C语言操作题常考编程题库

1、C语言编程题覆盖到的算法：1、个人所得税计算；2、求一组数的正、负数（或奇、偶数）的个数和平均值；3、二维数组主、次对角线之和；4、求素数（用函数实现）；5、级数有限项求和问题；6、两个一维数组相加（用函数实现）；7、求最大、最小值；8、判断闰年（用函数实现）；9、求水仙花数；10、百钱百鸡；11、求最大公约数、最小公倍数。12、求回文数；13、排序；14、二维数组的转置；15、递归函数求阶乘；16、求斐波那契数列；17、求和：a+aa+aaa+aaaa+.；18、求符合条件的整数（如：是某个二位数的平方，个位、十位、百位数各不相同等）；(包括素数，回文，完数，等等)19、字符串加密；20、统

2、计字符串中字母和数字的个数；/*1.个人所得税计算，以实验指导P24T5为标准*/#include<stdio.h>void main()int i,n;double a,b,c;n=i/400;printf("please input income:n");scanf("%d",&i);a=(i-800)*0.05,b=20+(i-1200)*0.08,c=84+(i-2000)*0.2;switch(n)case 0:case 1:printf("不需缴税n");break;case 2:printf(&quo

3、t;需交纳%lf元n",a);break;case 3:case 4:printf("需交纳%lf元n",b);break;default:printf("需交纳%lf元n",c);break;/*2. 求一组数的奇数个数，偶数个数和平均值#include<stdio.h>#define N 10void main()int aN;int i,m=0,n=0,sum=0;double average;printf("please input 10 numbers:n");for(i=0;i<N;i+)sca

4、nf("%d",&ai);if(ai%2=0)m+;elsen+;sum+=ai;average=(double)sum/N;printf("we have %d odds and %d evensn",n,m);printf("average=%lfn",average);*/*2'.求一组数的正数个数和负数个数与平均值*/#include<stdio.h>#define N 10void main()int aN;int i,m=0,n=0,sum=0;double average;printf(&qu

5、ot;please input 10 numbers:n");for(i=0;i<N;i+)scanf("%d",&ai);if(ai>0)m+;elsen+;sum+=ai;average=(double)sum/N;printf("we have %d positive numbers and %d nagetive numbersn",m,n);printf("the average =%lf",average);/*3.求二维数组的主次对角线之和*/#include<stdio.h>#

6、define M 5 #define N 5void main()int aMN;int i,j,sum1=0,sum2=0;printf("please input the matrix:n");for(i=0;i<M;i+)for(j=0;j<N;j+)scanf("%d",&aij);for(i=0,j=0;i<M;i+,j+)sum1+=aij;for(i=0,j=N-1;i<M;i+,j-)sum2+=aij;printf("主对角线和为%dn",sum1);printf("次对角线

7、和为%dn",sum2);/*4.调用函数判断素数*/#include<stdio.h>#include<math.h>int isPrime(int n)int i;for(i=1;i<sqrt(n);i+)if(n%i=0)return 0;return 1;void main()int n,i;printf("please input a numbern");scanf("%d",&n);i=isPrime(n);if(i)printf("%d is a primen",n);el

8、seprintf("%d is not a primen",n);/5.级数有限项求和(以格里高利公式求为例)/#include<stdio.h>#include<math.h>void main()int n=1;double p=0,t,pi;t=1/(pow(-1),(n+1)*2*(n-1);while(fabs(t)>=1e-6)pi+=t;n+;pi=4*p;printf("%lf",pi);/6.两个一维数组相加/*#include<stdio.h>#define N 5void main()int

9、 aN,bN,cN;int i;printf("please input the first array aN:n");for(i=0;i<N;i+)scanf("%d",&ai);printf("please input the second array bN:n");for(i=0;i<N;i+)scanf("%d",&bi);for(i=0;i<N;i+)ci=ai+bi;printf("the sum is:n");for(i=0;i<N;i+)p

10、rintf("%dt",ci);*/6.1调用函数实现/#include<stdio.h>#define N 5int f(int a,int b)int sum;sum=a+b;return sum;void main()int aN,bN,cN;int i;printf("please input the first array aN:n");for(i=0;i<N;i+)scanf("%d",&ai);printf("please input the second array bN:n&quo

11、t;);for(i=0;i<N;i+)scanf("%d",&bi);for(i=0;i<N;i+)ci=f(ai,bi);printf("the sum is:n");for(i=0;i<N;i+)printf("%dt",ci);/*7.求一组数的最大最小值*/*#include<stdio.h>void main()int i,max,min;int a10;printf("please input ten numbersn");for(i=0;i<10;i+)sc

12、anf("%d",&ai);max=a0;min=a0;for(i=1;i<10;i+)if(ai>max)max=ai;if(ai<min)min=ai;printf("max is %d,min is %dn",max,min);*/*随机数*/#include<stdio.h>#include<stdlib.h>void main()int i,max,min;int a10;for (i=0;i<10;i+)ai=rand()%90+10;printf("%dt",ai)

13、;max=a0;min=a0;for(i=1;i<10;i+)if(ai>max)max=ai;if(ai<min)min=ai;printf("max=%dtmin=%dn",max,min);/*8.判断闰年*/#include<stdio.h>int f(int n)if(n%4=0&&n%100!=0|n%400=0)return 1;elsereturn 0;void main()int n;printf("please input year:n");scanf("%d",&am

14、p;n);if(f(n)printf("%d是闰年n",n);elseprintf("%d不是闰年n",n);/*可能会有要输出某一范围内所有闰年，思想一样，用循环调用函数即可*/*9.判断水仙花数（运用循环）#include<stdio.h>void main()int n,a,b,c,m;printf("please input a number:n");scanf("%d",&n);a=n/100;b=n/10%10;c=n%10;m=a*a*a+b*b*b+c*c*c;if(m=n)pr

15、intf("%d is the number we wantn",n);elseprintf("%d is not the numbern",n);*/*9'.输出所有水仙花数（调用函数(书P108为循环做法)）*/#include<stdio.h>int f(int n)int a,b,c,m;a=n/100;b=n/10%10;c=n%10;m=a*a*a+b*b*b+c*c*c;if(m=n)return 1;elsereturn 0;void main()int i,t;for(i=100;i<1000;i+)t=f(i

16、);if(t=1)printf("%dt",i);/10.百钱买百鸡（题目见书P115）/#include<stdio.h>void main()int i,j,k;for(i=0;i<=20;i+)for(j=0;j<=33;j+)for(k=3;k<=99;k+=3)if(i+j+k=100)&&(5*i+3*j+k/3=100)printf("公鸡%d只，母鸡%d只，小鸡%d只n",i,j,k);/*11.求最大公约数和最小公倍数，函数实现*/#include<stdio.h>int f(i

17、nt m,int n)int i=1,t;if(m<n)t=m;m=n;n=t;while(i=m%n)!=0)m=n;n=i;return n;int g(int m,int n)int i,j;i=f(m,n);j=m*n/i;return j;void main()int m,n,a,b;printf("please input two numbers:n");scanf("%d %d",&m,&n);a=f(m,n);b=g(m,n);printf("最大公约数为%dn",a);printf("

18、最小公倍数为%dn",b);/12.1输出10-2000之间的回文数（循环）/*#include<stdio.h>void main()int i,j,k=0,a;printf("10-2000之间的回文数有：n");for(i=10;i<=2000;i+)a=i;j=0;while(a>0)j=j*10+a%10;a/=10;if(i=j)printf("%dt",i);k+;if(k%5=0)printf("n");printf("n");*/12.2输出10-2000之间的回

19、文数（函数调用）/*#include<stdio.h>int f(int n)int i=0;while(n>0)i=i*10+n%10;n/=10;return i;void main()int n,k;printf("10-2000之间的回文数有：n");for(n=10;n<=2000;n+)if(n=f(n)printf("%dt",n);k+;if(k%5=0)printf("n");printf("n");*/12.3判断回文数（循环）/*#include<stdio.h&

20、gt;void main()int i,a,j=0;printf("please input a number:n");scanf("%d",&i);a=i;while(a>0)j=j*10+a%10;a/=10;if(j=i)printf("%d是回文数n",i);elseprintf("%d不是回文数n",i);*/12.4判断回文数（函数调用）/#include<stdio.h>int f(int n)int i=0;while(n>0)i=i*10+n%10;n/=10;re

21、turn i;void main()int n;printf("please inpit a number:n");scanf("%d",&n);if(n=f(n)printf("%d是回文数n",n);elseprintf("%d不是回文数n",n);/13.排序/选择法/*#include<stdio.h>#define N 10void f(int a,int n)int i,j,k,t;for(i=0;i<=n;i+)k=i;for(j=i+1;j<n;j+)if(aj<

22、;ak)k=j;if(k!=i)t=ak;ak=ai;ai=t;void main()int aN=8,2,34,5,12,78,4,78,76,9;int i=0;int size=sizeof(a)/sizeof(int);for(i=0;i<N;i+)printf("%4d",ai);printf("n");f(a,size);for(i=0;i<N;i+)printf("%4d",ai);printf ("n");/冒泡法/#include<stdio.h>#define N 5vo

23、id f(int a,int n)int i,j;int t;for(i=0;i<n-1;i+)for(j=0;j<n-1-i;j+)if(aj>aj+1)t=aj;aj=aj+1;aj+1=t;*/插入法/#include<stdio.h>#define N 5void f(int a,int n)int i,j;int t;for(i=0;i<n;i+)t=ai;j=i;while(j>0&&aj-1>t)aj=aj-1;-j;aj=t;void main()int aN=8,2,34,5,12;int i=0;int siz

24、e=sizeof(a)/sizeof(int);for(i=0;i<N;i+)printf("%4d",ai);printf("n");f(a,size);for(i=0;i<N;i+)printf("%4d",ai);printf ("n");/二维数组的转置/#include<stdio.h>#define N 3#define M 3void main()int aMN,bMN;int i,j;printf("please input aMNn");for(i=0;

25、i<M;i+)for(j=0;j<N;j+)scanf("%d",&aij);for(i=0;i<M;i+)for(j=0;j<N;j+)bij=aji;printf("bMN=n");for(i=0;i<M;i+)for(j=0;j<N;j+)printf("%4d",bij);printf("n");printf("n");/15.调用递归函数求阶乘/#include<stdio.h>int f(int n)if(n=1|n=0)ret

26、urn 1;elsereturn f(n-1)*n;void main()int n,m;printf("please input a number:n");scanf("%d",&n);m=f(n);printf("%d!=%dn",n,m);/*16.运用递归函数求斐波拉契数列（前30项）*/#include<stdio.h>int f(int n)if (n=1|n=2)return 1;elsereturn f(n-1)+f(n-2);void main()int i,k=0;for (i=1;i<=

27、30;i+)printf("%dt",f(i);k+;if(k%5=0)printf("n");printf("n");/17.求a+aa+aaa+aaaa./*#include<stdio.h>#include<math.h>#define N 5void main()int n,i,j,k,a,sum1=0;printf("please input a number:n");scanf("%d",&n);for(i=1;i<=N;i+)k=fabs(10,i-1);j=n+n*(i-1)*k;sum1+=j;printf("sum=%dn",sum1);*/#include<stdio.h>#define N 5int k(int a,int sum)sum=sum*10+a;return sum;void main()int a,i=0,j,sum=0;