单片机原理习题5.doc

1-1 1-2 ALU1-3 PC1-4 F1-5 1-6 1-7 ?1-8 ?1-9 1-10 CPU168CPU MCS-512-1 MCS-512-2 80512-3 PC2-4 DPTP2-5 80512-6 PSW?2-7 MCS-51I/O 2-8 51ROMP2P0/2-9 ALE2-10 80512-11 I/O2-12 80512-13 80310000HFFFFH2-14 8052RAM25680HFFHSFR2-15 805290HRAM2-16 80512-17 51RAM00H7FHRAM00H7FH2-18 2-19 MSC-512-20 MCS-51I/O2-21 CPURAMCPU2-22 R0R7 MCS-513-1 MCS-513-2 MCS-51?3-3 MCS-51 3-4 70H=60H60H=20HP1B7HMOV R0,#70HMOV A,R0MOV R1,AMOV B,R1MOV P1,#0FFHMOV R0,P170HBR1R03-5 .CLR AMOV R2,AMOV R7,#4LOOP: CLR CMOV A,R0RLC AMOV R0,AMOV A,R1RLC AMOV R1,AMOV A,R2RLC AMOV R2,ADJNZ R7,LOOPSJMP $3-6 12MHZSTART: SETB P1.0NEXT: MOV 30H,#10LOOP2: MOV 31H,#0FAHLOOP1: NOPNOPDJNZ 31H,LOOP1DJNZ 30H,LOOP2CPL P1.0AJMP NEXTSJMP $3-7 MOV R7,#10MOV A,#30HMOV DPTR,#2000HLOOP: MOVX DPTR,AINC AINC DPLDJNZ R7,LOOPSJMP $3-8 SPMOV SP,#2FHMOV DPTR,#2000HMOV R7,#50HNEXT: MOVX A,DPTRPUSH AINC DPLDJNZ R7,NEXTSJMP $3-9 XCH A,30HMOV B,AANL A,#0FHMOV 33H,AMOV A,BSWAP AANL A,#15MOV 34H,ASJMP $3-10 MOVC A,A+DPTRA20HDPTR1000H1020H30H3-11 A=PSWYOVAC1(A)=6BH, ADD A,#81H2(A)=6BH, ADD A,#8CH3(A)=6BH,CY=0, ADDC A,#72H4(A)=6BH,CY=1, ADDC A,#79H5(A)=6BH,CY=1, SUBB A,#OF9H6(A)=6BH,CY=0, SUBB A,#OFCH7(A)=6BH,CY=1, SUBB A,#7AH8(A)=6BH,CY=0, SUBB A,#8CH3-14 (1)(2)31MOV A,R2ADD A,R0MOV 30H,AMOV A,R3ADDC A,R1MOV 31H,AMOV A#0ADDC A,#0MOV 32H,ASJMP $2CLR CMOV A,R4SUBB A,R2MOV R0,AMOV A,R5SUBB A,R3MOV R1,A3MOV A,R1MOV B,R0MUL ABMOV 30H,AMOV 31H,BMOV A,R2MOV B,R0MUL ABADD A,31HMOV 31H,AMOV A,BADDC A,#0MOV 32H,ASJMP $3-15 UVWXP1.0P1.3ORGENDBITMOV P1,#0FHMOV C,P1.0ANL C,P1.1CPL CMOV ACC.0,CMOV C,P1.2ORL C,/P1.3ORL C,ACC.0MOV F,CSJMP $ 4-1 20H83BCD30H31H4-2 30H2BCDBCD31H4-3 RAM30H37H838H4-4 RAMBLOCKLENMINI4-5 XVARFFUNCF1. X20F = 0 20=X=10- 1 X10 5-1 MCS-51P08P285-2 80315-3 8031P2I/O5-4 MCS-518031RAM256K5-5 MCS-51ALE P3.6P3.75-6 MCS-515-7 RAM5-8 861160000H3FFFH MCS-51/6-1 /6-2 / 6-3 / 6-4 /6-5 /6-6 12MHZP1.01msP1.12ms13016-