C语言程序设计习题答案

1、数据类型1.B2.char3.char4.85.long int 或long6.B7.C8.D9.(%d)%ld表达式10.2211.B12.0或113.D14.double15.D16.float17.218.sqrt(x*x+y*y)/(a+b)19.120.D21.2,522.C23.A24.B25.double26.A27.sqrt(abs(a-b)/(3*(a+b)或sqrt(fabs(a-b)/3/(a+b)基本1.A2.C3.A4.B5.A6.C7.B8.C9.D10.C11.表达式语句（函数调用语句）12.scanf13.3276814.标准或stdin或键盘15.216.11

2、7.1,0,118.%ld19.420.-32768循环21.C22.C23.C24.A25.D26.return27.for28.1329.2030.n flag=1 n-31.t=1 n<=i32.sum<k j-2数组1D2.D3.A4.B5.C6.37.A8.B9.1 4 3 2 5 810.1 2 43 5 76 8 911.18 2212.49235781613.7 8 16 9 25 4 314.11 2 11 4 6 4 115.1 3 131 5 212 8 3416.a*100+b*10+c sum/100 w=1 sj=sk字符数组17.D18.D19.D20

3、.B21.you&me22.3 0函数1.D2.B3.A4.B5.B6.A7.C8.B9.A10.C11.C12.&a0, a数组第一个元素的地址13.1.0014.13 00110115.234116.217.110011110111011118.5,2519.2 5 89 8 73 2 120.void21.10101222.第一个元素地址或起始地址23.-8 41 224.n<=0 n!=invert(n) x=x/1025.math.h fabs(term) -x*x/(n*(n+1)26.n/10+n%10*10(或n%10*10+n/10)mj%k=027.m

4、 a, b28.x x*x/i29.a>0r<10i-130.xx-f(x)/f1(x)31.j<i1/term32.n/10i<j33.strcmp(tmp, s2)=0或!strcmp(tmp, s2)i+&count34.1x*x/(2*n-1)*(2*n)n+35.!(n%i)或n%i=0m*10+n%10p(convert(i)36.-fs+=ws=fun(n)或s=fun(5)37.&opsi+1sn=c238.fabs(t)>epsn/(2*n+1)PI(e)39.s+n-k*10或s+n%10s+f(k)f(i)=g(i)40.x1

5、=x0fabs(x1-x0)>=1e-6root(0)41.pai-1*p+cn-1递归1.the result is: 3652.101003.74.15作用域1.A2.B3.B4.D5.D6.D7.1, 28.129.1610.911.1312.1513.8 1014.extern15.3预处理1.D2.C3.A4.485.D6.8.07.68.69.2010.3结构体1.B2.D3.A4.C5.B6.D7.C8.B9.C10.A11.11043380055012.813.5 7 514.1 5 3 2 45 5 4 3 2 115.416.POINTk=ii+1xk.x=xj.x1

6、7.pk.indexpkinserttv(p, s1,4)18.STUDp->gradecti+19.typedef i puk.grade<puj.grade20.string.hsyi.c_namesxi.type21.struct complex *return pp->r,p->i22.ai indexj.x>indexk.x*(p+j)或*(indexi.y+j)指针1.C2.B3.D4.C5.C6.D7.C 8.D9.D10.B11.C12.C13.C14.B15.C16.C17.D18.D19.B20.D21.D22.C23.B24.取操作数地址25

7、.2744A26.1,3,727.void *p28.no29.3,9,330.6,2,4,3,5,131.9 6 3 8 5 232.31 32-3333.FFD034.021 11335.336.edcba2543137.438.10, 2039.4,540.3 541.1 4 3 2 542.3 243.bell lleb44.bike 245.746.4,325,747.函数48.2 0 849.050.god51.char *p;52.postti+ji+j-153.slenk+mstrk54.bj!=0j+ck+i+j-k(或strlen(a)+strlen(b)-k)55.cha

8、r *a或char aai>='a'&&ai<='z'或islower(ai)return a56.bn-1-i或b3-iai>bjck=ai57.(f+1)%(n+1)(r+1)%(n+1)f!=r58.*n=*m=0av+=xixi>=av59.xi&&yj或xi!='0'&&yj!='0'z+kk=i链表1.B2.A3.31,31,3,54.2,3,4,5,6,7,8,92,3,5,74acom6.herteacthe7.32659235692568.p2->nextheadp1->nextp2->next=p19.headpmax->xpre->next*pm10.pk->nextpj->dpn!=headreturn k11.head->next=0q->nexth