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Code:Name:37th IChO Theoretical Examination Answer SheetsProblem 1:Chemistry of Amides and Phenols1-11-21-31-41-51-61-71-8Total Points4444648 438ReceivedProblem 2:Organic Synthesis and Stereochemistry2-12-22-32-42-52-62-72-8Total Points4866686 448ReceivedProblem 3:Organic Photochemistry and Photophysics3-13-23-33-43-53-63-73-8Total Points8444444436ReceivedProblem 4:Gold Capital of Asia4A-14A-24A-34A-44A-54A-64B-14B-24B-34B-44B-5Total Points2442622 22 8 842ReceivedProblem 5:Lewis Structure5-15-25-35-45-5Total Points2446521ReceivedProblem 6:Alkalinity of Water and Solubility of CO26-16-26-36-46-56-66-76-8Total Points4466466440ReceivedProblem 7:Kinetic Behavior Behavior of Ozone 7-17-27-37-47-5 Total Points6664628 ReceivedProblem 8:Protein Folding8-18-28-38-48-58-68-7Total Points226442626 ReceivedProblem 1:Chemistry of Amides and Phenols1-11-21-31-41-51-61-71-8Total Points4444648438 Received1-1Express your answer from high to low melting point as follows: (Insert compound codes A, B, C) 1-2 Answer for multiple choice question:1-3 Draw the structural formula of tripeptide Gly-Gly-Gly1-4The number of all possible linear tripeptides is: 1-5The number of optically active linear tripeptides is: 1-6 Express your answer from high to low binding affinity as follows: (Insert compound codes D, E, and F) 1-7 Draw the structural formula of compound H:1-8 Answer for multiple choice question:Problem 2:Organic Synthesis and Stereochemistry2-12-22-32-42-52-62-72-8Total Points4866686448 Received2-1 Draw the structural formula of compound A.2-2 T or F (a) OsO4 is an oxidizing agent in the reaction of A to B. (b) MeOH is generated as a by-product in the reaction of B to C. (c) Protons act as the catalyst in the transformation of B to C. (d) C will still be formed albeit in lower yields in the absence of Me2C(OMe)22-3 D/E ratio before recrystallization: Show your work hereCode:Name:2-4T or F (a) The reaction was to oxidize compound F. (b) The oxygen atom inserted originated from MCPBA. (c) The R/S notation of C-1 remained unchanged before and after the reaction.2-5 Draw the configurational formula of compound H.2-5 Give your answers as followsC-1: ; C-2: ;C-3: ;C-4: .2-7 2-8 The number of diastereoisomers of pentasaccharide is:Problem 3:Organic Photochemistry and Photophysics3-13-23-33-43-53-63-73-8Total Points8444444436Received3-1 Draw the structural formula of C and D3-2 Answer for multiple choice question:3-3 Answer for multiple choice question:3-4 Answer for multiple choice question:3-5 Draw the structural formula of compound H3-6 (cis or trans)3-7 (Answer for multiple choice question )3-8 (Answer for multiple choice question )Problem 4:Gold Capital of Asia4A-14A-24A-34A-44A-54A-64B-14B-24B-34B-44B-5Total Points2442622228842Received4A-1 Draw a structure for Au(CN)2-4A-2 Weight for KCN: gShow your work here 4A-3 Code:Name:4A-4 oxidizing agent: reducing agent:4A-5 Formation constant K:Show your calculations here4A-6 Answer for multiple choice question:4B-1 Answer for multiple choice question:4B-2 Answer for multiple choice question:4B-3 Answer for multiple choice question:4B-4 Answer for multiple choice question: Show your work here4B-5 Answer for multiple choice question: Show your work hereProblem 5:Lewis Structure5-15-25-35-45-5Total Points2446521 Received5-15-25-35-4 Answer for multiple choice question 5-4a: Answer for multiple choice question 5-4b: Answer for multiple choice question 5-4c:5-5Problem 6:Alkalinity of Water and Solubility of CO26-16-26-36-46-56-66-76-8Total Points4466466440 Received6-1 H2CO3:HCO3-:CO32-= :1.00: (a) (b)Show your work here6-26-36-46-56-66-76-8Problem 7:Kinetic Behavior of Ozone7-17-27-37-47-5Total Points6664628 Received7-17-27-37-47-5Problem 8:Protein Folding8-18-28-38-48-58-68-7Total Points226442626Received8-18-28-38-4 Answer for multiple choice question:8-5 Answer for multiple choice question:8-6 8-7 Country:Name:Experiment 1The Synthesis of D,L-Phenylglycine and Its Optical ResolutionTotal Scores: 100 points1-11-21-31-41-5Total Points251525530100ReceivedStep 1. Preparation of (D,L)-phenylglycine1-1 Confirmed and signedby lab assistantWeight of benzoylformic acid used: g Weight of fritted glass funnel: g After complete dryness:Product weight + fritted glass funnel: gWeigh on a balance that reads to the nearest centigram (0.01g).Weight of D,L-phenylglycine obtained: gChemical yield: %Calculate the chemical yield (% yield; show the calculations).Recommended scoring standard: g/ g/ g/Country:Name:We will double check the calculations, 5 points will be taken off for the wrong calculations. Points will be given based on the correct chemical yield.1-2Turn in the sample (in the vial with blue label).Signature of student: Signature of the lab assistant:The organization committee will weigh an appropriate amount of sample (0.01g) for 1H NMR spectroscopic analysis.Recommended scoring standard:Impurity may come from the ammonium formate and unknown side products. From our pilot studies, most students will be able to get 15 points.Step 2. Optical resolution of D,L-phenylglycine by (+)-camphorsulfonic acid (+)-CSA1-3 Confirmed and signedby lab assistant g/Weight of D,L-phenylglycine used: g g/Weight of fritted glass funnel: gCountry:Name: g/After complete dryness:Product weight + fritted glass funnel: g Weigh on a balance that reads to the nearest centigram (0.01g).Weight of the resolved phenylglycine (+)-CSA salt: gChemical yield: %Calculate the chemical yield (% yield; show the calculations).Recommended scoring standard:We will double check the calculations, 5 points will be taken off for the wrong calculations. Points will be given based on the correct chemical yield.1-4Draw the correct configuration formula (stereo chemical structure) of the isolated phenylglycine.If only correct chemical structure is given (no stereo chemistry), 1 point is given.Country:Name:1-5Specific rotation of the enantiomeric phenylglycine (+) CSA salt (to be determined by the organization committee)Turn in the sample (in the vial with pink label).Signature of student: Signature of the lab assistant:The organization committee will weigh an appropriate amount of sample (0.055 0.065g) for measurement of optical purity.Recommended scoring standard:The organization committee will weigh the resolved product (from the fritted glass funnel) for students who fail to finish the procedure in time. However, 15 penalty points will be taken.Country:Name:Experiment 2Identification of Unknown Inorganic SamplesTotal Scores: 100 points2-12-2Total Points964100Received2-1 Unknown Code Unknown Code Unknown Code Compound Number* Compound Number* Compound Number* HCl , H2SO4 , NH4SCN , NaOH , BaCl2 , K4SCN , Na2CO3 , ZnCl2 , Na2CO3 , H2O2 , *Second column is for duplicates.2-2A. Write the electrolysis equation that would help you confirm that an unknown sample is ZnCl2.Zn2+(aq) + 2Cl(aq) Cl2(aq) (anode) + Zn(s) (deposit on cathode) B. Write one equation that shows how to clean the deposit of Zn on the electrode (limited to the items provided in this task).Zn(s) + 2H+(aq) H2(g) + Zn2+(aq) or Zn(s) + 2OH(aq) H2(g) + ZnO22(aq) Country:Language:37th IChO Theoretical Examination- use only the pen provided- time5 hours- problem booklet26 pages (including this cover sheet)- answer sheets:28 pages (including cover sheet, and fives pages at the end with only a box. Use if necessary. Write down the problem number inside the box- draft paper (will not be marked):5 sheets (more are available on request)- total number of points:279 (They are equally weighted in the final score)- your name and student codewrite on every answer sheet- atomic massesuse only the periodic system given- constantsuse only the values given in the table - answersonly in the appropriate boxes of the answer sheets. Nothing else will be marked- questions ask for show worksno point will be given to no showing work- restroom breakask your supervisor- official English-language versionavailable on request, for clarification only,youre your supervisor.- after the stop signalput your answer sheets in the correct order (if they arent), put them in the envelope (dont seal), deliver them at the exit- examination bookletkeep it, together with the pen and calculator.Country:Language:Fundamental Constants, Equations and Conversion FactorsAtomic mass unit1 amu=1.660510-27kgAvogadros numberN=6.021023mol-1Boltzmanns constantk=1.380650310-23JK-1Electron chargee=1.602210-19cFaradays constantF=9.6485104C mol-1Gas constantR=8.314JK-1mol-1=0.08205LatmK-1mol-1Mass of electronme=9.1110-31kgMass of neutronmn=1.6749271610-27kgMass of protonmp=1.6726215810-27kgPlancks constanth=6.6310-34JsSpeed of lightc=3108ms-1Nernst equation (T=298K)E=E0-(0.0592/n)logKArrhenius equationk=Ae-Ea/RTClausius-Clapeyron equationln P=-Hvap/RT+bDe Broglie relation=h/mvLdeal gas equationPV=nRTFree energyG=H-TSE=hvG=G0+RT lnQU=q+wV(cylinder)=r2hV(sphere)=4/3r3A(sphere)=4r21=10-10m1W=1Js-11J=1kgm2s-21cal=4.184 J1Pa=1kgm-1s-2=1Nm-21bar=105Pa1atm=1.01325105Pa=760mmHg(torr)1eV/molecule=96.4853kJ mol-1Standard atmosphere =101325 PaRT at 298.15K =2.4790kJ mol-1Pi() =3.1415927Country:Language:Problem 1: Chemistry of Amides and PhenolsTotal Scores: 38 points1-11-21-31-41-51-61-71-8Points44446484Condensation of a carboxylic acid with an amine gives an amide product. For example, condensation of formic acid with dimethylamine forms N,N-dimethylformamide (DMF), which can bedescribed as the following resonance structures.1-1 Predict the order of melting points among N,N-dimethylformamide (compound A), N-methylacetamide (CH3CONHCH3, compound B), and propionamide (CH3CH2CONH2, compound C). Express your answer from high to low melting point as follows: (Insert compound codes A, B, C)1-2 Carbonyl groups are usually identified by their characteristic strong absorptions in the infrared spectra. The position of the absorption is dependent on the strength of the C=O bond, which in turn is reflected in their bond lengths. In amides, the strength of the carbonyl groups can be shown by the resonance structure noted above. For example, cyclohexanone shows an absorption at 1715 cm-1 for the carbonyl group(C=O). In comparison with cyclohexanone, predict the absorption band for the carbonyl group in propionamide. Select your answer from the following choices.(a) 1660 cm-1 because of the shorter carbonyl bond length(b) 1660 cm-1 because of the longer carbonyl bond length(c) 1740 cm-1 because of the shorter carbonyl bond length(d) 1740 cm-1 because of the longer carbonyl bond lengthCountry:Language:1-3 Glycine (H2N-CH2-COOH) is an -amino acid. Three glycine molecules can form a tripeptide Gly-Gly-Gly via amide linkages, accompanied by elimination of two water molecules. Draw the structural formula of this tripeptide.1-4 When an -amino acid contains a substituent, there is a possibility of optical isomers. For example, L-alanine and D-alanine are two enantiomers. What is the number of all possible linear tripeptides that can be formed from the following three amino acids:glycine, L-alanine and D-alanine as the starting materials in the condensation reaction? Glycine(Gly) L-Alanine (L-Ala) D-Alanine (D-Ala)1-5 Among the tripeptides synthesized in 1-4, how many are optically active?Nowadays, polyacrylamide gel associated with electrophoresis (PAGE) was widely used in analyses of proteins and nucleic acids. However, one of the first applications of polyamide gel is the separation of phenol compounds on thin-layer chromatography. The phenol compounds bearing different substituents have varied acidities. The higher acidity results in stronger binding to PAGE gel.1-6 Predict the binding affinity of phenol (compound D), 4-methylphenol (compound E)and 4-nitrophenol (compound F) with a polyamide gel. Express your answer from high to low binding affinity as follows: (Insert compound codes D, E, and F)The absorption maximum of a molecule in its ultraviolet and visible spectrum (UV-vis spectrum) is related to the number of conjugated double bonds in a chain. A compound containing more than 5 conjugated double bonds tends to absorb visible light, and hence shows the complementary color.For example, phenolphthalein is a commonly used acid-base indicator, which is colorless in acidicand neutral solutions, but reddish pink in basic solutions (pH 8.3-10.0).Phenol PhenolphthaleinFor translation: concentrated1-7 Draw the structural formula of H derived from phenolphthalein that is attributable tothe reddish pink color in aqueous NaOH solution.1-8 A simple way to prepare phenolphthalein is via condensation of compound G with 2 equivalents of phenol. What is the most effective reagent for G to accomplish this transformation? Select your answer from the following compounds.Country:Language:Problem 2: Organic Synthesis and StereochemistryTotal Scores: 48 points2-12-22-32-42-52-62-72-8Points48666864Natural carbohydrates are generally produced by photosynthesis in plants. However, unnatural carbohydrates can be prepared by organic synthesis. The following outline is a synthetic scheme for the unnatural L-ribose (compound I).For translation sealed tube = pig liver esterase =(minor) = (major) =2-1 Compound A has the molecular formula of C10H10O5. Draw the structural formula of A.2-2 Given the chemistry described for reaction sequence A to C, indicate whether the following statements are true or false (Use T to represent true and F to represent false).Country:Language: (a) OsO4 is an oxidizing agent in the reaction of A to B. (b) MeOH is generated as a by-product in the reaction of B to C. (c) Protons act as the catalyst in the transformation of B to C. (d) C will still be formed albeit in lower yields in the absence of Me2C(OMe)2.Pig liver esterase is an enzyme that can hydrolyze esters to carboxylic acids. Hydrolysis of C by the pig liver esterase afforded an enantiomeric mixture of D and E, in which E was the major component. The optical rotation of the mixture was D20 = -37.1.Further purification by recrystallization gave pure E with the optical rotation D20 = -49.0.2-3 What is the molar ratio of D/E in the product mixture before the recrystallization? Show your work.2-4 Reaction of F with meta-chloroperbenzoic acid (MCPBA) afforded G as the product. Indicate whether the following statements are true or false (Use T to

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