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初中数学七年级上册《立方根》教学设计(人教版·五四制)
一、课标要求与教学理念阐述
《义务教育数学课程标准(2022年版)》明确指出,在初中阶段,学生要“理解乘方的意义,了解平方根、算术平方根、立方根的概念,会用根号表示数的平方根、算术平方根、立方根”。本课“立方根”是在学生已经学习了平方根、算术平方根的概念和求法,掌握了乘方运算的基础上,对开方运算的进一步拓展和深化。本节课的教学设计秉持“以学生发展为本”的核心素养导向,强调数学知识的发生与发展过程。我们不仅关注学生对立方根概念、符号表示及基本运算的掌握,更注重引导他们通过类比平方根的研究路径,自主建构立方根的知识体系,体会类比、从特殊到一般、符号化等核心数学思想方法,发展数学抽象、逻辑推理和数学运算素养。同时,教学设计将融入跨学科视野,引导学生认识立方根在现实世界(如物理、工程、信息技术)中的应用价值,培养其模型观念和应用意识。
二、教材内容与结构分析
本节课内容隶属于“数与代数”领域,是实数单元的重要组成部分。在人教版五四制七年级上册的教材编排中,它紧接“平方根”之后,两者共同构成了完整的开方运算基础。教材通常通过具体情境(如正方体体积求棱长)引入立方根的概念,进而给出定义和符号表示,再通过例题和练习探究立方根的性质并进行简单运算。
从知识结构看,立方根是乘方运算(指数为3)的逆运算,这一本质与平方根一致,构成了完美的知识对称性。然而,立方根在性质上与平方根存在显著差异(如被开方数可为任意实数,立方根符号内的被开方数不具有非负性限制等),这种“同中存异”的特点正是教学的关键点和学生认知的难点。深入理解这种差异,对于学生构建清晰、稳固的实数运算知识网络至关重要。本节课的学习也为后续学习实数运算、解简单三次方程、以及高中乃至更深层次的函数与方程思想奠定不可或缺的基础。
三、学情诊断与教学准备
学情分析:
认知基础:七年级学生已经熟练掌握了有理数的乘方运算,特别是求一个数的立方;刚刚系统学习了平方根与算术平方根的概念、表示方法及基本性质,对开方运算有了初步的感性认识和理性思考框架。这为通过类比迁移学习立方根提供了坚实的“最近发展区”。
认知障碍:学生可能存在的困难主要体现在以下几个方面:一是容易混淆平方根与立方根的符号表示及性质,尤其是在处理负数时,受平方根中“负数没有平方根”的思维定势影响,难以理解“负数有立方根”;二是对开立方运算的熟练度不足,尤其对非完全立方数的立方根的估算与表示感到困难;三是在从具体情境中抽象出立方根概念,并运用其解决实际问题时,建模意识与能力有待加强。
心理与能力特征:该阶段学生抽象逻辑思维开始占主导,但仍需具体经验支持。他们好奇心强,乐于探究,具备一定的小组合作与交流能力。因此,教学设计应充分利用其认知基础,创设有效情境,激发探究欲望,引导他们在自主探究、合作辨析中突破认知障碍。
教学准备:
教师准备:精心设计的多媒体课件(包含情境动画、探究问题链、对比表格等);实物或模型(如多个体积已知的小正方体);课堂练习与分层检测题卡。
学生准备:复习平方根的相关知识;准备计算器(用于探究非完全立方数的立方根);预习导学案。
四、教学目标
基于以上分析,确立本课的教学目标如下:
1.知识与技能:
(1)理解立方根的概念,掌握开立方运算,能准确叙述一个数a
a
a的立方根的定义。
(2)会用根号a
3
\sqrt[3]{a}
3a<pathd="M95,702
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c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54
c44.2,-33.3,65.8,-50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10
s173,378,173,378c0.7,0,35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429
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M83480h400000v40h-400000z">
表示一个数a
a
a的立方根,了解根指数、被开方数的含义。
(3)掌握正数、零、负数的立方根的性质,能求出一个数的立方根(包括完全立方数及利用计算器求近似值)。
(4)能区分平方根与立方根的异同,并能运用立方根的概念解决简单的实际问题。
2.过程与方法:
(1)经历从具体实际问题抽象出立方根概念的过程,发展数学抽象能力。
(2)通过类比平方根的学习路径,自主探究立方根的定义、表示和性质,体会类比思想在数学学习中的重要作用。
(3)在探究立方根性质的活动中,学会从特殊到一般的归纳方法,并通过与平方根的对比辨析,强化对知识本质的理解。
(4)在解决实际问题的过程中,初步建立数学模型,发展应用意识。
3.情感、态度与价值观:
(1)通过探索立方根性质的规律性,感受数学的简洁美、对称美与统一美。
(2)在克服认知冲突(如负数立方根的存在性)的过程中,培养敢于质疑、严谨求实的科学态度。
(3)通过了解立方根在现实世界中的应用,体会数学的价值,增强学习数学的兴趣和信心。
五、教学重点与难点
教学重点:立方根的概念、表示方法及求法。
教学难点:理解立方根与平方根在性质上的区别,特别是负数立方根的存在性及其意义;灵活运用立方根解决实际问题。
六、教学过程设计
(一)创设情境,问题导学(预计用时:8分钟)
1.情境引入:
教师利用多媒体展示两个问题情境:
情境A(复习链接):一个正方形展厅,面积为64平方米,它的边长为多少米?学生容易答出:边长是8米(因为8
2
=
64
8^2=64
82=64)。教师强调:这里我们实际上是已知一个数的平方(乘方结果),求这个数(底数),即求64的平方根。
情境B(新知探源):现要设计一个正方体形状的蓄水池,其容积为27立方米,请问这个正方体蓄水池的棱长应为多少米?
引导学生分析:正方体体积=棱长
3
^3
3。设棱长为x
x
x米,则得到方程x
3
=
27
x^3=27
x3=27。提问:“这里的已知量和未知量是什么关系?与我们刚才复习的平方根问题有什么相似和不同?”
2.提出问题链,激发认知冲突:
问题1:满足x
3
=
27
x^3=27
x3=27的x
x
x是多少?你是如何得到的?(学生可能通过心算3
3
=
27
3^3=27
33=27得出x
=
3
x=3
x=3)。
问题2:如果蓄水池容积是8立方米呢?棱长是多少?(x
=
2
x=2
x=2)。
问题3:如果容积是-8立方米呢?棱长可能是多少?是否存在这样的x
x
x,使得x
3
=
−
8
x^3=-8
x3=−8?(此处制造认知冲突。部分学生受平方根影响可能认为负数没有立方根,但通过计算(
−
2
)
3
=
−
8
(-2)^3=-8
(−2)3=−8,可以发现x
=
−
2
x=-2
x=−2)。
问题4:如果体积是10立方米(一个非完全立方数)呢?棱长还能用一个精确的整数表示吗?它大约是多少?
教师总结:像x
3
=
27
x^3=27
x3=27,x
3
=
8
x^3=8
x3=8,x
3
=
−
8
x^3=-8
x3=−8,x
3
=
10
x^3=10
x3=10这类问题,都是“已知一个数的立方,求这个数”的运算。这种运算在数学上叫做什么呢?它与我们学过的平方根运算有何关联?今天我们就一起来探究这种新的运算。
设计意图:从熟悉的平方根情境过渡到新的立方根情境,建立知识间的联系。通过具体的、有梯度的实际问题,让学生感受学习立方根的必要性。特别设置“负数”情境,引发学生认知冲突,为后续探究立方根与平方根的性质差异埋下伏笔,激发探究欲望。
(二)类比探究,建构概念(预计用时:15分钟)
1.概念生成:
引导学生回顾平方根的定义:“一般地,如果一个数的平方等于a
a
a,那么这个数叫做a
a
a的平方根(或二次方根)。”
提问:“你能类比平方根的定义,给‘立方根’下一个定义吗?”给予学生独立思考和小声讨论的时间。
请学生尝试表述,教师引导完善并板书严谨定义:
立方根的定义:一般地,如果一个数的立方等于a
a
a,那么这个数叫做a
a
a的立方根(或三次方根)。这就是说,如果x
3
=
a
x^3=a
x3=a,那么x
x
x叫做a
a
a的立方根。
教师强调定义中的关键词:“立方”、“等于a
a
a”、“数x
x
x”。并举例:因为2
3
=
8
2^3=8
23=8,所以2
2
2是8
8
8的立方根;因为(
−
2
)
3
=
−
8
(-2)^3=-8
(−2)3=−8,所以−
2
-2
−2是−
8
-8
−8的立方根。
2.符号表示:
复习平方根的符号表示:a
a
a的平方根记作±
a
\pm\sqrt{a}
±a<pathd="M95,702
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c44.2,-33.3,65.8,-50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10
s173,378,173,378c0.7,0,35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429
c69,-144,104.5,-217.7,106.5,-221
l0-0
c5.3,-9.3,12,-14,20,-14
H400000v40H845.2724
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c-6,0,-10,-1,-12,-3s-194,-422,-194,-422s-65,47,-65,47z
M83480h400000v40h-400000z">
,算术平方根记作a
\sqrt{a}
a<pathd="M95,702
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c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54
c44.2,-33.3,65.8,-50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10
s173,378,173,378c0.7,0,35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429
c69,-144,104.5,-217.7,106.5,-221
l0-0
c5.3,-9.3,12,-14,20,-14
H400000v40H845.2724
s-225.272,467,-225.272,467s-235,486,-235,486c-2.7,4.7,-9,7,-19,7
c-6,0,-10,-1,-12,-3s-194,-422,-194,-422s-65,47,-65,47z
M83480h400000v40h-400000z">
,其中“
\sqrt{\}
<pathd="M95,702
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c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54
c44.2,-33.3,65.8,-50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10
s173,378,173,378c0.7,0,35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429
c69,-144,104.5,-217.7,106.5,-221
l0-0
c5.3,-9.3,12,-14,20,-14
H400000v40H845.2724
s-225.272,467,-225.272,467s-235,486,-235,486c-2.7,4.7,-9,7,-19,7
c-6,0,-10,-1,-12,-3s-194,-422,-194,-422s-65,47,-65,47z
M83480h400000v40h-400000z">
”称为根号,a
a
a是被开方数,根指数2
2
2通常省略。
提问:“立方根应该如何表示呢?根指数还能省略吗?”
讲解并板书:一个数a
a
a的立方根,用符号a
3
\sqrt[3]{a}
3a<pathd="M95,702
c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5,-10,-9.5,-14
c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54
c44.2,-33.3,65.8,-50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10
s173,378,173,378c0.7,0,35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429
c69,-144,104.5,-217.7,106.5,-221
l0-0
c5.3,-9.3,12,-14,20,-14
H400000v40H845.2724
s-225.272,467,-225.272,467s-235,486,-235,486c-2.7,4.7,-9,7,-19,7
c-6,0,-10,-1,-12,-3s-194,-422,-194,-422s-65,47,-65,47z
M83480h400000v40h-400000z">
表示,读作“三次根号a
a
a”,其中a
a
a是被开方数,3
3
3是根指数,且根指数3
3
3不能省略。
强调书写规范,并在黑板上规范书写8
3
\sqrt[3]{8}
38<pathd="M95,702
c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5,-10,-9.5,-14
c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54
c44.2,-33.3,65.8,-50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10
s173,378,173,378c0.7,0,35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429
c69,-144,104.5,-217.7,106.5,-221
l0-0
c5.3,-9.3,12,-14,20,-14
H400000v40H845.2724
s-225.272,467,-225.272,467s-235,486,-235,486c-2.7,4.7,-9,7,-19,7
c-6,0,-10,-1,-12,-3s-194,-422,-194,-422s-65,47,-65,47z
M83480h400000v40h-400000z">
,−
8
3
\sqrt[3]{-8}
3−8<pathd="M95,702
c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5,-10,-9.5,-14
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c44.2,-33.3,65.8,-50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10
s173,378,173,378c0.7,0,35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429
c69,-144,104.5,-217.7,106.5,-221
l0-0
c5.3,-9.3,12,-14,20,-14
H400000v40H845.2724
s-225.272,467,-225.272,467s-235,486,-235,486c-2.7,4.7,-9,7,-19,7
c-6,0,-10,-1,-12,-3s-194,-422,-194,-422s-65,47,-65,47z
M83480h400000v40h-400000z">
等。
根据定义,我们有:若x
3
=
a
x^3=a
x3=a,则x
=
a
3
x=\sqrt[3]{a}
x=3a<pathd="M95,702
c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5,-10,-9.5,-14
c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54
c44.2,-33.3,65.8,-50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10
s173,378,173,378c0.7,0,35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429
c69,-144,104.5,-217.7,106.5,-221
l0-0
c5.3,-9.3,12,-14,20,-14
H400000v40H845.2724
s-225.272,467,-225.272,467s-235,486,-235,486c-2.7,4.7,-9,7,-19,7
c-6,0,-10,-1,-12,-3s-194,-422,-194,-422s-65,47,-65,47z
M83480h400000v40h-400000z">
。例如,3
3
=
27
⇔
3
=
27
3
3^3=27\Leftrightarrow3=\sqrt[3]{27}
33=27⇔3=327<pathd="M95,702
c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5,-10,-9.5,-14
c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54
c44.2,-33.3,65.8,-50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10
s173,378,173,378c0.7,0,35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429
c69,-144,104.5,-217.7,106.5,-221
l0-0
c5.3,-9.3,12,-14,20,-14
H400000v40H845.2724
s-225.272,467,-225.272,467s-235,486,-235,486c-2.7,4.7,-9,7,-19,7
c-6,0,-10,-1,-12,-3s-194,-422,-194,-422s-65,47,-65,47z
M83480h400000v40h-400000z">
;(
−
2
)
3
=
−
8
⇔
−
2
=
−
8
3
(-2)^3=-8\Leftrightarrow-2=\sqrt[3]{-8}
(−2)3=−8⇔−2=3−8<pathd="M95,702
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c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54
c44.2,-33.3,65.8,-50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10
s173,378,173,378c0.7,0,35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429
c69,-144,104.5,-217.7,106.5,-221
l0-0
c5.3,-9.3,12,-14,20,-14
H400000v40H845.2724
s-225.272,467,-225.272,467s-235,486,-235,486c-2.7,4.7,-9,7,-19,7
c-6,0,-10,-1,-12,-3s-194,-422,-194,-422s-65,47,-65,47z
M83480h400000v40h-400000z">
。
介绍“开立方”:求一个数a
a
a的立方根的运算,叫做开立方。开立方与立方互为逆运算。
3.初步应用(概念辨析):
完成一组快速口答练习,巩固概念与符号:
(1)填空:因为4
3
=
64
4^3=64
43=64,所以64
3
=
‾
\sqrt[3]{64}=\underline{\hspace{2cm}}
364<pathd="M95,702
c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5,-10,-9.5,-14
c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54
c44.2,-33.3,65.8,-50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10
s173,378,173,378c0.7,0,35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429
c69,-144,104.5,-217.7,106.5,-221
l0-0
c5.3,-9.3,12,-14,20,-14
H400000v40H845.2724
s-225.272,467,-225.272,467s-235,486,-235,486c-2.7,4.7,-9,7,-19,7
c-6,0,-10,-1,-12,-3s-194,-422,-194,-422s-65,47,-65,47z
M83480h400000v40h-400000z">
=。
(2)填空:−
125
3
=
‾
\sqrt[3]{-125}=\underline{\hspace{2cm}}
3−125<pathd="M95,702
c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5,-10,-9.5,-14
c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54
c44.2,-33.3,65.8,-50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10
s173,378,173,378c0.7,0,35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429
c69,-144,104.5,-217.7,106.5,-221
l0-0
c5.3,-9.3,12,-14,20,-14
H400000v40H845.2724
s-225.272,467,-225.272,467s-235,486,-235,486c-2.7,4.7,-9,7,-19,7
c-6,0,-10,-1,-12,-3s-194,-422,-194,-422s-65,47,-65,47z
M83480h400000v40h-400000z">
=,因为(
‾
)
3
=
−
125
(\underline{\hspace{1cm}})^3=-125
()3=−125。
(3)判断:27
3
\sqrt[3]{27}
327<pathd="M95,702
c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5,-10,-9.5,-14
c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54
c44.2,-33.3,65.8,-50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10
s173,378,173,378c0.7,0,35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429
c69,-144,104.5,-217.7,106.5,-221
l0-0
c5.3,-9.3,12,-14,20,-14
H400000v40H845.2724
s-225.272,467,-225.272,467s-235,486,-235,486c-2.7,4.7,-9,7,-19,7
c-6,0,-10,-1,-12,-3s-194,-422,-194,-422s-65,47,-65,47z
M83480h400000v40h-400000z">
表示27的立方根。()
(4)判断:−
64
3
=
−
4
\sqrt[3]{-64}=-4
3−64<pathd="M95,702
c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5,-10,-9.5,-14
c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54
c44.2,-33.3,65.8,-50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10
s173,378,173,378c0.7,0,35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429
c69,-144,104.5,-217.7,106.5,-221
l0-0
c5.3,-9.3,12,-14,20,-14
H400000v40H845.2724
s-225.272,467,-225.272,467s-235,486,-235,486c-2.7,4.7,-9,7,-19,7
c-6,0,-10,-1,-12,-3s-194,-422,-194,-422s-65,47,-65,47z
M83480h400000v40h-400000z">
=−4。()
(5)求值:0
3
=
‾
\sqrt[3]{0}=\underline{\hspace{2cm}}
30<pathd="M95,702
c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5,-10,-9.5,-14
c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54
c44.2,-33.3,65.8,-50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10
s173,378,173,378c0.7,0,35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429
c69,-144,104.5,-217.7,106.5,-221
l0-0
c5.3,-9.3,12,-14,20,-14
H400000v40H845.2724
s-225.272,467,-225.272,467s-235,486,-235,486c-2.7,4.7,-9,7,-19,7
c-6,0,-10,-1,-12,-3s-194,-422,-194,-422s-65,47,-65,47z
M83480h400000v40h-400000z">
=;1
3
=
‾
\sqrt[3]{1}=\underline{\hspace{2cm}}
31<pathd="M95,702
c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5,-10,-9.5,-14
c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54
c44.2,-33.3,65.8,-50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10
s173,378,173,378c0.7,0,35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429
c69,-144,104.5,-217.7,106.5,-221
l0-0
c5.3,-9.3,12,-14,20,-14
H400000v40H845.2724
s-225.272,467,-225.272,467s-235,486,-235,486c-2.7,4.7,-9,7,-19,7
c-6,0,-10,-1,-12,-3s-194,-422,-194,-422s-65,47,-65,47z
M83480h400000v40h-400000z">
=;−
1
3
=
‾
\sqrt[3]{-1}=\underline{\hspace{2cm}}
3−1<pathd="M95,702
c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5,-10,-9.5,-14
c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54
c44.2,-33.3,65.8,-50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10
s173,378,173,378c0.7,0,35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429
c69,-144,104.5,-217.7,106.5,-221
l0-0
c5.3,-9.3,12,-14,20,-14
H400000v40H845.2724
s-225.272,467,-225.272,467s-235,486,-235,486c-2.7,4.7,-9,7,-19,7
c-6,0,-10,-1,-12,-3s-194,-422,-194,-422s-65,47,-65,47z
M83480h400000v40h-400000z">
=。
设计意图:充分利用学生已有的平方根认知结构,引导他们通过类比自主生成立方根的定义和符号表示,实现知识的正向迁移。强调根指数“3”不可省略,是规范数学表达的重要环节。通过即时辨析练习,强化学生对概念和符号对应关系的理解。
(三)合作探究,归纳性质(预计用时:12分钟)
1.探究活动:求下列各数的立方根,并观察、归纳规律。
教师呈现探究表格(或让学生分组计算并记录):
|被开方数a
a
a|计算过程|立方根a
3
\sqrt[3]{a}
3a<pathd="M95,702
c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5,-10,-9.5,-14
c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54
c44.2,-33.3,65.8,-50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10
s173,378,173,378c0.7,0,35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429
c69,-144,104.5,-217.7,106.5,-221
l0-0
c5.3,-9.3,12,-14,20,-14
H400000v40H845.2724
s-225.272,467,-225.272,467s-235,486,-235,486c-2.7,4.7,-9,7,-19,7
c-6,0,-10,-1,-12,-3s-194,-422,-194,-422s-65,47,-65,47z
M83480h400000v40h-400000z">
|观察(正/负/零)|
|:---|:---|:---|:---|
|8|2
3
=
8
2^3=8
23=8|2|正数|
|-8|(
−
2
)
3
=
−
8
(-2)^3=-8
(−2)3=−8|-2|负数|
|27||||
|-27||||
|1||||
|-1||||
|1
8
\frac{1}{8}
81|(
1
2
)
3
=
1
8
(\frac{1}{2})^3=\frac{1}{8}
(21)3=81|1
2
\frac{1}{2}
21|正数|
|-1
8
\frac{1}{8}
81||||
|0|0
3
=
0
0^3=0
03=0|0|零|
2.小组讨论与归纳:
学生以小组为单位,完成表格计算,并围绕以下问题展开讨论:
(1)一个正数(如8、27、1
8
\frac{1}{8}
81)的立方根是正数还是负数?
(2)一个负数(如-8、-27、-1
8
\frac{1}{8}
81)的立方根是正数还是负数?
(3)0的立方根是什么?
(4)对比平方根的性质,立方根的性质有什么显著不同?(提示:从被开方数的取值范围和立方根的个数考虑)
3.性质归纳与对比:
各小组汇报讨论结果,师生共同归纳立方根的性质,并板书:
立方根的性质:
性质1:正数的立方根是正数。
性质2:负数的立方根是负数。
性质3:0的立方根是0。
本质:任何数都有且只有一个立方根。
引导学生与平方根性质进行对比,并共同完成对比表格:
|运算|被开方数a
a
a的取值范围|根的个数|符号表示|主要性质|
|:---|:---|:---|:---|:---|
|平方根|a
≥
0
a\ge0
a≥0|两个(互为相反数)|±
a
\pm\sqrt{a}
±a<pathd="M95,702
c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5,-10,-9.5,-14
c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54
c44.2,-33.3,65.8,-50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10
s173,378,173,378c0.7,0,35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429
c69,-144,104.5,-217.7,106.5,-221
l0-0
c5.3,-9.3,12,-14,20,-14
H400000v40H845.2724
s-225.272,467,-225.272,467s-235,486,-235,486c-2.7,4.7,-9,7,-19,7
c-6,0,-10,-1,-12,-3s-194,-422,-194,-422s-65,47,-65,47z
M83480h400000v40h-400000z">
|负数没有平方根;0的平方根是0;正数有两个平方根。|
|立方根|a
a
a为任意实数|只有一个|a
3
\sqrt[3]{a}
3a<pathd="M95,702
c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5,-10,-9.5,-14
c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54
c44.2,-33.3,65.8,-50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10
s173,378,173,378c0.7,0,35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429
c69,-144,104.5,-217.7,106.5,-221
l0-0
c5.3,-9.3,12,-14,20,-14
H400000v40H845.2724
s-225.272,467,-225.272,467s-235,486,-235,486c-2.7,4.7,-9,7,-19,7
c-6,0,-10,-1,-12,-3s-194,-422,-194,-422s-65,47,-65,47z
M83480h400000v40h-400000z">
|任何数都有唯一立方根;符号与被开方数相同。|
特别强调:“互为相反数的两个数,它们的立方根也互为相反数。”即−
a
3
=
−
a
3
\sqrt[3]{-a}=-\sqrt[3]{a}
3−a<pathd="M95,702
c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5,-10,-9.5,-14
c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54
c44.2,-33.3,65.8,-50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10
s173,378,173,378c0.7,0,35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429
c69,-144,104.5,-217.7,106.5,-221
l0-0
c5.3,-9.3,12,-14,20,-14
H400000v40H845.2724
s-225.272,467,-225.272,467s-235,486,-235,486c-2.7,4.7,-9,7,-19,7
c-6,0,-10,-1,-12,-3s-194,-422,-194,-422s-65,47,-65,47z
M83480h400000v40h-400000z">
=−3a<pathd="M95,702
c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5,-10,-9.5,-14
c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54
c44.2,-33.3,65.8,-50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10
s173,378,173,378c0.7,0,35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429
c69,-144,104.5,-217.7,106.5,-221
l0-0
c5.3,-9.3,12,-14,20,-14
H400000v40H845.2724
s-225.272,467,-225.272,467s-235,486,-235,486c-2.7,4.7,-9,7,-19,7
c-6,0,-10,-1,-12,-3s-194,-422,-194,-422s-65,47,-65,47z
M83480h400000v40h-400000z">
。这是由立方运算的符号规律决定的,是一个非常有用的性质。
设计意图:通过小组合作探究具体数值的立方根,让学生亲身经历从大量具体实例中观察、归纳一般规律的过程,发展归纳概括能力。与平方根的性质进行系统性对比,是突破本节课难点的关键。清晰的对比表格能帮助学生厘清两者间的联系与本质区别,尤其是打破“负数没有方根”的思维定势,深刻理解“任何实数都有唯一立方根”这一核心性质。
(四)深化理解,应用拓展(预计用时:10分钟)
1.基础运算与应用:
例1:求下列各式的值。
(1)−
64
3
\sqrt[3]{-64}
3−64<pathd="M95,702
c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5,-10,-9.5,-14
c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54
c44.2,-33.3,65.8,-50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10
s173,378,173,378c0.7,0,35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429
c69,-144,104.5,-217.7,106.5,-221
l0-0
c5.3,-9.3,12,-14,20,-14
H400000v40H845.2724
s-225.272,467,-225.272,467s-235,486,-235,486c-2.7,4.7,-9,7,-19,7
c-6,0,-10,-1,-12,-3s-194,-422,-194,-422s-65,47,-65,47z
M83480h400000v40h-400000z">
(2)−
1
27
3
-\sqrt[3]{\frac{1}{27}}
−3271<pathd="M98390
l0-0
c4,-6.7,10,-10,18,-10H400000v40
H1013.1s-83.4,268,-264.1,840c-180.7,572,-277,876.3,-289,913c-4.7,4.7,-12.7,7,-24,7
s-12,0,-12,0c-1.3,-3.3,-3.7,-11.7,-7,-25c-35.3,-125.3,-106.7,-373.3,-214,-744
c-10,12,-21,25,-33,39s-32,39,-32,39c-6,-5.3,-15,-14,-27,-26s25,-30,25,-30
c26.7,-32.7,52,-63,76,-91s52,-60,52,-60s208,722,208,722
c56,-175.3,126.3,-397.3,211,-666c84.7,-268.7,153.8,-488.2,207.5,-658.5
c53.7,-170.3,84.5,-266.8,92.5,-289.5z
M100180h400000v40h-400000z">
(3)0.216
3
\sqrt[3]{0.216}
30.216<pathd="M95,702
c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5,-10,-9.5,-14
c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54
c44.2,-33.3,65.8,-50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10
s173,378,173,378c0.7,0,35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429
c69,-144,104.5,-217.7,106.5,-221
l0-0
c5.3,-9.3,12,-14,20,-14
H400000v40H845.2724
s-225.272,467,-225.272,467s-235,486,-235,486c-2.7,4.7,-9,7,-19,7
c-6,0,-10,-1,-12,-3s-194,-422,-194,-422s-65,47,-65,47z
M83480h400000v40h-400000z">
(4)−
64
125
3
\sqrt[3]{-\frac{64}{125}}
3−12564<pathd="M98390
l0-0
c4,-6.7,10,-10,18,-10H400000v40
H1013.1s-83.4,268,-264.1,840c-180.7,572,-277,876.3,-289,913c-4.7,4.7,-12.7,7,-24,7
s-12,0,-12,0c-1.3,-3.3,-3.7,-11.7,-7,-25c-35.3,-125.3,-106.7,-373.3,-214,-744
c-10,12,-21,25,-33,39s-32,39,-32,39c-6,-5.3,-15,-14,-27,-26s25,-30,25,-30
c26.7,-32.7,52,-63,76,-91s52,-60,52,-60s208,722,208,722
c56,-175.3,126.3,-397.3,211,-666c84.7,-268.7,153.8,-488.2,207.5,-658.5
c53.7,-170.3,84.5,-266.8,92.5,-289.5z
M100180h400000v40h-400000z">
教学处理:引导学生先判断符号,再求值。强调(2)中“-”号在根号外,表示求1
27
\frac{1}{27}
271的立方根的相反数。对于(3),可将小数化为分数216
1000
=
(
6
10
)
3
\frac{216}{1000}=(\frac{6}{10})^3
1000216=(106)3来求解。
例2:解方程:(1)x
3
=
512
x^3=512
x3=512;(2)(
x
−
1
)
3
=
−
0.125
(x-1)^3=-0.125
(x−1)3=−0.125。
教学处理:引导学生将求立方根与解简单方程结合。强调解形如x
3
=
a
x^3=a
x3=a的方程,直接开立方得x
=
a
3
x=\sqrt[3]{a}
x=3a<pathd="M95,702
c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5,-10,-9.5,-14
c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54
c44.2,-33.3,65.8,-50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10
s173,378,173,378c0.7,0,35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429
c69,-144,104.5,-217.7,106.5,-221
l0-0
c5.3,-9.3,12,-14,20,-14
H400000v40H845.2724
s-225.272,467,-225.272,467s-235,486,-235,486c-2.7,4.7,-9,7,-19,7
c-6,0,-10,-1,-12,-3s-194,-422,-194,-422s-65,47,-65,47z
M83480h400000v40h-400000z">
。对于(2),先化为(
x
−
1
)
3
=
(
−
1
2
)
3
(x-1)^3=(-\frac{1}{2})^3
(x−1)3=(−21)3,再利用立方根定义求解。
2.估算与计算器使用:
探究:10
3
\sqrt[3]{10}
310<pathd="M95,702
c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5,-10,-9.5,-14
c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54
c44.2,-33.3,65.8,-50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10
s173,378,173,378c0.7,0,35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429
c69,-144,104.5,-217.7,106.5,-221
l0-0
c5.3,-9.3,12,-14,20,-14
H400000v40H845.2724
s-225.272,467,-225.272,467s-235,486,-235,486c-2.7,4.7,-9,7,-19,7
c-6,0,-10,-1,-12,-3s-194,-422,-194,-422s-65,47,-65,47z
M83480h400000v40h-400000z">
是多少?它是一个整数吗?它在哪两个连续整数之间?
引导学生思考:因为2
3
=
8
2^3=8
23=8,3
3
=
27
3^3=27
33=27,而8
<
10
<
27
8<10<27
8<10<27,所以2
<
10
3
<
3
2<\sqrt[3]{10}<3
2<310<pathd="M95,702
c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5,-10,-9.5,-14
c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54
c44.2,-33.3,65.8,-50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10
s173,378,173,378c0.7,0,35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429
c69,-144,104.5,-217.7,106.5,-221
l0-0
c5.3,-9.3,12,-14,20,-14
H400000v40H845.2724
s-225.272,467,-225.272,467s-235,486,-235,486c-2.7,4.7,-9,7,-19,7
c-6,0,-10,-1,-12,-3s-194,-422,-194,-422s-65,47,-65,47z
M83480h400000v40h-400000z">
<3。
提问:如果需要更精确的值怎么办?介绍利用计算器求立方根的方法(不同计算器按键可能不同,常见为
3
\boxed{\sqrt[3]{}}
3<pathd="M95,702
c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5,-10,-9.5,-14
c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54
c44.2,-33.3,65.8,-50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10
s173,378,173,378c0.7,0,35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429
c69,-144,104.5,-217.7,106.5,-221
l0-0
c5.3,-9.3,12,-14,20,-14
H400000v40H845.2724
s-225.272,467,-225.272,467s-235,486,-235,486c-2.7,4.7,-9,7,-19,7
c-6,0,-10,-1,-12,-3s-194,-422,-194,-422s-65,47,-65,47z
M83480h400000v40h-400000z">
键或S
H
I
F
T
\boxed{SHIFT}
SHIFT+x
3
\boxed{x^3}
x3键)。让学生动手计算10
3
\sqrt[3]{10}
310<pathd="M95,702
c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5,-10,-9.5,-14
c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54
c44.2,-33.3,65.8,-50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10
s173,378,173,378c0.7,0,35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429
c69,-144,104.5,-217.7,106.5,-221
l0-0
c5.3,-9.3,12,-14,20,-14
H400000v40H845.2724
s-225.272,467,-225.272,467s-235,486,-235,486c-2.7,4.7,-9,7,-19,7
c-6,0,-10,-1,-12,-3s-194,-422,-194,-422s-65,47,-65,47z
M83480h400000v40h-400000z">
的近似值(保留四位小数)。
3.简单实际应用(跨学科联系):
问题:科学家发现一种新型材料的密度为5.2
g/cm
3
5.2\,\{g/cm}^3
5.2g/cm3。现有一块该材料的正方体样本,测得质量为168.48
168.48
168.48克。请估算这个正方体样本的棱长大约是多少厘米?(密度=质量/体积;正方体体积=棱长
3
^3
3)
引导学生分析:先求体积V
=
m
/
ρ
=
168.48
/
5.2
=
32.4
(
cm
3
)
V=m/\rho=168.48/5.2=32.4\,(\{cm}^3)
V=m/ρ=168.48/5.2=32.4(cm3)。设棱长为x
x
xcm,则x
3
=
32.4
x^3=32.4
x3=32.4,所以x
=
32.4
3
x=\sqrt[3]{32.4}
x=332.4<pathd="M95,702
c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5,-10,-9.5,-14
c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54
c44.2,-33.3,65.8,-50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10
s173,378,173,378c0.7,0,35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429
c69,-144,104.5,-217.7,106.5,-221
l0-0
c5.3,-9.3,12,-14,20,-14
H400000v40H845.2724
s-225.272,467,-225.272,467s-235,486,-235,486c-2.7,4.7,-9,7,-19,7
c-6,0,-10,-1,-12,-3s-194,-422,-194,-422s-65,47,-65,47z
M83480h400000v40h-400000z">
。估算:3
3
=
27
3^3=27
33=27,3.2
3
=
32.768
3.2^3=32.768
3.23=32.768,故棱长略小于3.2cm。可用计算器求得更精确值。
简要讨论:此问题涉及物理中的密度概念,体现了数学作为工具在科学研究中的应用。
设计意图:通过例题巩固立方根的基本求值、符号处理和简单方程求解。引入估算和计算器使用,满足对非完全立方数处理的需求,体现方法的完整性。设计简单的实际问题,建立数学模型,让学生体会立方根的应用价值,并自然融入跨学科视角。
(五)变式训练,巩固提升(预计用时:8分钟)
1.辨析题(强化概念与性质):
(1)下列说法正确的是()。
A.-1的立方根是-1
B.27
3
\sqrt[3]{27}
327<pathd="M95,702
c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5,-10,-9.5,-14
c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54
c44.2,-33.3,65.8,-50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10
s173,378,173,378c0.7,0,35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429
c69,-144,104.5,-217.7,106.5,-221
l0-0
c5.3,-9.3,12,-14,20,-14
H400000v40H845.2724
s-225.272,467,-225.272,467s-235,486,-235,486c-2.7,4.7,-9,7,-19,7
c-6,0,-10,-1,-12,-3s-194,-422,-194,-422s-65,47,-65,47z
M83480h400000v40h-400000z">
表示27的算术平方根
C.1
64
\frac{1}{64}
641的立方根是±
1
4
\pm\frac{1}{4}
±41
D.−
8
3
=
−
2
\sqrt[3]{-8}=-2
3−8<pathd="M95,702
c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5,-10,-9.5,-14
c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54
c44.2,-33.3,65.8,-50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10
s173,378,173,378c0.7,0,35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429
c69,-144,104.5,-217.7,106.5,-221
l0-0
c5.3,-9.3,12,-14,20,-14
H400000v40H845.2724
s-225.272,467,-225.272,467s-235,486,-235,486c-2.7,4.7,-9,7,-19,7
c-6,0,-10,-1,-12,-3s-194,-422,-194,-422s-65,47,-65,47z
M83480h400000v40h-400000z">
=−2,所以-8的立方根是-2
(2)若1
−
2
x
3
\sqrt[3]{1-2x}
31−2x<pathd="M95,702
c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5,-10,-9.5,-14
c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54
c44.2,-33.3,65.8,-50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10
s173,378,173,378c0.7,0,35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429
c69,-144,104.5,-217.7,106.5,-221
l0-0
c5.3,-9.3,12,-14,20,-14
H400000v40H845.2724
s-225.272,467,-225.272,467s-235,486,-235,486c-2.7,4.7,-9,7,-19,7
c-6,0,-10,-1,-12,-3s-194,-422,-194,-422s-65,47,-65,47z
M83480h400000v40h-400000z">
与3
y
−
2
3
\sqrt[3]{3y-2}
33y−2<pathd="M95,702
c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5,-10,-9.5,-14
c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54
c44.2,-33.3,65.8,-50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10
s173,378,173,378c0.7,0,35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429
c69,-144,104.5,-217.7,106.5,-221
l0-0
c5.3,-9.3,12,-14,20,-14
H400000v40H845.2724
s-225.272,467,-225.272,467s-235,486,-235,486c-2.7,4.7,-9,7,-19,7
c-6,0,-10,-1,-12,-3s-194,-422,-194,-422s-65,47,-65,47z
M83480h400000v40h-400000z">
互为相反数,求x
y
\frac{x}{y}
yx的值。(提示:利用A
3
=
−
B
3
⇒
A
=
−
B
\sqrt[3]{A}=-\sqrt[3]{B}\RightarrowA=-B
3A<pathd="M95,702
c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5,-10,-9.5,-14
c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54
c44.2,-33.3,65.8,-50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10
s173,378,173,378c0.7,0,35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429
c69,-144,104.5,-217.7,106.5,-221
l0-0
c5.3,-9.3,12,-14,20,-14
H400000v40H845.2724
s-225.272,467,-225.272,467s-235,486,-235,486c-2.7,4.7,-9,7,-19,7
c-6,0,-10,-1,-12,-3s-194,-422,-194,-422s-65,47,-65,47z
M83480h400000v40h-400000z">
=−3B<pathd="M95,702
c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5,-10,-9.5,-14
c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,6
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