最新2022年全国高考化学题分类汇编(热化学计算)

1、最新2022年全国高考化学题分类汇编(热化学计算)of rural drinking water sources, protection of drinking water sources in rural areas by the end of the delimitation of the scope of protection, complete with warning signs, isolating network protection facilitiesof rural drinking water sources, protection of drinking water s

2、ources in rural areas by the end of the delimitation of the scope of protection, complete with warning signs, isolating network protection facilitiesof rural drinking water sources, protection of drinking water sources in rural areas by the end of the delimitation of the scope of protection, complet

3、e with warning signs, isolating network protection facilities热化学计算(2022重庆)答案：D2022四川卷1116分3： 25、101kpa时，Mn(s)O2(g)MnO2(s) H520kJ/molS(s)O2(g)SO2(g) H297kJ/molMn(s)S(s)2O2(g)MnSO4(s) H1065kJ/molSO2与MnO2反响生成无水MnSO4的热化学方程式是_。2022新课标I28、(15分)2：甲醇脱水反响2CH3OH(g)CH3OCH3(g)H2O(g)H123.9KJmol1甲醇制烯烃反响2CH3OH(g)C

4、2H4 (g)2H2O(g) H229.1KJmol1乙醇异构化反响CH3CH2OH(g)CH3OCH3(g) H3+50.7KJmol1那么乙烯气相直接水合反响C2H4 (g)H2O(g)C2H5OH(g)的H -45.5KJmol12022广东B3116分用CaSO4代替O2与燃料CO反响，既可提高燃烧效率，又能得到高纯CO2，是一种高效、清洁、经济的新型燃烧技术，反响为主反响，反响和为副反响。CaSO4(s)+CO(g) CaS(s)+CO2(g) H1= 47.3kJmol-1 CaSO4(s)+CO(g) CaO(s)+CO2(g) +SO2(g) H2= +210.5kJmol-1

5、 CO(g) C(s)+ CO2(g) H3= 86.2kJmol-1 1反响2CaSO4(s)+7CO(g) CaS(s)+ CaO(s)+6CO2(g)+ C(s) +SO2(g)的H_用H1、H2和H3表示2022北京：2NO2g N2O4gH1 2NO2g N2O4lH2 以下能量变化示意图中，正确的选项是选填字母_。 A B CN2O4与O2、H2O化合的化学方程式是_。2022广西28(15分)化合物AX3和单质X2在一定条件下反响可生成化合物AX5。答复以下问题：1AX3的熔点和沸点分别为93.6 和76 ，AX5的熔点为167 。室温时AX3与气体X2反响生成lmol AX5，

6、放出热量123.8 kJ。该反响的热化学方程式为 。2022新课标II13、室温下，将1mol的CuSO45H2O(s)溶于水会使溶液温度降低，热效应为H1，将1mol的CuSO4(s)溶于水会使溶液温度升高，热效应为H2；CuSO45H2O受热分解的化学方程式为：CuSO45H2O(s) eq o(=,sup5()CuSO4(s)+5H2O(l)， 热效应为H3。那么以下判断正确的选项是A、H2H3 B、H1H3C、H1+H3 =H2 D、H1+H2 H32022江苏10：C(s)O2(g)CO2(g) H1CO2(g)C(s)2CO(g) H22CO(g)O2(g)2CO2(g) H34F

7、e(s)3O3(g)2Fe2O3(s) H43 CO(g)Fe2O3(s)3CO2(g)2Fe(s) H5以下关于上述反响焓变的判断正确的选项是AH10，H30BH20，H40CH1H2H3DH3H4H52022海南4、标准状况下，气态分子断开1mol化学键的焓变称为键焓。HH，HO，和O=O键的键焓H分别为436KJ/mol，463KJ/mol，495KJ/mol，以下热化学方程式正确的选项是 A、H2O(g)=H2(g)+1/2O2(g) H =485KJ/molB、H2O(g)=H2(g)+1/2O2(g) H = + 485KJ/molC、2 H2(g) + O2(g)=2 H2O(g) H = + 485KJ/molD、2 H2(g) + O2(g)=2 H2O(g) H =485KJ/mol 【答案】D【解析】根据“HH，HO，和O=O键的键焓H分别为436KJ/mol，463KJ/mol，495KJ/mol，可以计算出2mol H2和1mol O2完全反响生