华人工作相关人格量表_的编制_意义与效度

1、/p> int Type;bus9;struct BranchDataStructint ID;int FisrtBus; int EndBus;float R,X,B,K;Branch9;float YG99, YB99;int main(array<System:String > args)ifstream ob("F:yangyuanyuandata.txt"); for(int i=0;i<9;i+) ob >> busi.ID >> busi.U >> busi.A >> busi.PG &g

2、t;> busi.QG >> busi.PL >> /-输入数据- busi.QL >> busi.Type;for(int i=0;i<9;i+) ob.close(); ob >> Branchi.ID >> Branchi.FisrtBus >> Branchi.EndBus >> Branchi.R >> Branchi.X >> Branchi.B >> Branchi.K; 4/-节点导纳矩阵- for(int i=0;i<9;i+) for(i

3、nt j=0;j<9;j+) YGij = YBij = 0.0; for(int i=0;i<9;i+) float yG = Branchi.R / ( Branchi.R* Branchi.R + Branchi.X * Branchi.X); float yB =- Branchi.X / ( Branchi.R* Branchi.R + Branchi.X * Branchi.X); int ii = Branchi.FisrtBus - 1; int jj = Branchi.EndBus - 1; YGiiii += yG;YGjjii += -yG; YBiiii

4、+= yB + Branchi.B;YBjjjj += yB + Branchi.B; YBiijj += -yB; YBjjii += -yB; ofstream ob2("F:yangyuanyuanYmatric.txt"); for(int i=0;i<9;i+)for(int j=0;j<9;j+)if(YBij>=0) ob2<<YGij<<"+"<<YBij<<"j"<<"t" elseob2<<YGij<

5、<YBij<<"j"<<"t" ob2<<"n"ob2.close(); /-设电压初值- float Ue9,Uf9; for (int i=0;i<9;i+) Uei=busi.U; Ufi=0.0; 5/-循环- ofstream ob3("f:yangyuanyuandelta.txt");ofstream ob4("f:yangyuanyuanJacobian.txt");ofstream ob6("f:yangyuanyuan

6、deltaEF.txt");ofstream ob7("f:yangyuanyuanU.txt");for (int step=1;step<5;step+) ob3 <<endl<< endl<< "step" << step << endl; ob4 << endl<< endl<< "step" << step<< endl; ob6 << endl<< endl<

7、< "step" << step<< endl;ob7 <<endl<< endl<< "step" << step<< endl; float deltaP9,deltaQ9,deltaUU9; float aii9=0,bii9=0; float P9,Q9;for (int i=0;i<9;i+) Pi=busi.PG-busi.PL; Qi=busi.QG-busi.QL; for (int i=0;i<9;i+) for (int j=0;j&

8、lt;9;j+)aiii+=YGij*Uej-YBij*Ufj;biii+=YGij*Ufj+YBij*Uej;deltaPi=Pi-Uei*aiii-Ufi*biii;deltaQi=Qi-Ufi*aiii+Uei*biii;deltaUUi=busi.U*busi.U-Uei*Uei-Ufi*Ufi;for(int i=0;i<9;i+) ob3 << "deltaP" << i << "=" << deltaPi << endl; for(int i=0;i<9;i+) ob3

9、 << "deltaQ" << i << "=" << deltaQi << endl; ob3 << "deltaUU" << i << "=" << deltaUUi << endl; for(int i=0;i<9;i+) 6/-形成雅可比矩阵- float H99,N99,J99,L99,R99,S99;for(int i=0;i<9;i+)for(int j=0;j<9;j+) Hij=0; Nij=0