微机原理编程题

1、微机原理编程题1.分支程序设计 .编写一段程序，已知BUF1单元中有一带符号字节数据 X, BUF2中有一带符号 字节数据丫，根据以下函数关系编写程序求 Z的值，结果存入 RESULT单元。Z=|X-Y| ；DATASEGMENTBUF1 DB05HBUF2 DB02HRESULTDBDATAENDSCODESEGMENTASSUMCS:CODE,DS:DATASTARTMOVXQATAMODS,AXMOAL,BUF1MOBL,BUF2SUBAL,BLJNC GREATNEGALGREATMORESULT,ALEXIT: MOAH,4CHINT 21HCODEENDSENDSTART 编写一段

2、程序，已知BUF单元中有一无符号字节数据 X,假设为8,根据以 下函数关系编写程序求 丫的值，结果存入RESULT单元。Z=5X X<10,X-5 X>=10;DATASEGMENTBUF DB8RESULTDB DATAENDSCODESEGMENTASSUMCS:CODE,DS:DATASTARTMOVXQATAMODS,AXMOAL,BUFCMPAL,10JAE GREMOBL,ALADDAL,ALADDAL,ALADDAL,BLJMP DONEGRE: SUBAL,5DONE:MOVRESULT,ALMOAH,4CHINT 21HCODEENDSENDSTART .在内存单

3、元BUF中存放一个带符号字节数据 X,假定为-2，试根据以下函数关系编写程序求丫的值，结果存入RESULT单元。丫=1 X>0,0 X=0,-1 X<0;DATASEGMENTBUFDB-2RESULTDBDATAENDSCODESEGMENTASSUMCS:CODE,DS:DATASTARTMOVXQATAMODS,AXMOAL,BUFCMPAL,0JGE L1MOAL, -1JMP L3L1:JZ L2M0AL,1JMP L3L2: MOAL,0L3: MORESULT,ALM0AH,4CHINT 21HCODEENDSENDSTART2. N个数中求最大值、最小值.假定N=1

4、0,已知原始数据存放在BUF开始的内存 单元中，将结果存入 MAX MIN内存单元中。DATASEGMENTBUF DB3,5,7,8,5,3,9,7,13,1COUNTEQU$-BUFMAXDBMIN DBDATAENDSCODESEGMENTASSUMCS:CODE,DS:DATASTARTMOVXQATAMODS,AXMOVCX,COUN-T1MOAL,BUFMOVMAX,ALMOVMIN,ALLEASI,BUFAGAIN:MOAL,SI+1CMPAL,MINJGE S1MOVMIN,ALS1: CMPAL,MAXJLE S2MOVMAX,ALS2: INC SILOOP AGAINMO

5、AH,4CHINT 21HCODEENDSENDSTART3.编写程序求1+2+3+N<100时最大的N值，将N值送NUM单元中，同时将 1+2+3+N的和送到SUM单元中。DATASEGMENTNUMDBSUMDBDATAENDSCODESEGMENTASSUMCS:CODE,DS:DATASTARTMOAX,DATAMOVDS,AXMOAL,0MOVBL,0AGAIN :INC BLADDAL,BLCMPAL,100JB AGAINSUBAL,BLDECBLMOVJUM,BLMOVSUM,ALMOAH,4CHINT 21HCODEENDSENDSTART4.统计字符，正数，负数，零的

6、个数。若自STRING单元开始存放一个字符串，以'$'结尾，试编写程序,统计字符串的长度，并将结果存入 COUN单元。DATASEGMENTSTRINGDB'abcdefg$'COUNTDWDATAENDSCODESEGMENTASSUMCS:CODE,DS:DATASTARTMOVXQATAMODS,AXLEASI,STRINGMOVCX,0NEXT: MOAL,SICMPAL, '$'JZ DONEINC CXINC SIJMP NEXTDONE:MOVCOUNT,CXMOAH,4CHINT 21HCODEENDSENDSTART.自BUF单

7、元开始存放10个带符号字节数据，将其中的正数、负数和零选出 来，并统计其个数，分别存入 PLUS MINUS和ZERO单元中。DATASEGMENTBUF DB5, -2,0, -1,4,0, -4,8,0, -7PLUS DBMINUSDBZERO DBDATAENDSCODESEGMENTASSUMCS:DATA,DS:DATASTARTMOVXQATAMODS,AXLEASI,BUFMOVCX,10AGAINMIOAL,BXINC BXANDAL,ALJS M1JZ M2INC PLUSJMP NEXTM1:INC MINUSJMP NEXTM2:INC ZEROJMP NEXTNEXT

8、: LOOP AGAINMOAH,4CHINT 21HCODEENDSENDSTART5.求压缩BCD码的和。已知从BUF1和 BUF2单元开始，存放两个各为10个字节 的BCD数，求这两个数的和，并将结果存入 BUF3单元中。DATASEGMENTBUF1 DB01H,01H,01H,01H,01H,01H,01H,01H,01H,01HBUF2 DB03H,03H,03H,03H,03H,03H,03H,03H,03H,03HBUF3 DB11 DUP)DATAENDSCODESEGMENTASSUMCS:CODE,DS:DATASTARTMOVXQATAMODS,AXMOVCX,10LE

9、ASI,BUF1LEADI,BUF2LEABX,BUF3AGAIN:MOVAL,SIADCAL,DIDAAMOVBX,ALINC SIINC DIINC BXLOOP AGAINADCAH,0MOBX,AHMOAH,4CHINT 21HCODEENDSENDSTART6. 8255编程题：（课后实验）8255 工作于方式0,此时PA PB PC均为可独立输入/输出的并行口。8255 的各寄存器对应的口地址为： PAD: 200H, PB口： 202H, PC口： 204H,控制口： 206Ho要求8255工作于方式0, PA 口设置为输入，PC口设置为输出。DATASEGMENTC8255EQU206HP8255AEQU200HP8255CEQU204HDATAENDSCODESEGMENTASSUM£