02b First Law concepts.ppt_第1页
02b First Law concepts.ppt_第2页
02b First Law concepts.ppt_第3页
02b First Law concepts.ppt_第4页
02b First Law concepts.ppt_第5页
已阅读5页,还剩36页未读 继续免费阅读

下载本文档

版权说明:本文档由用户提供并上传,收益归属内容提供方,若内容存在侵权,请进行举报或认领

文档简介

1、Lectures: M14:30-16:10AM, H101,Course Information,Instructor: Jianping Liu,email: ,Office Hours: Fri 16:00-17:30 H219,Mobile:Bilingual Course by Jianping Liu,F10:00-11:40AM, 8110,Atkins & de Paula: Atkins Physical Chemistry 7e,2,The first law: the concepts,Bilingual Course by Jianping L

2、iu,2.4 Heat transactions, internal energy change and heat transfer,In general,dU = dq + dwexp+ dwe,dU = dqv,at constant volume (dwexp = 0) and no additional work (dwe = 0),U = qv,(a) Calorimetry,the study of heat transfer during physical and chemical processes, Adiabatic bomb calorimeter,The common

3、device for measuring U.,qV = CT,U = qv,( C is the calorimeter constant),(b) Heat capacity at constant volume CV,Since dU = dqv then,the internal energy varies with the temperature and the volume being held constant., internal energy change at constant volume,(b) Heat capacity at constant volume CV,

4、Why introduce?,2.5 Enthalpy H,In general, the system is free to change its volume, then,can q equal to another thermodynamic property of the system at constant pressure?,Question:,(a) The definition of enthalpy,(state function), enthalpy change,Infinitesimal,measurable,2.5 Enthalpy H,(at equilibrium

5、 and expansion work only),at constant pressure,Infinitesimal,measurable,for a reaction that produces or consumes gas,for a perfect gas,Since dH = dqp then, heat capacity at constant pressure Cp,Questions:, Cp CV?, Cp = f(T)?,The variation of capacity with temperature,Two empirical expressions, The m

6、olar constant-volume heat capacity,(d) relation between heat capacities,monatomic gas,diatomic gas, for a perfect gas,体积功,等容无其它功,等压无其它功,显热,求 W, q , U , H。,q=0 (adiabatic),附2.2 1 mol 理想气体简变 (迅速膨胀),q=0 (绝热),U = q + w = -1030J,求 W, q , U , H。,附2.2 1 mol 理想气体简变 (迅速膨胀),1.0 mol 乙醇在正常沸点下蒸发成乙醇气体,求 此过程 W, Q

7、, U , H。,附2.3 等温等压下相变,附2.3 等温等压下相变,解(1) :,Q1= -110.52 kJ.mol-1,U1=Q1+W1= -111.76 kJ mol-1,H1=Qp=Q1= -110.52 kJ.mol-1,解(2) :,Q2= U2 -W2,U2= U1= -111.76 kJ mol-1,H2= H1= -110.52 kJ.mol-1,=(-111.76)-(-61.39)=-56.37 kJ.mol-1,Summary,Total differential of Z,z depends only on the initial and final state,a

8、nd is independent of the path.,Numerical problems,P2.3 at page 69,P2.3,Numerical problems,P2.3 at page 69,P2.3,( isotherm ),Numerical problems,P2.3 at page 69,Numerical problems,P2.3 at page 69,Numerical problems,P2.3 at page 69,P2.3, Adiabatic,for perfect gas,2.6 Adiabatic changes,(1) The work of a

9、diabatic change,Decide the initial and final state,2.6 Adiabatic changes, the state function,The state function and the process function, isothermal process, adiabatic process, the adiabatic reversible expansion,perfect gas,adiabatic,reversible,2.6 Adiabatic changes,The adiabatic reversible expansion,Illustration 2.5,(2) Heat capacity ratio,2.6 Adiabatic changes, isothermal, adiabatic,Atkins & de Paula: Atkins Ph

温馨提示

  • 1. 本站所有资源如无特殊说明,都需要本地电脑安装OFFICE2007和PDF阅读器。图纸软件为CAD,CAXA,PROE,UG,SolidWorks等.压缩文件请下载最新的WinRAR软件解压。
  • 2. 本站的文档不包含任何第三方提供的附件图纸等,如果需要附件,请联系上传者。文件的所有权益归上传用户所有。
  • 3. 本站RAR压缩包中若带图纸,网页内容里面会有图纸预览,若没有图纸预览就没有图纸。
  • 4. 未经权益所有人同意不得将文件中的内容挪作商业或盈利用途。
  • 5. 人人文库网仅提供信息存储空间,仅对用户上传内容的表现方式做保护处理,对用户上传分享的文档内容本身不做任何修改或编辑,并不能对任何下载内容负责。
  • 6. 下载文件中如有侵权或不适当内容,请与我们联系,我们立即纠正。
  • 7. 本站不保证下载资源的准确性、安全性和完整性, 同时也不承担用户因使用这些下载资源对自己和他人造成任何形式的伤害或损失。

评论

0/150

提交评论