大学专业试卷 2001~2003三学年 浙江理工大学 计算机软件专业 C语言 程序设计基础试卷含答案

1、浙江大学“程序设计基础-C”试题卷2001-2002学年春季学期考试时间:2002年6月30日下午2:00-4:00注意：答题内容必须写在答题卷上，写在本试题卷上无效一单项选择题（每题2分，共20分）1.C语言程序的三种基本结构是顺序结构、选择结构和结构。2.A.递归B.转移下列运算符中，优先级最高的是。C.循环D.嵌套3.A.-B.+表达式!(x0&y0)等价于。C.&D.=A.!(x0)|!(y0)B.!x0|!y0C.!x0&!y0D.!(x0)&!(y0)4.表达式sizeof(nsum=%dn)的值是_。5.A.8B.9以下选项中不正确的实型常量是。C.10D.116.A.0.23E

2、B.2.3e-1表达式的值不是1。C.1E3.2D.2.3e0A.0?0:1B.5%4C.!EOFD.!NULL7.数组定义为inta1111,则数组a有_个数组元素。A.12B.144C.100D.1218.对于以下的变量定义，表达式是不正确的。structnodeintj,k;x,*p=&x;9.A.p-k=2B.（*p）.k=2不正确的赋值或赋初值的方式是。C.x.k=2D.x-k=2A.charstr=string;B.charstr10;str=string;C.char*p=string;D.char*p;p=string;10.设程序中不再定义新的变量，写出在函数main中可以使

3、用的所有变量#includeintz;intp(intx)staticinty;return(x+y);voidmain()inta,b;printf(%dn,p(a);Aa,bBa,b,zCa,b,y,zDa,b,x,y,z二、填空题（每题2分，共30分）设字符型变量ch的值是小写英文字母，将它转换为相应大写字母的表达式是TOC o 1-5 h z2.表达式101人5)的值是。下列程序段的输出结果是。inta=1;longb=a*0 x12345678;printf(%xn,b);设变量已正确定义，在程序段B中填入正确的内容，使程序段A和程序段B等价。程序段Afor(k=s=0;k=10;s

4、+=ak+)if(ak0)break;程序段Bfor(k=0,s=0;s+=ak+)if()break;下列程序段的输出结果是。#defineT10#defineMD3*Tprintf(%d,30/MD);下列程序段的输出结果是。intk,s;for(k=s=0;k10&s=10;s+=k)k+;printf(k=%d,s=%d,k,s);下列程序的输出结果是。#includeintf(intm)staticintk=2;k+;returnk+m;voidmain()ints;s=f(2);printf(%d,%dn,s,f(s);TOC o 1-5 h z对于以下递归函数f,调用f的返回值是

5、。f(intn)return(n=0)?n:f(n-1)+f(n-2);下列程序段的输出结果是。intc=10,0,-10;int*k=c+2;printf(%d,*k-);下列程序段的输出结果是。intk=1,j=2,*p=&k,*q=p;p=&j;printf(%d,%d,*p,*q);下列程序的输出结果是。#includechar*f(char*str)returnstr=fun;voidmain()char*str=one;printf(%s,%cn,f(str)+1,*f(str)+1);下列程序的输出结果是。#includevoidp(int*x,inty)+*x;y-;voidm

6、ain()intx=0,y=3;p(&x,y);printf(%d,%d,x,y);下列程序的输出结果是。#includestdio.hvoidmain()intj,k,a22;for(k=1;k3;k+)for(j=1;j3;j+)ak-1j-1=(k/j)*(j/k);for(k=0;k2;k+)for(j=0;j2;j+)printf(%d,akj);用typedef定义一个指向函数的指针类型FP,该函数的返回值为整型。三、程序阅读题(每题5分，共15分)1.输入c2470f?后,下列程序的输出结果是,该程序的主要功能是#includestdio.hintmain()charch;lon

7、gnumber=0;while(ch=getchar()6)while(ch!=?&ch=0&ch=6)number=number*7+ch-0;printf(%ld#,number);ch=getchar();2输入4后，下列程序的输出结果是。#includestdio.hintmain()intj,k,n;floatf,s;scanf(%d,&n);s=0;f=1;for(k=1;k=n;k+)for(j=1;jk;j+)f=f*k;s=s+f;printf(%.0f#,s);3输入55926369-1后，下列程序的输出结果是#include#includestructlinkintmar

8、k;structlink*next;voidf(structlink*);main()structlink*head,*p;head=(structlink*)malloc(sizeof(structlink);head-mark=0;head-next=NULL;f(&head);for(p=head;p!=NULL;p=p-next)printf(%d#,p-mark);voidf(structlink*head)intmark;structlink*p;scanf(%d,&mark);if(markmark+;return;elsep=(structlink*)malloc(sizeof

9、(structlink);p-mark=mark;p-next=*head;*head=p;f(head);四、程序填空题(每空2分，共20分)输入10个浮点数，调用函数f(x)计算并输出相应的函数值。f(x)的功能是计算分段函数：TOC o 1-5 h zx2+2x+1x0#includeif(xvO)(2);else;elsereturn3;voidmain()intk;floatx;for(k=1;k=10;k+)scanf(%f,&x);printf(y=%fn,f(x);函数sort使用冒泡法将一维整型数组中各元素按值从大到小排序。voidsort(inta,intn)intk,j,

10、t;for(k=1;kn;k+)for(;jn-k;j+)if()输入1个长整数，求各位数字的平方和。例如：输入-123，输出14。#includevoidmain()intdigit;longin,s;scanf(%ld,&in);TOC o 1-5 h z;；while(in0);s=s+digit*digit;printf(sum=%ldn,s);五、编程题(共15分)1函数ff(str,ch)的功能是统计并返回字符ch在字符串str中出现的次数。例如：调用ff(every,e)后返回2,因为在字符串every中字符e出现了2次。2.从键盘输入一个字符ch,输出该字符在文本文件input

11、.txt的每一行中出现的次数。(必须调用第1题定义的函数ff统计ch的出现次数)。例如：如果文件input.txt中存放了下列数据：every121amastudent.运行程序，并输入e后，输出201浙江大学“程序设计基础-C”参考答案2001-2002学年春季学期（2002年6月30日）一、单项选择题（每题2分，共20分）4B9B5AC10B1C2A6C7D3A8D二、填空题（每题2分，共30分）1ch-a+A或toupper(ch)213045678或123456785ak10(错1项扣1分)61007k=5,s=15(错1项扣1分)85,9错1个数字扣1分）9-210-10112,1（

12、错1个数字扣1分）12un,g(un1分,g1分)131,3（错1个数字扣1分）141,0,0,1分)（错1个数字扣115typedefint(*FP)();(扣1分)（错1项三、程序阅读题（每题5分，共15分）12#18#七进制转换十进制错1项扣2分31#3#21#1173#错1项扣2分370#63#92#55#0#错1项扣1分四、程序填空题（每空2分，共20分）(1)floatf(floatx)(2)returnx*x+2*x+1(3)if(x=0)return0(4)j=0(5)ajaj+1(6)t=aj+1;aj+1=aj;aj=t;(7)if(in0)in=-in(8)s=0（7）、

13、（8）可以互换(9)digit=in%10(10)in=in/10五、编程题(共15分)1、intff(char*str,charch)/*说明1分*/intcount=0;while(*str)/*循环3分条件、查找、str递增各1分*/if(*str=ch)count+;str+;returncount;/*返回1分*/2、#inelude/*头文件、变量说明、打开关闭文件、输入ch共2分*/#includevoidmain()charch,c,s80;intk;FILE*fp;if(fp=fopen(input.txt,r)=NULL)printf(errorn);exit(0);ch=

14、getchar();k=0;while(1)/*循环+beaak1分*/c=fgetc(fp);/*读入1分*/if(c=n|c=EOF)/*共6分*/sk=0;k=0;printf(%dn,ff(s,ch);if(c=EOF)break;elsesk+=c;fclose(fp);k=0;/*循环判断1分*/*读入1分*/*共5分*/while(!feof(fp)c=fgetc(fp);if(c!=n)sk+=c;elsesk=0;k=0;printf(%dn,f(s,ch);if(c!=n)/*处理最后1行1分*/sk=0;printf(%dn,ff(s,ch);CProgrammingTE

15、STPAPERTime:8:30-10:30am.June20,2003Importantnote:youranswersmustbewrittenontheanswersheetSection1:SingleChoice(1markforeachitem,total10marks)D=D1.0D!(x0)|!(y0)DNULLTheprecedenceofoperatoristhelowestone.TOC o 1-5 h zA0|y0)isequivalentto.A!(x0)&!(y0)B!x0&!y0C!x0|!y0Thevalueofexpressionisnt0。A1/2B!0C!

16、EOFIfxisafloatvariable,thevalueofexpression(x=10/4)is。A2.5B2.0C3D2Ifvariablesaredefinedandassignedcorrectly,theexpressioniswrong.A.a&bB.aAbC.&xD.a,bAccordingtothedeclaration:inta10,*p=a;theexpressioniswrong.A.a9B.p5C.*p+D.a+iswrong.A.charstr10;str=string;B.charstr=string;C.char*p=string;D.char*p;p=s

17、tring;Ifallvariableshavebeendefinedanddeclaredinthefollowingprogram,allthevariableswhichcanbeusedinfunctionfun()are.#includevoidfun(intx)staticinty;return;intz;voidmain()inta,b;fun(a);A.x,yB.x,y,zC.a,b,y,zD.a,b,x,y,zAccordingtothedeclaration:intp5,*a5;theexpressioniscorrect.A.p=aB.p0=aC.*(a+1)=pD.a0

18、=2Section2:Fillintheblanks(2markforeachitem,total30marks)Accordingtothedeclaration:inta234，thenumberofelementsofarrayaisWritingconditionalexpressiontocalculatethevalueofy.TOC o 1-5 h z1x0y=0 x=01-1x0Thevalueofexpression1105is.Thevalueofexpression(101)&4is.Thevalueofexpressionsizeof(“hello”)isTheoutp

19、k,s;for(k=1,s=0;k10;k+)if(k%2=0)continue;s+=k;printf(k=%ds=%d,k,s);Theoutputofthefollowingstatementsis.#defineMM(x,y)(x*y)printf(%d,MM(2+3,15);Tk=1,s=0;switch(k)case1:s+=10;case2:s+=20;break;default:s+=3;printf(k=%ds=%d,k,s);Theou

20、tputofthefollowingprogramis.#includeintf()staticintk;return+k;voidmain()intk;for(k=0;k3;k+)printf(%d#,f();Theoutputofthefollowingprogramis.f(intx)if(x=1)return1;elsereturnf(x-1)+f(x-2);voidmain()printf(%d,f(4);Tk=1,j=2,*p,*q,*t;p=&k;q=&j;t=p;p=q;q=t;printf(%d,%d

21、,*p,k);Tc=10,30,5;int*pc;for(pc=c;pcc+2;pc+)printf(%d#,*pc);Theoutputofthefollowingstatementsis.char*st=ONE,TWO,FOUR,K;printf(%s,%cn,*(st+2),*st+1);Theoutputofthefollowingprogramis.#includevoidp(int*x,inty)+*x;y=y+2;voidmain()intx=0,y=3;p(&y,y);printf(%d,%d,x,y)

22、;Writingthedeclarationwithtypedef,whichmakesCPasynonymforacharacterpointerarray,10elements.Section3:Readeachofthefollowingprogramsandanswerquestions(5marksforeachitem,totalmarks:30)Theoutputofthefollowingprogramis.#includevoidmain()intk,x,s,t;x=3;s=0;t=x;for(k=1;k=3;k+)t=t*10+x;s=s+t;printf(%d#,s);W

23、heninput:730303129760,theoutputis.#includevoidmain()intj,k,sub,x;inta5;for(j=1;j=2;j+)for(k=0;k5;k+)scanf(“%d”,&ak);scanf(“%d”,&x);sub=-1;for(k=0;k5;k+)if(ak=x)sub=k;printf(%d#,sub);Theoutputofthefollowingprogramis.#includevoidmain()longnumber,wt,x;x=number=10230;wt=1;while(x!=0)wt=wt*10;x=x/10;wt=w

24、t/10;while(number!=0)printf(%d#,number/wt);number=number%wt;wt=wt/10;Wheninput:398653712421234,theoutputis#includestdio.hvoidmain()intflag,i,j,k,col,n,ri,a66;for(ri=1;ri=2;ri+)scanf(%d,&n);for(i=0;in;i+)for(j=0;jn;j+)scanf(%d,&aij);flag=0;for(i=0;in;i+)col=0;for(j=0;jn;j+)if(aicolaij)col=j;for(k=0;k

25、n;k+)if(aicol=n)printf(a%d%d=%d#,i,col,aicol);flag=1;if(!flag)printf(NO#);Wheninput:howareyou?,theoutputis#includevoidmain()intword;charch;word=0;while(ch=getchar()!=?)if(ch=)word=0;elseif(word=0)word=1;if(ch=a)ch=ch-a+A;putchar(ch);Ifthefollowingdataarestoredintextfilea.txtone?two?1234?output?Andth

26、efollowingdataarestoredintextfileb.txtone?two?1204?input?Theoutputofthefollowingprogramis.#include#includevoidmain()intcount;charch1,ch2;FILE*f1,*f2;if(f1=fopen(a.txt,r)=NULL)printf(Cantopenfile:%sn,a.txt);exit(0);if(f2=fopen(b.txt,r)=NULL)printf(Cantopenfile:%sn,b.txt);exit(0);count=0;while(!feof(f

27、1)|!feof(f2)ch1=fgetc(f1);ch2=fgetc(f2);if(ch1!=ch2)printf(%c#%c#,ch1,ch2);printf(%d#,count);break;if(ch1=?)count+;fclose(f1);fclose(f2);Section4:Accordingtothespecification,completeeachprogram(2markforeachblank,total:30marks)1Ifinputisn(n0),calculatethevalueofs=1/1!+1/2!+1/3!+1/n!.#includevoidmain(

28、)intj,k,n;floatf,s;scanf(%d,&n);(1);for(k=1;k0),ifitsaprimenumber,printYES,otherwiseprintNO.(Primenumbers:anintegralnumbernotdivisiblewithoutaremainderbyanyintegralnumberotherthanitselfandone.Oneisntaprimenumber,buttwoisaprimenumber)。#include#includevoidmain()intn;intprime(intm);scanf(%d,&n);if(5)pr

29、intf(YESn);elseprintf(NOn);intprime(intm)inti,n;if(m=1)return0;n=sqrt(m);for(i=2;i=n;i+)if(6)return(7)(8)；3Thedefinitionoffunctionf2()isequivalenttothedefinitionoffunctionf1().intf1(chars)intk=0;while(sk!=0)k+;returnk;intf2(char*s)char*ss;；while(*s+!=(10);return(11);4Wheninputisthenamesandscoresof30

30、students,printthenameandscoreofthestudentwhohavethehighestscore.#includestructstudentcharname10;intscore;voidmain()intk;structstudents30,*ptr;structstudent*f(structstudent*stud,intn);for(k=0;kname,ptr-score);structstudent*f(structstudent*stud,intn)structstudent*pmax,*p;(13)；for(p=stud;pscorepmax-sco

31、re)(14)return(15):浙江大学“c程序设计及实验”参考答案2002-2003学年春季学期（2003年6月20日）一、单项选择题（每题1分，共10分）1D2D3A4B5B6C7D8A9A10C二、填空题（每题2分，共30分）1242x0?1:(x=0)?0:-13140566k=10s=25（错1项扣1分）7478k=1s=30(错1项扣1分1#2#3#（错1个数字扣159分）10112,1（错1个数字扣1分）1210#30#1分)（错1个数字扣FOUR,P（错1个项扣10,4（错1个数字扣13分）141分）typedefchar*CP10：错1项15扣1分）三、程序阅读题（每题5

32、分，共30分）133#366#3699#错1项扣2分33#-1#错1项扣2分31#0#2#3#错1项扣2分4a00=9#a12=7#a11=4错1项扣2分5HowAreYou错1项扣2分63#0#2#错1项扣2分四、程序填空题（每空2分，共30分）_s=0(2)_f=1(3)jv=k(4)_f=f*j(5)prime(n)(6)m%i=O(7)_0(8)return1(9)ss=s(10)卫s-ss-1(12)ptr=f(s,30)(13)pmax=stud(14)pmax=p(15)pmax提醒：考试失败你将仍有机会；警告：考试作弊你将失去学位。CProgrammingTESTPAPERTi

33、me:8:30-10:30am.Jan15,2004Importantnote:youranswersmustbewrittenontheanswersheetdeclaresthevariablewhichcanholdthelargestpositiveSection1:SingleChoice(2markforeachitem,total20marks)Thedeclarationnumber.Ddoubled;D/DnAinta;Bcharb;Cfloatc;Theoperatorcannotbeusedasaunary-operator.TOC o 1-5 h zA+B-C*iswr

34、ongifitisusedasacharacterconstant.A”1”B1C1Ifcisacharactervariable,itsvalueis1or0afterevaluatingtheexpression。c=getchar()!=EOFB.(c=getchar()!=EOFC.c=OD.c=cAcAccordingtothedeclaration:inta10,*p=&a1;thelastelementofthearrayaisA.a1OB.p8C.p9D.p1OTheprecedenceofoperatoristhehighestone.A.+=B.C.?:D.+Thefoll

35、owingcodefragmentprintsout.chars=student;printf(“%s%d”,s+3,sizeof(s);A.student7B.dent7C.dent8D.student8Accordingtothefollowingdeclaration,isvalid.structnodechars1O;intk;p5;A.p.k=2B.pO-k=2C.(p-s)O=aD.pO.s=“a”Accordingtothedeclaration:int(*p)1O,pisa.A.pointerB.arrayC.functionD.elementofaarrayAssumetha

36、ttheuserofaprogramisaskedtoenteradaynumber(1-7)intoanintegervariablecalledday.Inthefollowingwhileloops,canbeusedtovalidatethedayentered.while(day=1|day=1&day=7)printf(ERROR1-7only,enteragain:);scanf(”%d”,&day);while(day7)printf(ERROR1-7only,enteragain:);scanf(”%d”,&day);while(day=7)printf(ERROR1-7on

37、ly,enteragain:);scanf(”%d”,&day);Section2:Fillintheblanks(2markforeachitem,total30marks)Writeaconditionalexpressiontocalculatethemaximumofxandy.TOC o 1-5 h zThevalueofexpression7*7/9*4%3is.Thevalueofexpression10=10=10is.Thevalueofexpression255&128is.Ta=3,b;if(a5)b

38、=7;elseif(a2)b=6;elseb=5;printf(%d,b);Ta=13;intb=3;floatx;x=a/b;printf(%.1f,x);Tj=1,k=2;printf(%d,%d#,j+,+k);printf(%d,%d,-j,k-);Tx,y;x=y=3;switch(y)case1:x=0;break;case2:x=17;break;case4:x=9;

39、break;printf(“%d”,x);Tarray=2,8,6,11,13,2,8,2;intk;inttotal=0;for(k=0;k8;k+)if(arrayk%2)break;total+=arrayk;printf(“%d”,total);Theoutputofthefollowingstatementsis.#defineMM(x,y)(x)*(y)printf(%d,MM(4,2+3)-8);Theoutputoftheprogramgivenbelowis.#includeintmain(void)in

40、tk=1;inta_function(intj);k=a_function(k);printf(%d,k);inta_function(intj)if(j3)j+;j=a_function(j);printf(%d#,j);return(j);Ta=1;intb=2;int*x,*y;x=&a;y=&b;*x=*x+1;x=y;*x=*x+1;printf(%d,%d,a,b);Toexecutethecommand:progatmyhome,thevalueof*(+argv)1isTheprogramgivenbelo

41、wprintsout.voidmelon(intg,int*h);intmain(void)inta=1,b=2;melon(a,&b);printf(a=%d,b=%d,a,b);voidmelon(intb,int*c)b+;*c=*c+b;Writeawhileloopthatisequivalenttotheforloopgivenbelow.for(k=0;k10;k+)sum=sum+k;Section3:Readeachofthefollowingprogramsandanswerquestions(6marksforeachitem,totalmarks:30)Theoutpu

42、tofthefollowingprogramis.#includestdio.hvoidmain()intj,k;for(j=0;j3;j+)for(k=0;k3;k+)printf(%2d,(k+j+1)%3?(k+j+1)%3:3);printf(#);Theoutputofthefollowingprogramis.#includevoidmain()inti,k,m;inta8=60,75,63,92,87,64,79,21,s10;for(k=0;k10;k+)sk=0;for(i=0;i8;i+)k=ai/10;sk+;m=s0;k=1;while(km)m=sk;k+;print

43、f(%d,m);Theoutputofthefollowingprogramis.#include#includeintprime(intn)inti,m;if(n=1)return0;m=sqrt(n);for(i=2;im;voidmain()intnum,i;num=20;for(i=2;i=num;i+)while(prime(i)&(num%i=0)printf(%d,i);num/=i;Theoutputofthefollowingprogramis.#includevoidmain()intj,k;charc,s180=”a-b-e8-9”,s280;j=k=0;while(c=

44、s1j+)!=0)if(s1j=-&s1j+1=c)j+;while(cs1j)s2k+=c+;elses2k+=c;s2k=0;printf(“%s”,s2);Ifthefollowingdataarestoredintextfilea.txtOne23Two45Theoutputofthefollowingprogramis.#include#includevoidmain()charch;FILE*fp;if(fp=fopen(a.txt,r)=NULL)printf(Cantopenfile:%sn,a.txt);exit(0);while(!feof(fp)ch=fgetc(fp);

45、if(ch=0&ch=9)putchar(ch-0+A);fclose(fp);Section4:Accordingtothespecification,completeeachprogram(2markforeachblank,total:20marks)1Theprogramwrittenbelowprintsoutthenumbersbetween1and1000,whichequalthesumofthecubesofthedigits.Forexample,oneofthenumbersprintedoutcouldbe153,because153=1*1*1+5*5*5+3*3*3.#includevoidmain()intdigit,k,m,s;for(k=1;k=1000;k+)(1);m=k;while(m!=0)digit=m%10