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2026届浙江省九年级数学中考二模模拟试卷(含答案详解与评分标准)学校________班级________姓名________考号________考试时间120分钟满分120分考试节点中考二模适用对象2026届九年级注意事项:1.本试卷为浙江省九年级数学中考二模考前检测用卷,满分120分,考试时间120分钟。2.答题前,请将学校、班级、姓名、考号填写清楚;选择题答案填写在答题栏内。3.解答题应写出必要的文字说明、证明过程或演算步骤;作图题可先用铅笔作图,再用黑色字迹笔描清。4.全卷共三大题、22小题。选择题10小题,每小题3分,共30分;填空题6小题,每小题3分,共18分;解答题6小题,共72分。题型选择题填空题解答题总分题号1—1011—1617—22分值30分18分72分120分一、选择题(本大题共10小题,每小题3分,共30分。每小题只有一个正确选项)1.在实数-2,0,1/3,√5中,最小的数是()A.-2B.0C.1/3D.√52.2026年浙江省某市预计参加中考人数约为6.82×10⁴人,将这个数写成普通计数法为()A.6820B.68200C.682000D.0.6823.下列运算正确的是()A.a³+a²=a⁵B.(a²)³=a⁶C.a⁶÷a²=a³D.(-2a)²=-4a²4.若式子√(x-3)在实数范围内有意义,则x的取值范围是()A.x>3B.x≥3C.x<3D.x≤35.如图形语言描述:两条直线a∥b,直线c分别与它们相交,若一组同位角中较小的角为65°,则与它相邻的内角为()A.25°B.65°C.115°D.130°6.从写有数字1,2,3,4的四张完全相同卡片中任意抽取一张,放回后再抽取一张,则两次抽到的数字之和为偶数的概率是()A.1/4B.1/3C.1/2D.3/47.若关于x的一元二次方程x²-4x+m=0有两个不相等的实数根,则m的取值范围是()A.m<4B.m≤4C.m>4D.m≥48.某班一次数学二模专项练习的成绩分布如下表,则该组数据的众数是()成绩/分80859095人数51294A.80B.85C.90D.959.如图形语言描述:在⊙O中,弦AB的长为8,圆心O到弦AB的距离为3,则⊙O的半径为()A.3B.4C.5D.610.已知二次函数y=x²-2x-3的图象与x轴交于A,B两点,与y轴交于C点。若点P在抛物线上且△ABP的面积为6,则符合条件的点P的个数是()A.1B.2C.3D.4选择题答题栏:题号12345678910答案二、填空题(本大题共6小题,每小题3分,共18分)11.分解因式:x²-9=__________.12.若点P(2,m)在反比例函数y=6/x的图象上,则m=__________.13.一个多边形的内角和为1080°,则这个多边形的边数为__________.14.已知一组数据7,8,9,a,11的平均数为9,则a=__________.15.如图形语言描述:在Rt△ABC中,∠C=90°,AC=6,BC=8,点D是斜边AB的中点,则CD=__________.16.已知二次函数y=x²-4x+k的图象与x轴只有一个公共点,则k=__________.三、解答题(本大题共6小题,共72分。解答应写出文字说明、证明过程或演算步骤)17.(10分)为检验二模前基础运算掌握情况,完成下列各题:(1)计算:|-3|+(π-2026)⁰-√16+(-1)²;(2)解不等式组:{2x-1≥3,x+4<3x},并把解集在数轴上表示出来。________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________18.(10分)某校九年级开展“二模前函数与统计专项训练”。从九年级学生中随机抽取40名学生的训练成绩,整理成如下频数表:成绩x/分60≤x<7070≤x<8080≤x<9090≤x≤100合计频数41018840(1)求被抽取学生成绩不低于80分的频率;(2)若该校九年级共有600名学生,请估计成绩不低于90分的学生人数;(3)在成绩不低于90分的学生中随机选2名参加经验交流。若其中男生5名、女生3名,请用列表或画树状图的方法求恰好选到1名男生和1名女生的概率。________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________19.(12分)如图形语言描述:在△ABC中,AB=AC,点D是BC的中点。点E,F分别在AB,AC上,且AE=AF,连接ED,FD,EF。(1)求证:△ADE≌△ADF;(2)若AB=AC=10,BC=12,AE=6,求EF的长;(3)在第(2)问条件下,求四边形EBCF的面积。________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________20.(12分)某文具店在二模复习阶段销售一种错题本。已知每本进价为8元,按每本12元销售时,每天可售出120本。经市场调查,售价每提高1元,每天少售出10本。设每本售价为x元,每天销售利润为w元。(1)当x=14时,每天可售出多少本?每天利润是多少元?(2)求w与x之间的函数表达式,并写出自变量x的实际取值范围;(3)若该店希望每天利润达到560元,并且尽量让学生负担较低的售价,应将售价定为多少元?____________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________21.(14分)如图形语言描述:AB是⊙O的直径,点C在⊙O上,过点C作⊙O的切线l,过点A作AD⊥l,垂足为D,连接AC,BC,OC。(1)求证:∠ACD=∠ABC;(2)若AB=10,BC=6,求AC的长;(3)在第(2)问条件下,求AD的长。____________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________22.(14分)综合题。已知抛物线y=x²-2x-3与x轴交于A,B两点(点A在点B左侧),与y轴交于点C,顶点为D。直线BC与抛物线的对称轴交于点E。(1)求点A,B,C,D的坐标;(2)求直线BC的函数表达式,并求点E的坐标;(3)点P为线段BC上一动点,过点P作PQ∥y轴交抛物线于点Q。设点P的横坐标为t,求线段PQ的最大值;(4)在抛物线上是否存在点M,使△MBC的面积等于△DBC的面积?若存在,求点M的坐标;若不存在,请说明理由。________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________
参考答案与解析说明:本答案给出主要解法和评分标准。不同解法只要逻辑正确、结果准确,可参照相应步骤给分;选择题与填空题每题均按题目分值给分。一、选择题答案与关键理由(每小题3分,共30分)题号12345678910答案ABBBCCABCD1.答案:A。负数小于零和正数,且-2小于其余三个数。2.答案:B。6.82×10⁴=68200。3.答案:B。幂的乘方法则:(a²)³=a⁶。其余选项分别混淆合并同类项、同底数幂除法和积的乘方符号。4.答案:B。二次根式有意义需被开方数非负,即x-3≥0,所以x≥3。5.答案:C。平行线同位角相等,所给角为65°;与它相邻的内角互为邻补角,故为180°-65°=115°。6.答案:C。两次抽取共有4×4=16种等可能结果。和为偶数需同奇偶:奇奇2×2=4种,偶偶2×2=4种,共8种,概率8/16=1/2。7.答案:A。判别式Δ=(-4)²-4m=16-4m。两个不相等实根需Δ>0,得m<4。8.答案:B。众数是出现次数最多的数据。表中85分对应人数12人,最多。9.答案:C。圆心到弦的垂线平分弦,半弦为4,半径r=√(3²+4²)=5。10.答案:D。抛物线与x轴交点满足(x-3)(x+1)=0,故AB=4。面积S=1/2·AB·|y_P|=6,得|y_P|=3。当y=3时,x²-2x-6=0有两个实根;当y=-3时,x²-2x=0有两个实根,所以共有4个符合条件的点。二、填空题答案与解析(每小题3分,共18分)11.答案:(x+3)(x-3)。平方差公式:x²-9=x²-3²=(x+3)(x-3)。12.答案:3。将P(2,m)代入y=6/x,得m=6/2=3。13.答案:8。设边数为n,则(n-2)×180°=1080°,解得n=8。14.答案:10。平均数为9,则7+8+9+a+11=45,得a=10。15.答案:5。直角三角形斜边中线等于斜边的一半,AB=√(6²+8²)=10,故CD=5。16.答案:4。图象与x轴只有一个公共点,判别式Δ=(-4)²-4k=0,得k=4。三、解答题答案、解析与评分标准(共72分)17.(10分)(1)|-3|+(π-2026)⁰-√16+(-1)²=3+1-4+1=1。评分标准:正确写出|-3|=3、(π-2026)⁰=1、√16=4、(-1)²=1各1分,计算结果1分,共5分。(2)由2x-1≥3得x≥2;由x+4<3x得x>2。两个条件同时成立,解集为x>2。数轴上用空心圆表示2,向右画线。评分标准:每个不等式解法各2分,写出公共解集1分,数轴表示正确1分;本小问满分5分,若只写x≥2或x>2的一个条件,最多得2分。18.(10分)(1)不低于80分的人数为18+8=26人,频率为26/40=0.65。(2)不低于90分的频率为8/40=0.2,估计全校人数为600×0.2=120人。(3)把5名男生记为M₁,M₂,M₃,M₄,M₅,3名女生记为G₁,G₂,G₃。从8人中任取2人共有C₈²=28种等可能结果;恰好1名男生和1名女生共有5×3=15种结果,所以概率为15/28。评分标准:第(1)问人数与频率各1分,共2分;第(2)问频率1分、估计人数2分,共3分;第(3)问列举或组合总数2分、有利结果2分、概率1分,共5分。19.(12分)(1)因为AB=AC,D是BC的中点,所以AD是等腰三角形底边上的中线,也是顶角平分线,即∠EAD=∠DAF。又AE=AF,AD为公共边,所以△ADE≌△ADF。(2)由AB=AC且AE=AF,得AE/AB=AF/AC=6/10=3/5,所以EF∥BC,△AEF∽△ABC。于是EF/BC=AE/AB=3/5,故EF=12×3/5=36/5。(3)因为AB=AC=10,D为BC的中点,所以BD=6,且AD⊥BC。在Rt△ABD中,AD=√(10²-6²)=8。由相似可知点E,F到A的比例为3/5,故EF到BC的距离为AD×(1-3/5)=16/5。四边形EBCF为梯形,面积S=((BC+EF)/2)×16/5=(12+36/5)×8/5=768/25。评分标准:第(1)问写出等腰三角形三线合一2分,利用边角边证明全等2分,共4分;第
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