f”,&P,&J,&P2); P1=(P-J*P2)/(1+J);printf(“%f”,P1);5.#includestdio.hmain()float P2,PB,P,J;scanf(“%f,%f,%f” ,&PB,&P,&J); P2=PB+J*P;printf(“%f”,P2);6.#includestdio.hmain()float PCP,P1,P2;scanf(“%f,%f” ,&P1,&P2); PCP=(2/3)*(P1+(P2*P2)/(P1+P2);printf(“%f”,PCP);7.#includestdio.hmain

3、()float B,E,D,d;d=pow(D,0.2);scanf(“%f,%f” ,&E,&D);B=1.05*0.03817/(E*E*d);printf(“%f”,B);8.#includestdio.h#includemath.hmain()float l,D,q,P1,P2,X,B,Z,TCP,d;X=0.61;scanf(%f,%f,%f,%f,%f,%f,%f ,&D,&q,&P1,&P2,&B,&Z,&TCP);d=pow(D,2.5);l=(105.113*d/q)* (105.113*d/q)*(P1*P1-P2*P2)/(X*B*Z*TCP);printf(%f,l);

4、9.#includestdio.hmain()float PKCP,P1,PK;scanf(“%f,%f” ,&P1,&PK);PKCP=(2/3)*(P1+PK*PK/(P1+PK);printf(“%f”,PKCP);10.#includestdio.h#includemath.hmain()float l,D,q,P1,PK,X,B,ZK,TKCP,d;X=0.61;scanf(%f,%f,%f,%f,%f,%f,%f ,&D,&q,&P1,&PK,&B,&ZK,&TKCP);d=pow(D,2.5);l=(105.113*d/q)* (105.113*d/q)*(P1*P1-PK*PK

5、)/(X*B*ZK*TKCP);printf(%f,l);11.#includestdio.hmain()float n,L,lk,l;scanf(“%f,%f” ,&lk,&l);L=650;n=(L-lk)/l+1;printf(“%f”,n);12#includestdio.h#includemath.hmain()float H,k,ZB,R,T,a,b;k=1.5;R=48.34;T=293;scanf(“%f,%f” ,&ZB,&a);b=pow(a,(0.5/1.5);H=(k/(k-1)*Z*R*T*(b-1);printf(“%f”,H);13.#includestdio.h

6、main()float N0,G,H,c;c=0.8;G=70.91scanf(“%f,%f” ,&G,&H);N0=G*H/(102*c);printf(“%f”,N0);14#includestdio.hmain()float GT,D,a;scanf(“%f,%f” ,&G,&H); GT=0.0246615*(D-a)*a;N0=G*H/(102*c);printf(“%f”,GT);15#includestdio.hmain()float K,KN,a,N,L,K0,KB,GT,KD,D,Kn;scanf(“%f,%f,%f,%f” ,>,&D,&L,&N); KN=7200;a

7、=1.05;K0=20000000;KB=960;KD=1.21794/650;Kn=15000;K=KN*a*N/L+K0/L+KB*GT+KD*D+Kn;printf(“%f,%f”,K,K*650);16#includestdio.hmain()float C,CN,N,L,C0,Ca,K;scanf(“%f,%f,%f” ,&L,&K,&N); CN=5000;C0=100000;Ca=100000;C=CN*N/L+C0/L+K+Ca;printf(“%f,%f”,C,650*C);17#includestdio.hmain()float E,KZ,CZ,S;scanf(%f,%f ,&KZ,&CZ); E=0.124;S=E*KZ+CZ;printf(%f,S)